Chemistry: Determining Empirical and Molecular Formulas of Compounds, Lecture notes of Chemistry

Solutions to various problems related to determining empirical and molecular formulas of compounds. Topics covered include the difference between empirical and molecular formulas, identifying the empirical formula of benzene, determining the type of iron oxide based on the amount of iron, finding the empirical formula of an oxide formed by red phosphorus, and calculating the molecular formula of oxalic acid. Students studying chemistry will find this document useful for understanding the concepts of empirical and molecular formulas.

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2021/2022

Uploaded on 09/27/2022

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SHOW ALL WORK, ALL EQUATIONS, and ALL UNITS Name: _____________________________________
Empirical Formula, Molecular Formula, and Hydrates:
DETERMINE Empirical and Molecular Formula for the compound.
1. The compound benzene has two formulas, CH and C6H6. Which is the empirical formula and which is the molecular formula?
CH is the empirical formula (smallest whole-number ratio) and C6H6 is the
molecular formula (because it is NOT the smallest whole number ratio)…
Whole-Number ratio refers to the “Mole Ratio” – Subscripts within formula
2. Rust, or iron oxide can exist as either iron(II)oxide or as iron(III)oxide. If you analyzed the sample by isolating the iron from the
oxygen and found that you had 272.1 grams of iron which type of iron oxide are you looking at if you started with 350 grams
of rust?
3. A form of phosphorus called red phosphorus is used in match heads. When 0.062 grams of red phosphorus burns, 0.142 grams
of phosphorus oxide is formed. What is the empirical formula of this oxide?
0.142 grams ( P?O? ) - 0.062 grams Phosphorus = 0.08 grams of Oxygen
P:
mol
grams
Pmolgrams 3
100.2
97.30
1062.0
;
220.1
100.2
100.2
3
3
mol
mol
O:
mol
grams
Omolgrams 3
100.5
00.16
108.0
;
52
2
1
2
100.2
100.5
3
3
mol
mol
P2O5, phosphorus pentoxide
pf3

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SHOW ALL WORK , ALL EQUATIONS, and ALL UNITS Name: _____________________________________ Empirical Formula, Molecular Formula, and Hydrates:

DETERMINE Empirical and Molecular Formula for the compound.

  1. The compound benzene has two formulas, CH and C 6 H 6. Which is the empirical formula and which is the molecular formula?

CH is the empirical formula (smallest whole-number ratio) and C 6 H 6 is the

molecular formula (because it is NOT the smallest whole number ratio)…

Whole-Number ratio refers to the “Mole Ratio” – Subscripts within formula

  1. Rust, or iron oxide can exist as either iron(II)oxide or as iron(III)oxide. If you analyzed the sample by isolating the iron from the oxygen and found that you had 272.1 grams of iron – which type of iron oxide are you looking at if you started with 350 grams of rust?
  2. A form of phosphorus called red phosphorus is used in match heads. When 0.062 grams of red phosphorus burns, 0.142 grams of phosphorus oxide is formed. What is the empirical formula of this oxide?

0.142 grams ( P?O? ) - 0.062 grams Phosphorus = 0.08 grams of Oxygen

P: mol

grams

grams molP 3

 ^  ;^1.^022

3

3    

mol

mol

O: mol

grams

grams molO 3

 ^  ;^25

3

3    

mol

mol

P 2 O 5 , phosphorus pentoxide

  1. A compound is composed of 7.20 grams of carbon, 1.20 grams of hydrogen, and 9.60 grams of oxygen. The molar mass of the compound of the compound is 180 grams. Find the empirical and molecular formulas for the compound.
  2. Oxalic acid is a compound used in cosmetics and paints. A 0.725 gram sample of oxalic acid was found to contain 0.016 grams of hydrogen, 0.194 grams of carbon, and 0.516 grams of oxygen. If the molar mass of oxalic acid is 90.04 g/mol, what is the molecular formula?

H: mol

grams

grams molH

  1. 01587
  2. 008

  ;^1

mol

mol

C: mol

grams

grams molC

  1. 01615
  2. 01

  ;^1

mol

mol

O: mol

grams

grams molO

  ;^2

mol

mol

( HCO 2 )n = 12.01g + 1.008g + (2)16g = 45.018g ;^2

g

g n

( HCO 2 ) 2 = H 2 C 2 O 4