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Activity on Piecewise Function, Exercises of Mathematical Analysis

Adamson University (AU)Mathematical Analysis

An Activity about piecewise function with answers and solutions

Typology: Exercises

2021/2022

Available from 03/24/2022

carbon418
carbon418 ๐Ÿ‡ต๐Ÿ‡ญ

3 documents

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5๐‘ฅ + 6 ๐‘“ โ‰ฅ 0
2
College of Science
Mathematics and Physics Department
Computing 1
Piecewise Function
VII. Activity
Name: ________________________________________________________________________________________________
Direction: Solve the given problem.
Evaluate a Piecewise-Function
I. Given the function ๐‘“(๐‘ฅ) = { 5๐‘ฅ + 3 ๐‘– ๐‘“๐‘ฅ < 0 , evaluate:
1. ๐‘“(โˆ’1)
2. ๐‘“(0)
3. ๐‘“(2)
๐‘บ๐’๐’๐’–๐’•๐’Š๐’๐’ ๐’‚๐’๐’… ๐‘จ๐’๐’”๐’˜๐’†๐’“:
5๐‘ฅ + 3 ๐‘–๐‘“ ๐‘ฅ < 0
๐‘“(โˆ’1) = 5(โˆ’1) + 3
= โˆ’5 + 3
๐‘“(โˆ’1) = โˆ’2
๐‘บ๐’๐’๐’–๐’•๐’Š๐’๐’ ๐’‚๐’๐’… ๐‘จ๐’๐’”๐’˜๐’†๐’“:
5๐‘ฅ + 6 ๐‘–๐‘“ ๐‘ฅ โ‰ฅ 0
๐‘“(0)= 5(0)+6
= 0 + 6
๐‘“(0) = 6
๐‘บ๐’๐’๐’–๐’•๐’Š๐’๐’ ๐’‚๐’๐’… ๐‘จ๐’๐’”๐’˜๐’†๐’“:
5๐‘ฅ + 6 ๐‘–๐‘“ ๐‘ฅ โ‰ฅ 0
๐‘“(2)= 5(2)+6
= 10 + 6
๐‘“(2) = 16
Michelle Anne C. Dungo
Section: CM 101
pf2

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2

College of Science

Mathematics and Physics Department

Computing 1

Piecewise Function

VII. Activity

Name: ________________________________________________________________________________________________

Direction: Solve the given problem.

Evaluate a Piecewise-Function

I. Given the function ๐‘“

, evaluate:

5 ๐‘ฅ + 3 ๐‘–๐‘“ ๐‘ฅ < 0

๐‘“(โˆ’ 1 ) = 5 (โˆ’ 1 ) + 3

= โˆ’ 5 + 3

๐‘“(โˆ’ 1 ) = โˆ’ 2

5 ๐‘ฅ + 6 ๐‘–๐‘“ ๐‘ฅ โ‰ฅ 0

๐‘“

( 0

) = 5

( 0

)

  • 6

= 0 + 6

๐‘“( 0 ) = 6

5 ๐‘ฅ + 6 ๐‘–๐‘“ ๐‘ฅ โ‰ฅ 0

๐‘“

( 2

) = 5

( 2

)

  • 6

= 10 + 6

๐‘“( 2 ) = 16

Michelle Anne C. Dungo

Section: CM 101

1 / 2

II. Sketch a graph of the function and state its domain and range

Given the piecewise definition

5 ๐‘ฅ + 6 ๐‘–๐‘“ ๐‘ฅ โ‰ฅ 0

๐‘“ (

1

2

) = 5 (

1

2

) + 6

=

5

2

  • 6

=

17

2

๐‘“ (

1

2

) = 8

1

2

5 ๐‘ฅ + 6 ๐‘–๐‘“ ๐‘ฅ โ‰ฅ 0

๐‘“( 5 ) = 5 ( 5 ) + 6

= 25 + 6

๐‘“

( 5

) = 31