Amount - Engineering Economics - Solved Exam, Exams of Microeconomics

Main points of this exam paper are: Amount, Condition, Beginning, Interest Compounding, Same, Interest, Nominal Yearly Rate

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CE 167 Midterm #1
Fall 2000
Prof. C.W. Ibbs
Question #1 [15 Points]
The amount of $600 per year is to be paid into an account over each of the next 4 years. The
nominal interest rate is 15% per year. Determine the total amount the account will eventually
contain under the following conditions:
(a) Deposits are made at the beginning of the year with interest compounding yearly:
NFV = [$600 (F/A, 15%, 4)](1+i)
NFV = $600 )1(
1)1( i
i
in+
+
NFV = $600 )15.01(
15.0
1)15.01( 4+
+
NFV = $344.45.43
(b) Deposits at the end of the year with interest compounding yearly:
NFV = [$600(F/A, 15%, 4)]
This is the same as the Part (a),
except you do not have to account
for the extra year of interest
NFV = $600
+
15.0
1)15.01( 4 = $2996.03
For Parts (a) & (b), 3 points were awarded for the correct usage of the formula, and 2 points
for the correct answer.
(c) $50 deposits are made at the end of each month with interest compounding monthly:
Since i = 15% is a nominal yearly rate, you must find ieffective:
ieffective = 11
+
m
m
r = 1
12
15.0
1
12
+ = 16.08%
ieffective = 16.08% per year = 1.34% per month This part was worth 1 point
A=$600
F=?
Because the equations are set up so that
payment are made at the end of the year,
you have to account for the one extra
year’s worth of interest made by making
the deposit at the beginning of the year!
A=$600
F=?
0
1
2
3
0
1
2
3
pf3
pf4
pf5
pf8

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CE 167 Midterm #

Fall 2000

Prof. C.W. Ibbs

Question #1 [15 Points]

The amount of $600 per year is to be paid into an account over each of the next 4 years. The nominal interest rate is 15% per year. Determine the total amount the account will eventually contain under the following conditions:

(a) Deposits are made at the beginning of the year with interest compounding yearly:

NFV = $600 (F/A, 15%, 4)

NFV = $600 ( 1 )

i i

i n ^ + 

NFV = $600 ( 1 0. 15 )

4 ^ + 

NFV = $344.45.

(b) Deposits at the end of the year with interest compounding yearly:

NFV = [$600(F/A, 15%, 4)]

This is the same as the Part (a), except you do not have to account for the extra year of interest

NFV = $600 

4 = $2996.

For Parts (a) & (b), 3 points were awarded for the correct usage of the formula, and 2 points for the correct answer.

(c) $50 deposits are made at the end of each month with interest compounding monthly:

Since i = 15% is a nominal yearly rate, you must find ieffective:

ieffective = (^1)  − 1 

m

m

r = 1 12

12

^ − 

ieffective = 16.08% per year = 1.34% per month This part was worth 1 point

A=$

F=?

Because the equations are set up so that payment are made at the end of the year, you have to account for the one extra year’s worth of interest made by making the deposit at the beginning of the year!

A=$

F=?

0 1 2 3

0 1 2 3

NFV = [$50(F/A, ieffective, 48)] (48 payments = 12 months/year times 4 years)

NFV = $50 

( 1 0. 0134 )^481

= $3337.

The use of the correct equation (after finding ieffective) was worth 3 points; the correct answer was worth 1 point.

Question #2 [15 Points]

You are considering buying office space. You can buy two small office buildings or one large office building. The small buildings cost $1,000,000 apiece and have a resale value of $1,100,000 apiece after two years. The large office building costs $2,200,000 and has a resale value of $2,350,000 after two years. The purchase of the two small buildings will provide a total of $40,000 of net income per year. The purchase of the large office will provide a total of $50, of net income per year. Your MARR is 4%. On the basis of an internal rate of return comparison, which option would you choose? Why? (Net income is accrued at the end of the year.)

Option 2 Small Buildings 1 Large Building Initial Cost $2,000,000 $2,200, Yearly Benefit $40,000 $50, Salvage $2,200,000 $2,350,

MARR = 4%

2 Small Buildings:

NPV = 0 = -$2M + 

+ 1 2 ( 1 )^2

i

M

i

k i

k

NPV is approximately 0 when i = 7%, therefore the IRR (^) 2small = 7% > MARR; this is a viable option!

Solving for the IRR = 5 points

1 2 47 48

A = $

F =?

P = $2M

A = $40k

F = $2.2M

NPV

i 6 7

IRR = 7% Not To Scale!

Question #3 [35 points total]

Part A [15 points]

A small municipality determines that it will cost $1,000,000 to build a water treatment plant in 10 years (end of year 10). The municipality also expects the plant to last for 20 years. The municipality currently has no money set aside for the plant and estimates that it will take $75, per year to cover operating expenses. How much does the municipality need to set aside from its budget per year (uniform amount) for the next 10 years in order to afford this plant. Assume i = 8%.

Water treatment plant will cost $1M at EOY 10 → F 10 =$1M

Operating costs will be $75k for 20 years → A10-30 = $75k/year

Find A1-

In year 10: A1-10 (F/A, 8%, 10) = $1M + A10-30 (P/A, 8%, 20)

I used tables for simplicity: A1-10 (14.486) - $1M + $75k(9.8181)

A1-10 = 

$ 1 M $ 75 k ( 9. 8181 ) = $119,

The municipality must save $119,865 per year for ten years (year 1 through year 10) to be able to afford the plant & maintenance.

5 points each for both of the annuity equations; 5 points for the correct answer

Part B [20 points]

Conduct a sensitivity analysis on key variables, except number of years. Briefly discuss your results.

The most important variable to vary is the interest rate, so it was necessary to vary it. We would have given credit for a correct sensitivity analysis of any of the other variables. Vary by 10-30%.

I varied by 25%. Therefore, i +/-25% = 6%, 10%

For i = 6%: A1-10 (F/A, 6%, 10) = $1M + $75k(P/A, 6%, 20) A1-10 (13.180) = $1M + $75k(11.47) A1-10 = $141,142 per year

A1-

A10- $1M

Year 0 Year 10 Year 30

For i = 10%: A1-10 (F/A, 10%, 10) = $1M + $75k(P/A, 10%, 20) A1-10 (15.937) = $1M + $75k(8.5436) A1-10 = $102,954 per year

Maintenance +/- 25% = $56,250, $93,

For $56,250: A1-10 (F/A, 8%, 10) = $1M + $56,250(P/A, 8%, 20) A1-10 (14.486) = $1M + $56,250(9.8181) A1-10 = $102,954 per year

For $93,750: A1-10 (F/A, 8%, 10) = $1M + $93,750(P/A, 8%, 20) A1-10 (14.486) = $1M + $93,750(9.8181) A1-10 = $132,573 per year

The slope of the i +/- 25% line is steeper, so changes in i will affect the project more severly than changes in maintenance costs.

4 points were given for each individual part of the sensitivity analysis (+ and ñ for two variables) and 4 points were given for at least a basic interpretation of your results.

-25% +25%

I+/-25%

Maintenance +/- 25%

This diagram is Not To Scale!

Question #5 [10 points total ñ 5 point each]

Draw the relationship for a Design-Bid-Build contract. Identify and discuss 3 advantages to the client of the Design-Bid-Build method of construction.

Draw the relationship for a Design-Build contract. Identify and discuss 3 advantages to the client of the Design-Build method of construction.

Owner

A/E

Designer

General Contractor

! Well established method of contracting ! Specialization of the involved parties (design, construction, etc.) ! Design is completed prior to construction, which leads to… ! …A final estimated cost can be determine prior to construction ! Bidding leads to more competitive bids Design

Bid

Construct

time

Owner

Design/Build Firm

Design

Construct

time

! Integrated team—improves communication (designers and contractors on same team, so they should be in communication with each other) ! Owner is dealing with only one contract (owner is saved from designer/contractor disputes) ! Fast-tracking due to overlap of design and construction (saves time) ! Designs are created with the builder in mind (or at least more so than Design-Bid-Build)

2 points

3 points total

2 points

3 points total

Question #6 [15 points total] Be specific!

Who were the original owners of Rincon Center? How were they organized? Draw the contractual relationship of the major parties. [5 Points]

What was Tutor-Salibaís (and its owner Ron Tutorís) role in Rincon Center? How did this arrangement hurt and/or hinder the construction of Rincon Center? [10 Points]

Tutor-Saliba’s role in Rincon Center was two-fold. First, Tutor-Saliba was brought in as an owner, and second, they were made the general contractor. The prevailing wisdom was that having the GC as part owner would help keep construction costs down. However, Tutor-Saliba’s organizational role hindered the project. Tutor-Saliba did not have adequate experience with this type of project, and advised the other owners incorrectly. Tutor insisted on concrete, and did not accurately estimate the cost of building with concrete. The other owners were too easily persuaded by Tutor and accepted his input without sufficient proof. An outsider (like an agency construction management firm) should have been employed to provide an objective opinion, and also keep an eye on costs. The project should have gone out to open bid, or a professional construction manager, independent project accountant, engineer, or other knowledgeable consultant should have been hired. This way Tutor’s organizational position could not have been abused.

Also, Tutor-Saliba’s position created a conflict of interest that experienced owners or a construction manager would have caught. Tutor had the motivation to low-ball the expected costs because then he gets a larger percentage of the ownership pie (if he is investing a fixed amount, $X, then $X is a larger percentage of a smaller number). But, when he actually started building, he could recoup costs through mark ups (he was providing capital to be an owner, but he was being paid as a contractor to construct Rincon Center, so he also makes money by jacking up the construction costs). For Tutor, it was a win-win situation, despite the fact that the escalating construction costs were pinching the other owners.

  • 2 points were given if the fact that Tutor (or Tutor-Saliba) were part owners and the general contractor
  • 1 point each were given if the fact that Tutor insisted on concrete over steel (and the subsequent events), Tutor hindered the construction, and Tutor’s lack of experience for this type of construction were mentioned
  • The remaining 5 points came from discussing Tutor’s conflict of interest (more detail on the owner/GC conflict) and grader discretion (your overall grasp of the question).

Perini Land & Development (50.1%)

Blumenthal (2%)

P.Q. Chin (18.45%) Tutor-Saliba (13%) Blumenthal (16.45%)

Tier 1 Owners

Tier 2 (limited) Owners

Designers ! Chin & Hensolt ! Pereira

General Contractor ! Tutor-Saliba

Points:

  • 2: some names
  • 3: names only
  • 4: all names, no organizational structure
  • 5: fully understood framework and structure