Algebra maths problems, Assignments of Algebra

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HOW TO WORK WORD PROBLEMS IN ALGEBRA: PART II Word Problem Examples: 1. Age: Abigail is 6 years older than Jonathan. Six years ago she was twice as old as he. How old is each now? Solution: Let x = Jonathan's age now (smaller number) = Abigail's age now (x + 6)- 6 = Abigail's age 6 years ago Six years ago she was twice as old as he. Equation: (x+6)-6 Answers: x = 12 (Jonathan’s age now) x+6=18 (Abigail’s age now) 2. Numbers: There are two numbers whose sum is 72. One number is twice the other. What are the numbers? Steps: 1. Read the probiem. It is about numbers. 2. The question at the end asks, "What are the numbers?" So we start out "let x = smaller number,” Be sure you always start with x (that is, 1x). Never start off with “let 2x = something,” because it is meaningless unless you know what x stands for. 3. Now let's put it all together and solve. Solution: Let x = smaller number 2x = larger number Then x + 2x = 72 3x=72 Answers: x = 24 (smaller number) 2x = 48 (larger number) Check: The sum of the numbers is 72. Thus 24 + 48 = 72.