







Study with the several resources on Docsity
Earn points by helping other students or get them with a premium plan
Prepare for your exams
Study with the several resources on Docsity
Earn points to download
Earn points by helping other students or get them with a premium plan
The final examination for mathematics 265 at the university of british columbia, held on december 17, 2010. The examination covers various topics in mathematics, including differential equations, laplace transforms, and systems of linear equations. It consists of multiple choice questions, problem-solving questions, and instructions for exam rules and regulations.
Typology: Exams
1 / 13
This page cannot be seen from the preview
Don't miss anything!








The University of British Columbia Final Examination -December 17, 2010 Mathematics 265 Instructor: Dr. Keshet
Closed book examination Time: 2.5 hours
LAST Name: FIRST Name:
Student #: Signature Section: 101 / 103 / (Circle one)
Special Instructions: - Be sure that this examination has 13 pages. Write your full name (as on your Student ID) on top of each page. Circle your section number (MW 8:00AM is the 101 section. MW 9:00AM is the 103 section).
Rules governing examinations
Total 100
Page 1 out of 13
1 : Consider the (discontinuous) function described by
f (t) =
0 t < 1 −(2t + 1) 1 ≤ t ≤ 2 t^2 2 < t ≤ 4 0 4 < t
This function can be written in terms of step functions as follows: (a) f (t) = −(u 1 (t) + u 2 (t))(2t + 1) + (u 2 (t) + u 4 (t))t^2 (b) f (t) = −(2t + 1)u 1 (t) + (t + 1)^2 u 2 (t) − t^2 u 4 (t) (c) f (t) = −(2t + 1)u 1 (t) + t^2 u 2 (t) (d) f (t) = (2t + 1)u 2 (t) + t^2 u 4 (t) (e) f (t) = −(2t + 1)u 2 (t) − t^2 u 4 (t)
2 : Suppose that two solutions of a differential equation y′′^ + p(t)y′^ + q(t)y = 0 are y 1 (t) = t^2 − 2 t + 1 and y 2 = t − 1. Then the Wronskian of these solutions, W is
(a) W = −(t − 1)^2 (b) W = 3t^2 − 6 t + 3 (c) W = (t − 1)(2t − 3) (d) W = −t^2 + 6t − 1 (e) W = (t − 1)^3
3 : To solve the ODE y′′^ − y′^ − 2 y = t + te−t, the form of the particular solution that is needed is
(a) yp(t) = At + Bte−t (b) yp(t) = At + B + Cte−t (c) yp(t) = At + B + (Ct + D)e−t (d) yp(t) = At + B + t(Ct + D)e−t (e) yp(t) = At^2 + t^2 (Ct + D)e−t
x(t) y(t)
, and consider the following systems of equations.
(a) Match each system with a corresponding phase plane diagram (circle 1 correct response: a,b,c,d, or None).
(b) For those cases that matched, draw a few arrows directly on the diagrams to indicate the direction of increasing time along the solution curves in the xy plane. (Hint: you do not need to solve the ODEs fully to figure out those directions.)
-0.
-0.
-0.
-0.
0
1
-1 -0.8 -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0.8 1 (a)
-0.
-0.
-0.
-0.
0
1
-1 -0.8 -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0.8 1 (b)
-0.
-0.
-0.
-0.
0
1
-1 -0.8 -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0.8 1 (c)
-0.
-0.
-0.
-0.
0
1
-1 -0.8 -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0.8 1 (d)
Figure 1: Phase plane plots for Problem 2. (x is the horizontal axis, y the vertical axis in each case)
dy dx
Extra space (if needed)
(a) Solve the initial value problem y′′^ − 3 y′^ + 2y = δ(t − 1), y(0) = 1, y′(0) = 1. (b) What is the value of y at time t = 2?
Solve the system of first order ODEs given below:
dx dt
x, with x(0) =
Problem 7: For a holiday dinner, a large roast is to be cooked. At time t = 0, the roast is taken out of the refrigerator, and its initial temperature is T (0) = 0◦^ Celsius. It is left at room temperature (Eroom = 20◦ Celsius) for 1 hour. Then it is put into an oven (Eoven = 220◦^ Celsius) for 1 hour. After this time, it is left at room temperature until dinner. Assume that Newton’s Law of Cooling is a good approximation so that the temperature of the roast T (t) at time t > 0 satisfies
dT dt
= k(E(t) − T ), where the ambient temperature is E(t) =
Eroom 0 ≤ t ≤ 1 Eoven 1 < t ≤ 2 Eroom 2 < t
For simplicity, assume that k = 1. Find the temperature of the roast, T (t) for t > 0.
You may tear out this page for convenience. You do not need to submit it with the exam.
s
s−a
n n! sn+
a s^2 +a^2
e−cs s
ct