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ยง4.3a Absolute
Value
Review ยง
๏ง Any QUESTIONS About
- ยง4.2 โ InEqualities & Problem-Solving
๏ง Any QUESTIONS About HomeWork
โข ยง4.2 โ HW-
4.2 MTH 55
Graph y = | x |
- Make T-table x y = | x | -6 6 -5 5 -4 4 -3 3 -2 2 -1 1 0 0 1 1 2 2 3 3 4 4 5 5 6 6
x
y
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0
1
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3
4
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-6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6
file =XY_Plot_0211.xls
Absolute Value Properties
- | ab | = | a |ยท | b | for any real numbers a & b
- The absolute value of a product is the product of the absolute values
- | a / b | = | a |/| b | for any real numbers a & b โ 0
- The absolute value of a quotient is the quotient of the absolute values
- |โa| = |a| for any real number a
- The absolute value of the opposite of a number is the same as the absolute value of the number
Distance & Absolute-Value
- For any real numbers a and b , the distance between them is | a โ b |
- Example ๏ Find the distance between โ 12 and โ56 on the number line
- SOLUTION
- |โ 12 โ (โ56)| = |+44| = 44
- Or
- |โ 56 โ (โ12)| = |โ44| = 44
Example ๏ AbsVal Expressions
- Find the Solution-Sets for
a) | x | = 6 b) | x | = 0 c) | x | = โ
- SOLUTION a) | x | = 6
- We interpret | x | = 6 to mean that the number x is 6 units from zero on a number line.
- Thus the solution set is {โ6, 6}
Example ๏ AbsVal Expressions
- Find the Solution-Sets for
a) | x | = 6 b) | x | = 0 c) | x | = โ
- SOLUTION c) | x | = โ
- Since distance is always NonNegative, | x | = โ has NO solution.
- Thus the solution set is ร
Absolute Value Principle
- For any positive number p and any
algebraic expression X :
a. The solutions of | X | = p are those numbers that satisfy X = โ p or X = p
b. The equation | X | = 0 is equivalent to the equation X = 0
c. The equation | X | = โ p has no solution.
Example ๏ AbsVal Principle
- Solve: a) |2 x +1| = 5; b) |3 โ 4 x | = โ
- SOLUTION b) |3 โ 4 x | = โ
- The absolute-value principle reminds us that absolute value is always nonnegative.
- So the equation |3 โ 4 x | = โ10 has NO solution.
- Thus The solution set is ร
Example ๏ AbsVal Principle
- Solve |2 x + 3| = 5
- SOLUTION
- For |2 x + 3| to equal 5, 2 x + 3 must be 5 units from 0 on the no. line. This can happen only when 2 x + 3 = 5 or 2 x + 3 = โ5.
- Solve Equation Set
2 x + 3 = 5 or 2 x + 3 = โ 2 x = 2 x = 1
2 x = โ x = โ
or or
- Graphing the Solutions โ5 โ4 โ3 โ2 โ1 0 1 2 3 4 5
Two AbsVal Expression Eqns
- Sometimes an equation has TWO absolute- value expressions.
- Consider | a | = | b |. This means that a and b are the same distance from zero.
- If a and b are the same distance from zero, then either they are the same number or they are opposites.
Example ๏ 2 AbsVal Expressions
- Solve: |3 x โ 5| = |8 + 4 x |.
- SOLUTION
- Recall that if | a | = | b | then either they are the same or they are opposites
3 x โ 5 = 8 + 4 x
This assumes these numbers are the same
This assumes these numbers are opposites.
3 x โ 5 = โ(8 + 4 x )
OR
๏ง Need to solve Both Eqns for x
Solve Eqns of Form | ax + b | = | cx + d |
- To solve an equation in the form
| ax + b | = | cx + d |
1. Separate the absolute value equation
into two equations: ax + b = cx + d and
ax + b = โ ( cx + d ).
2. Solve both equations.
Inequalities &AbsVal Expressions
- Example ๏ Solve: |x| < 3 Then graph
- SOLUTION
- The solutions of | x | < 3 are all numbers whose distance from zero is less than 3. By substituting we find that numbers such as โ2, โ1, โ1/2, 0, 1/3, 1, and 2 are all solutions.
- The solution set is { x | โ3 < x < 3}. In interval notation, the solution set is (โ3, 3). The graph:
-3 3
( (^) )