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Principal Jaime Martinez Instructor Ms. Carolyn Peterson Assistant Principal 965 Longwood ave
Assignment # 1
Aim: How Do We Calculate the Distance Between Bends for Making an Offset?
BENFIELD’S OFFSET TABLE Angle Constant Multiplier Shrink Per Inch of Offset Depth 10 X 10 6 1/16" Per Inch 22 ½ X 22 ½ 2.6 3/16" Per Inch 30 X 30 2 1/4 " Per Inch 45 X 45 1.4 3/8 " Per Inch 60 X 60 1.2 1/2 " Per Inch
Benfield’s Distance Between Bends Formula Offset Depth X Constant Multiplier = Distance Between Bends
Directions : Using Benfield’s formula calculate the distance between bends, for making offsets using the information provided in the question below. You must show all work! Question : The distance from the center of a coupling to the edge of a 1900 box is (A). The 1900 box is
secured to a beam that has a depth of (B). Calculate the distance between bends for making an offset using an
angle of (C) degrees?
A =30" B =5" C =30o^ 2) A =45" B =6" C =10o
A =44 1/2 " B =10" C =45 o^ 4) A =48 1/4 " B =8" C =30 o
Example of how to perform calculations based on the question above.
1st. Read the question carefully.
A) Then draw a picture of the situation described. B) After that, refer to Benfield’s offset formula to determine the information necessary for calculating the distance between bends. a) The depth of the offset is represented by the letter ______. b) The offset angle is represented by the letter ______. c) The constant multiplier is determined by knowing the _____________ used for making the offset. d) *note that the measurement designated by the letter “ A ” is not needed to calculate the distance between bends. C) Then, substitute the words with numbers in the formula and multiply.
Answer to #1 (^) Offset Depth X Constant Multiplier = Distance Between Bends
5" X 2 = 10"
Principal Jaime Martinez Instructor Ms. Carolyn Peterson Assistant Principal 965 Longwood ave
Assignment # 2
Aim: How Do We Perform Calculations for Determining the Distance Between Bends?
BENFIELD’S OFFSET TABLE
Angle Constant Multiplier Shrink Per Inch of Offset Depth 10 X 10 6 1/16" Per Inch 22 ½ X 22 ½ 2.6 3/16" Per Inch 30 X 30 2 1/4 " Per Inch 45 X 45 1.4 3/8 " Per Inch 60 X 60 1.2 1/2^ " Per Inch
Benfield’s Distance Between Bends Formula
Offset Depth X Constant Multiplier = Distance Between Bends
The picture above shows a bird’s eye view of an offset bend.
Directions : Calculate the distance between bends for the problems shown below.
All final answers must be:
A) reduced to lowest terms B) fractions that can be read on a standard ruler (NO decimal answers)
You Must Show All Work
1. Offset Depth = 7" 2. Offset Depth = 3" 3. Offset Depth = 6 3/8" 4. Offset Depth = 4 1/4" Angle = 30° Angle = 45° Angle = 10° Angle = 22 ½°
b
a
c
COLUMN
Principal Jaime Martinez Instructor Ms. Carolyn Peterson Assistant Principal 965 Longwood ave
Assignment # 3
Aim: How Do We Perform Calculations for Determining Conduit Shrinkage?
BENFIELD’S OFFSET TABLE Angle Constant Multiplier Shrink Per Inch of Offset Depth 10 X 10 6 1/16" Per Inch 22 ½ X 22 ½ 2.6 3/16" Per Inch 30 X 30 2 1/4 " Per Inch 45 X 45 1.4 3/8 " Per Inch 60 X 60 1.2 1/2 " Per Inch
Directions : Determine conduit shrinkage, for making offsets using the information provided in the question below.
You must show all work!
Question : The distance from a coupling to the edge of a 1900 box is ( A ). The 1900 box is secured to a beam that has
a depth of ( B ). Determine how much the conduit will shrink for making an offset using ( C ) degree angles?
A =30" B =5" C =30 o^ 2) A =45" B =6" C =10 o
A =44 1/2" B =10" C =45 o^ 4) A =48 1/4" B =8" C =30 o
For question #2: at what measurement must you mark the conduit for cutting before you make the offset bend, so that it will fit perfectly between the 1900 box and the coupling?
Example : of how to calculate conduit shrinkage for the questions above.
2nd. Read the question carefully.
A) Then draw a picture of the situation described. B) Next refer to Benfields offset formula to determine the information necessary for calculating the conduit shrinkage. C) The depth of the offset is represented by the letter ______. D) The offset angle is represented by the letter ______. E) The Shrink Per Inch is determined by knowing the _____________ used for making the offset.
*note : that the letter “ A ” is not needed to calculate the conduit shrinkage.
Perform Calculation : Look at the table to find the desired angle then look at the Shrink Per Inch column.
Next, substitute the words with numbers in the formula and multiply.
Offset Depth X Shrink Per Inch = Conduit Shrinkage 5" X ¼ = 5/4 = 1 ¼" *Change 5/4 from an improper fraction to a mixed number.
Principal Jaime Martinez Instructor Ms. Carolyn Peterson Assistant Principal 965 Longwood ave
Assignment # 4
BENFIELD’S OFFSET TABLE
Angle Constant Multiplier Shrink Per Inch of Offset Depth 10 X 10 6 1/16" Per Inch 22 ½ X 22 ½ 2.6 3/16" Per Inch 30 X 30 2 1/4 " Per Inch 45 X 45 1.4 3/8^ " Per Inch 60 X 60 1.2 1/2 " Per Inch
Benfield’s Conduit Shrinkage Formula
Offset Depth X Shrink Per Inch = Conduit Shrinkage
The picture above shows a bird’s eye view of an offset bend made to fit between a coupling and a 1900 box.
Directions :
Calculate conduit shrinkage and at what measurement you will cut the pipe before bending offsets using the distance, depth, and angles given below. Change all answers to fractions that can be identified on a standard ruler.
1) Distance = 50 " 2) Distance = 43 " Angle = 30° Angle = 45° Depth = 5" Depth = 4 ½ "
3) Distance = 57 ⅝ " 4) Distance = 31 ⅜ " Angle = 10° Angle = 22 ½° Depth = 6" Depth = 3 1/16 "
COLUMN
b
A
COUPLING
1900 BOX
a
c
Principal Jaime Martinez Instructor Ms. Carolyn Peterson Assistant Principal 965 Longwood ave
Assignment # 6
3 Point Saddle Bend
Directions: Calculate how much you must move your center mark ahead and the distance you make your
outer marks from the center mark when bending a Three Point Saddle for the following example. Change all
decimal answers to fractions that can be identified on a standard ruler.
Example: The distance from the edge of a 1900 box to the center of a water pipe is (A), and the water pipe
has an outside diameter of (B).
1. A=18 ¼ " B=3 " 2. A=31 ½" B=5 "
3. A=19 ¼ " B=2 " 4. A=30" B=4 "
- For problem number two and three : At what measurement must you make your center mark on the conduit?
A
B
Principal Jaime Martinez Instructor Ms. Carolyn Peterson Assistant Principal 965 Longwood ave
Assignment # 7
- What shape is formed by an offset bend?
- What name is given to the longest side of a right triangle?
- The Hypotenuse is always opposite which angle?
- What formula (theorem) is used to determine the unknown side of a right triangle?
- If side (a) measured 3" and side (b) 4", how long would side C measure?
- What would side c measure if (a) is 4" and (b) is 5"?
a
b
c
Principal Jaime Martinez Instructor Ms. Carolyn Peterson Assistant Principal 965 Longwood ave
Assignment # 9
Aim : How Do We Determine the Angle Used for Making an Offset Bend When the Dimensions are Given?
BENFIELD’S OFFSET TABLE ANGLE CONSTANT MULTIPLIER SHRINK PER INCH OF OFFSET DEPTH 10 X 10 6 1/16" Per Inch 22 ½ X 22 ½ 2.6 (^) 3/16" Per Inch 30 X 30 2 1/4 " Per Inch 45 X 45 1.4 3/8 " Per Inch 60 X 60 1.2 1/2 " Per Inch
- Using Benfields offset formula; calculate the distance between bends for an offset with a depth of 5 inches
when using 30 degrees?
- Using Pythagoreans Theorem Calculate the distance between bends for an offset if the:
A) Distance from the 1 st^ bend to the obstruction is 8 " B) Offset depth is 6 "
- In question number two all the sides are known; at what angle must you make your bends?
a
b
c
Principal Jaime Martinez Instructor Ms. Carolyn Peterson Assistant Principal 965 Longwood ave
Assignment # 10
Trigonometry and Offset Bends
- Use the triangle pictured above to fill in the blanks.
Angle A is opposite side____ and adjacent to side____
Angle B is opposite side____ and adjacent to side____
The Hypotenuse is always opposite the________ angle.
- Determine the distance between bends for an offset; where angle (A) = 40 degrees and side (a) is 10 inches.
- Determine angle (B) if side (a) is 5 " and side (b) is 10".
a
c
b
A
B
