Algebra
Least Common Multiple (L.C.M.)
๏ท L.C.M by Factorization
1. Find the L.C.M of the following:
(i) 3 a4 b2 c3, 5 a2 b3 c5
Solution: L.C.M of 3 x 5 =15
L.C.M of 3 a4 b2 c3 , 5 a2 b3 c5 is 15 a4 b3 c5
(ii) 15 x3 y3 z, 25 x y3 z2
Solution:
5 15, 25
3, 5
L.C.M of 15 x3 y3 z, 25 x y3 z2 is 75 x3 y3 z2
(iii) 15 p3 q4, 20 m2 p2 q3, 30 m p3
Solution:
5 15, 20, 30
2 3, 4, 6
3 3, 2, 3
1, 2, 1
L.C.M of 15 p3 q4, 20 m2 p2 q3 , 30 m p3 is 60 p3 q4 m2.
