Wronskian - Math - Assignment, Exercises of Mathematics

These are the important key points of assignment of Math are: Wronskian, Functions, Variation of Parameters, General Solution, Linearly Independent Solutions, Particular Solution, Characteristic Equation, Variation of Parameters, Nonhomogeneous, Differential Equation

Typology: Exercises

2012/2013

Uploaded on 01/10/2013

ekbal
ekbal 🇮🇳

3.3

(4)

46 documents

1 / 1

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
Math 334
Assignment 4
Due: 12 Noon on Thursday, October 12, 2006.
1. The Wronskian of three functions is defined in terms of a determinant as follows:
W[φ1, φ2, φ3](x) :=
φ1(x)φ2(x)φ3(x)
φ
1(x)φ
2(x)φ
3(x)
φ′′
1(x)φ′′
2(x)φ′′
3(x)
.
(a) Find the Wronskian of the functions
φ1(x) = 1, φ2(x) = x, φ3(x) = x2.
(b) Find the Wronskian of the functions
φ1(x) = ex, φ2(x) = ex, φ3(x) = cosh x.
2. Use variation of parameters to find the general solution of
(a) y′′ + 16y= sec 4x;
(b) x2y′′ +xy+ 9y=tan(3 ln x).
3. Use variation of parameters to show that
y(x) = c1cos x+c2sin x+Zx
0
f(s) sin(xs)ds
is the general solution to the differential equation
y′′ +y=f(x).
4. Determine the motion for an undamped system at resonance governed by
d2x
dt2+ 9x= 2 cos 3t, x(0) = 1,dx
dt (0) = 0,
5. Consider the following homogeneous boundary value problem on the interval (0,1) with homogeneous
boundary conditions:
y′′ +ω2y= 0, y(0) = 0, y(1) = 0.
The difference between initial value problems (IVPs) and boundary value problems (BVPs) is that the
auxiliary conditions for IVPs are applied at one point only, whereas the auxiliary conditions for BVPs
are applied at more than one point. While we have a theorem that guarantees that there is one and
only one solution for an IVP, the situation for BVPs is quite different. The trivial solution y0 is
always a solution to a homogeneous BVP, but there may be other solutions. In fact, there may be
infinitely many solutions.
Determine all the values of ωfor which the above BVP has at least one nontrivial solution.
6. Suppose φ1(x) and φ2(x) are linearly independent solutions of y′′ +P(x)y+Q(x)y= 0. Suppose fur-
ther that φ1(x) has at least two zeros. Show that φ2(x) has one and only one zero between consecutive
zeros of φ1(x).

Partial preview of the text

Download Wronskian - Math - Assignment and more Exercises Mathematics in PDF only on Docsity!

Math 334

Assignment 4

Due: 12 Noon on Thursday, October 12, 2006.

  1. The Wronskian of three functions is defined in terms of a determinant as follows:

W φ 1 , φ 2 , φ 3 :=

φ 1 (x) φ 2 (x) φ 3 (x)

φ

′ 1 (x) φ

′ 2 (x) φ

′ 3 (x)

φ ′′ 1 (x) φ ′′ 2 (x) φ ′′ 3 (x)

(a) Find the Wronskian of the functions

φ 1 (x) = 1, φ 2 (x) = x, φ 3 (x) = x

2 .

(b) Find the Wronskian of the functions

φ 1 (x) = e

x , φ 2 (x) = e

−x , φ 3 (x) = cosh x.

  1. Use variation of parameters to find the general solution of

(a) y

′′

  • 16y = sec 4x;

(b) x 2 y ′′

  • xy ′
  • 9y = − tan(3 ln x).
  1. Use variation of parameters to show that

y(x) = c 1 cos x + c 2 sin x +

x

0

f (s) sin(x − s) ds

is the general solution to the differential equation

y

′′

  • y = f (x).
  1. Determine the motion for an undamped system at resonance governed by

d 2 x

dt 2

  • 9x = 2 cos 3t, x(0) = 1,

dx

dt

  1. Consider the following homogeneous boundary value problem on the interval (0, 1) with homogeneous

boundary conditions:

y

′′

  • ω

2 y = 0, y(0) = 0, y(1) = 0.

The difference between initial value problems (IVPs) and boundary value problems (BVPs) is that the

auxiliary conditions for IVPs are applied at one point only, whereas the auxiliary conditions for BVPs

are applied at more than one point. While we have a theorem that guarantees that there is one and

only one solution for an IVP, the situation for BVPs is quite different. The trivial solution y ≡ 0 is

always a solution to a homogeneous BVP, but there may be other solutions. In fact, there may be

infinitely many solutions.

Determine all the values of ω for which the above BVP has at least one nontrivial solution.

  1. Suppose φ 1 (x) and φ 2 (x) are linearly independent solutions of y

′′

  • P (x)y

  • Q(x)y = 0. Suppose fur-

ther that φ 1 (x) has at least two zeros. Show that φ 2 (x) has one and only one zero between consecutive

zeros of φ 1 (x).