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Problem set questions related to the herbrand quotient in the context of finite cyclic groups and abelian groups on which they act. The herbrand quotient is defined as the ratio of the sizes of certain subgroups of an abelian group. Questions include showing the independence of the choice of generator, computing the herbrand quotient for specific g-modules, and proving properties of the herbrand quotient for exact sequences of g-modules.
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Problem set #
to do in class on Wednesday January 23
Suppose G is a finite cyclic group, and A is an abelian group on which G acts (i.e.,
A is a G-module). Define N : A → A by N (a) =
g∈G
ga. Fix a generator σ of G
and define
0
(A) := A
G
/image(N )
1
(A) := ker(N )/(σ − 1)A.
Define the Herbrand quotient
h(A) :=
0 (A)|
1 (A)|
if these quantities are finite.
(1) Show that
1 (A) is independent of the choice of σ.
(2) Compute h(A) for the following G-modules A:
(a) A = Z (with trivial G-action)
(b) A = R[G] for any ring R.
(3) If A is finite, show that h(A) = 1. Hint: check that the following sequences
are exact
0 −→ ker(N ) −→ A
N
−−→ image(N ) −→ 0
G → A
σ− 1
−−→ (σ − 1)A −→ 0.
(4) Show that if 0 → A → B → C → 0 is an exact sequence of G-modules, then
there is an exact hexagon
0 (A)
/ / ˆ H
0 (B)
!!
C
C
C
C
C
C
C
C
1 (C)
= = | | | | | | | |
0 (C)
} } |
|
|
|
|
|
|
|
1 (B)
a a C C C C C C C C
1 (A)
oo
(5) Show that if 0 → A → B → C → 0 is an exact sequence of G-modules, and
if at least two of h(A), h(B), h(C) are defined, then all three are defined and
h(B) = h(A)h(C).
(6) Show that if A has finite index in B then h(A) = h(B).
(7) Find an example of a G-module A such that h(A) = 1, but
0 (A) and
1 (A)
are not isomorphic abelian groups.