Empirical Formulas in Chemistry: Finding Simplest Ratio of Atoms, Study notes of Chemistry

The concept of empirical formulas in chemistry and provides steps to find the empirical formula of a compound. It also discusses how to use the empirical formula to determine the molecular formula. Real-life examples are given to illustrate the concepts.

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4.6  Empirical Formulas
The empirical formula is a formula that gives the simplest whole
number ratio of atoms in a compound.
For example, C
2
H
4
, C
3
H
6
, and C
4
H
8
all contain twice as many H
atoms than C atoms. Therefore, the empirical formula of all these
molecules is CH
2
.
The simplest ratio of C and H atoms is 1C : 2H
To find the empirical formula for chemistry problems, we will be
doing the opposite of finding the percent composition of a compound.
We can follow these steps:
1.
Find the number of moles present of each element in the
compound.
2.
Divide each of the number of moles by the
smallest
number of
moles calculated.
3.
Find the simplest
whole
number ratio from these numbers.
Ex) A 25.00 g sample of an orange compound is found to contain
6.64 g of Potassium, 8.84 g of Chromium, and 9.52 g of Oxygen.
Find the empirical formula.
If you are given percentages instead of masses, a good strategy is to
assume there is a total of 100 g of the substance.
Ex) A compound consists of 72.2% magnesium and 27.8% nitrogen
by mass. What is the empirical formula?
pf2

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4.6 Empirical Formulas

The empirical formula is a formula that gives the simplest whole number ratio of atoms in a compound. For example, C 2 H 4 , C 3 H 6 ,^ and^ C 4 H 8 all^ contain^ twice^ as^ many^ H atoms than C atoms. Therefore, the empirical formula of all these molecules is CH 2. The simplest ratio of C and H atoms is 1C : 2H To find the empirical formula for chemistry problems, we will be doing the opposite of finding the percent composition of a compound. We can follow these steps:

  1. Find the number of moles present of each element in the compound.
  2. Divide each of the number of moles by the smallest number of moles calculated.
  3. Find the simplest whole number ratio from these numbers. Ex) A 25.00 g sample of an orange compound is found to contain 6.64 g of Potassium, 8.84 g of Chromium, and 9.52 g of Oxygen. Find the empirical formula. If you are given percentages instead of masses, a good strategy is to assume there is a total of 100 g of the substance. Ex) A compound consists of 72.2% magnesium and 27.8% nitrogen by mass. What is the empirical formula?

Once we find the empirical formula, we can then find the molecular

formula.

In order to do this from the empirical formula, we need to know the

molecular mass of the compound.

If CH 2 is the empirical formula for C 2 H 4 , C 3 H 6 , and C 4 H 8 then the

molar masses of C 2 H 4 , C 3 H 6 , and C 4 H 8 must be a multiple of the

molar mass of CH 2 (or the empirical mass ).

To find this magical multiple, we must divide the molar mass of the

molecule by the empirical mass.

Once we have this multiple, we need to multiply that into the

empirical formula to find the number of atoms of each element in

our molecular formula.

Ex) Vitamin C’s empirical formula is C 3 H 4 O 3 ,^ Its^ molar^ mass^ is

180 g/mole. What is its molecular formula?