3D Vectors components lecture notes, Lecture notes of Mathematics

3D vector components lecture notes

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2020/2021

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SESSION 3: COMPONENTS, 3D VECTORS, UNIT VECTORS
Components of a vector given magnitude and direction
Given a vector
𝑨
"
"
#
$
with magnitude
|𝑨
"
"
#
$|
and direction
𝜽
from
the positive x-axis to the positive y-axis (Illustration 1), we
calculate its x-component
𝑨𝒙
and its y-component
𝑨𝒚
by:
Magnitude and direction of a vector given its components
Given the x-component
𝐴*
and y-component
𝐴+
of vector
𝑨
"
"
#
, we calculate its magnitude
|𝑨
"
"
#
$|
and
direction
𝜃
by:
|𝑨
"
#
$|$=
𝐴*
1+
𝐵+
1
tan𝜃 = 𝐴+
𝐴* 𝜃 = arctan<𝐴+
𝐴*=
Resultant Vector
When multiple vectors
𝑨
"
"
#
>,𝑨
"
"
#
1,𝑨
"
"
#
@,,𝑨
"
"
#
B
are added, a resultant vector
𝑹
"
"
#
is generated. Illustration 2 shows
how multiple vectors may be added:
To calculate the x-component
𝑅*
and y-component
𝑅+
of the resultant vector
𝑹
"
"
#
, we have:
𝑅*=𝐴>E+𝐴1E+ 𝐴@E++𝐴BE
𝑅+=𝐴>G+𝐴1G+ 𝐴@G++𝐴BG
We calculate the magnitude and the direction of vector
𝑹
"
"
#
in the same manner as we do with other vectors.
𝐴*=𝐴cos𝜃
𝐴+=𝐴sin𝜃
Illustration1
Illustration 2
pf3
pf4
pf5

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SESSION 3: COMPONENTS, 3D VECTORS, UNIT VECTORS

Components of a vector given magnitude and direction

Given a vector 𝑨

with magnitude |𝑨

| and direction 𝜽 from

the positive x-axis to the positive y-axis (Illustration 1), we

calculate its x-component 𝑨 𝒙

and its y-component 𝑨

𝒚

by:

Magnitude and direction of a vector given its components

Given the x-component 𝐴

and y-component 𝐴

of vector 𝑨

, we calculate its magnitude |𝑨

| and

direction 𝜃 by:

1

1

tan 𝜃 =

⇒ 𝜃 = arctan <

Resultant Vector

When multiple vectors 𝑨

1

@

B

are added, a resultant vector 𝑹

is generated. Illustration 2 shows

how multiple vectors may be added:

To calculate the x-component 𝑅

and y-component 𝑅

of the resultant vector 𝑹

, we have:

E

1

E

@

E

B

E

G

1 G

@ G

B G

We calculate the magnitude and the direction of vector 𝑹

in the same manner as we do with other vectors.

= 𝐴 cos 𝜃

= 𝐴 sin 𝜃

Illustration

Illustration 2

Vectors in Three Dimensions

A vector 𝑨

in three dimensions is described by its x-, y-, and z-components, K𝐴

L

M (Illustration 3).

The distance between vectors 𝑨

and 𝑩

in three dimensions (Illustration 4) can be calculated by

1

1

L

L

1

Unit Vectors

A unit vector has a magnitude of 1 and is used to describe a direction in space. Vectors may be expressed

in unit-vector notation.

A unit vector 𝚤̂ points in the direction of the positive x-axis, 𝚥̂ in the direction of the positive y-axis, and 𝑘

T

in the direction of the positive z-axis (Illustration 5 and Illustration 6).

Vector 𝑨

with x- and y-components 𝐴

and 𝐴

respectively may be written as:

Illustration 3

Illustration 4

Illustration 5

Illustration 6

(c) To solve for the magnitude d𝐴

d and direction 𝜃 of the resultant vector,

d𝐴

d =

1

1

e( 5 𝑚

1

1

𝜃 = tan

f>

= tan

f>

= tan

f>

Vector Magnitude Direction x-component y-component

""⃗ 10 m 90° 𝟎𝒎 𝟏𝟎𝒎

"⃗ 5 m 0° 𝟓𝒎 𝟎𝒎

"""⃗ 4 m 90° 𝟎𝒎 𝟒𝒎

Resultant

vector 𝑨

15 m 𝟕𝟎° 𝟓𝒎 𝟏𝟒𝒎

(d) To express the resultant vector into unit vector notation,

  1. Given the vectors below, calculate the distance between 𝐴

and 𝐵

and between 𝐵

and 𝐶

= [ 12 𝑚, 4. 0 𝑚, − 2. 0 𝑚]

= [− 5. 0 𝑚, − 1. 0 𝑚, 6. 0 𝑚]

= [ 10 𝑚, 7. 0 𝑚, 3. 0 𝑚]

(a) To find the distance 𝐴𝐵 between 𝐴

and 𝐵

1

1

L

L

1

1

1

1

e 378 𝑚

1

(b) To find the distance BC between 𝐵

and 𝐶

1

1

L

L

1

e( − 5 𝑚 − 10 𝑚

1

1

1

  1. Given the following vectors 𝐴

and 𝐵

T

and 𝐵

T

, find 𝐴

and

its magnitude, and 𝐴

and its magnitude.

(a) To find 𝐴

L

L

T

T

= −r

  • 𝟏𝟎s

u

(b) To find the magnitude of 𝐴

d𝐴

d = e(− 1 )

1

1

1

(c) To find 𝐴

L

L

T

T

= 𝟑r̂ + 𝟐ŝ + 𝟒𝒌

u

(a) To find the magnitude of 𝐴

d𝐴

d =

e( 3

1

1

1