Absolute Value: Definition, Properties, and Examples, Slides of Algebra

An in-depth explanation of absolute value, including its definition, properties, and examples. It covers topics such as the distance between numbers on the number line, absolute value of expressions, and solving equations with absolute values. The document also includes exercises for practice.

Typology: Slides

2012/2013

Uploaded on 04/30/2013

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ยง4.3a Absolute
Value
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Download Absolute Value: Definition, Properties, and Examples and more Slides Algebra in PDF only on Docsity!

ยง4.3a Absolute

Value

Review ยง

๏‚ง Any QUESTIONS About

  • ยง4.2 โ†’ InEqualities & Problem-Solving

๏‚ง Any QUESTIONS About HomeWork

โ€ข ยง4.2 โ†’ HW-

4.2 MTH 55

Graph y = | x |

  • Make T-table x y = | x | -6 6 -5 5 -4 4 -3 3 -2 2 -1 1 0 0 1 1 2 2 3 3 4 4 5 5 6 6

x

y

**-

-**

0

1

2

3

4

5

6

-6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6

file =XY_Plot_0211.xls

Absolute Value Properties

  1. | ab | = | a |ยท | b | for any real numbers a & b
    • The absolute value of a product is the product of the absolute values
  2. | a / b | = | a |/| b | for any real numbers a & b โ‰  0
    • The absolute value of a quotient is the quotient of the absolute values
  3. |โˆ’a| = |a| for any real number a
    • The absolute value of the opposite of a number is the same as the absolute value of the number

Distance & Absolute-Value

  • For any real numbers a and b , the distance between them is | a โ€“ b |
  • Example ๏ƒ† Find the distance between โˆ’ 12 and โˆ’56 on the number line
  • SOLUTION
    • |โˆ’ 12 โˆ’ (โˆ’56)| = |+44| = 44
    • Or
    • |โˆ’ 56 โˆ’ (โˆ’12)| = |โˆ’44| = 44

Example ๏ƒ† AbsVal Expressions

  • Find the Solution-Sets for

a) | x | = 6 b) | x | = 0 c) | x | = โˆ’

  • SOLUTION a) | x | = 6
  • We interpret | x | = 6 to mean that the number x is 6 units from zero on a number line.
  • Thus the solution set is {โˆ’6, 6}

Example ๏ƒ† AbsVal Expressions

  • Find the Solution-Sets for

a) | x | = 6 b) | x | = 0 c) | x | = โˆ’

  • SOLUTION c) | x | = โˆ’
  • Since distance is always NonNegative, | x | = โˆ’ has NO solution.
  • Thus the solution set is ร˜

Absolute Value Principle

  • For any positive number p and any

algebraic expression X :

a. The solutions of | X | = p are those numbers that satisfy X = โˆ’ p or X = p

b. The equation | X | = 0 is equivalent to the equation X = 0

c. The equation | X | = โˆ’ p has no solution.

Example ๏ƒ† AbsVal Principle

  • Solve: a) |2 x +1| = 5; b) |3 โˆ’ 4 x | = โˆ’
  • SOLUTION b) |3 โˆ’ 4 x | = โˆ’
    • The absolute-value principle reminds us that absolute value is always nonnegative.
    • So the equation |3 โˆ’ 4 x | = โˆ’10 has NO solution.
    • Thus The solution set is ร˜

Example ๏ƒ† AbsVal Principle

  • Solve |2 x + 3| = 5
  • SOLUTION
    • For |2 x + 3| to equal 5, 2 x + 3 must be 5 units from 0 on the no. line. This can happen only when 2 x + 3 = 5 or 2 x + 3 = โˆ’5.
    • Solve Equation Set

2 x + 3 = 5 or 2 x + 3 = โ€“ 2 x = 2 x = 1

2 x = โ€“ x = โ€“

or or

  • Graphing the Solutions โ€“5 โ€“4 โ€“3 โ€“2 โ€“1 0 1 2 3 4 5

Two AbsVal Expression Eqns

  • Sometimes an equation has TWO absolute- value expressions.
  • Consider | a | = | b |. This means that a and b are the same distance from zero.
  • If a and b are the same distance from zero, then either they are the same number or they are opposites.

Example ๏ƒ† 2 AbsVal Expressions

  • Solve: |3 x โ€“ 5| = |8 + 4 x |.
  • SOLUTION
    • Recall that if | a | = | b | then either they are the same or they are opposites

3 x โ€“ 5 = 8 + 4 x

This assumes these numbers are the same

This assumes these numbers are opposites.

3 x โ€“ 5 = โ€“(8 + 4 x )

OR

๏‚ง Need to solve Both Eqns for x

Solve Eqns of Form | ax + b | = | cx + d |

  • To solve an equation in the form

| ax + b | = | cx + d |

1. Separate the absolute value equation

into two equations: ax + b = cx + d and

ax + b = โˆ’ ( cx + d ).

2. Solve both equations.

Inequalities &AbsVal Expressions

  • Example ๏ƒ† Solve: |x| < 3 Then graph
  • SOLUTION
    • The solutions of | x | < 3 are all numbers whose distance from zero is less than 3. By substituting we find that numbers such as โˆ’2, โˆ’1, โˆ’1/2, 0, 1/3, 1, and 2 are all solutions.
    • The solution set is { x | โˆ’3 < x < 3}. In interval notation, the solution set is (โˆ’3, 3). The graph:

-3 3

( (^) )