Assignment 3 Solutions - Application Order Differential Equations | MATH 0266A, Assignments of Mathematics

Material Type: Assignment; Class: APPL ORD DIFF EQUAT; Subject: Mathematics; University: University of California - Los Angeles; Term: Fall 2006;

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Jeffrey Hellrung
Friday, October 20, 2006
Math 266A, Homework 02
1. Show that for any matrices A, B of small size,
e1
2AeBe1
2AeA+B=O(|A|3+|B|3).
Solution
By definition,
e1
2A=I+1
2A+1
8A2+O(|A|3);
eB=I+B+1
2B2+O(|B|3);
eA+B=I+ (A+B) + 1
2(A+B)2+O(|A+B|3).
It follows that
e1
2AeBe1
2A=I+1
2A+1
8A2I+B+1
2B2I+1
2A+1
8A2+O(|A|3+|B|3)
=I+1
2+1
2A+B+1
8+1
4+1
8A2+1
2AB +1
2BA +1
2B2+O(|A|3+|B|3)
=I+A+B+1
2(A2+AB +BA +B2) + O(|A|3+|B|3)
=eA+B+O(|A|3+|B|3),
as desired.
2. Let
A=2ǫ1
0ǫ, x0=0
1.
Let x(t) solve
xt=Ax, x(0) = x0.
Find
max
0t<|x(t)|.
Solution
The general solution is easily found to be
x(t) = c11
0e2ǫt +c21
ǫeǫt.
With the initial condition x(0) = x0, we find that
c1=1
ǫ, c2=1
ǫ,
giving
x(t) = 1
ǫeǫt 1eǫt
ǫ.
From the above we can easily deduce that
max |x(t)| |x(1)| O(1).
1
pf2

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Download Assignment 3 Solutions - Application Order Differential Equations | MATH 0266A and more Assignments Mathematics in PDF only on Docsity!

Jeffrey Hellrung Friday, October 20, 2006 Math 266A, Homework 02

  1. Show that for any matrices A, B of small size,

e

(^12) A eB^ e

(^12) A − eA+B^ = O(|A|^3 + |B|^3 ).

Solution By definition,

e

1 2 A^ = I +

A +

A^2 + O(|A|^3 );

eB^ = I + B +

B^2 + O(|B|^3 );

eA+B^ = I + (A + B) +

(A + B)^2 + O(|A + B|^3 ).

It follows that

e

(^12) A eB^ e

(^12) A

I +

A +

A^2

I + B +

B^2

I +

A +

A^2

+ O(|A|^3 + |B|^3 )

= I +

A + B +

A^2 +

AB +

BA +

B^2 + O(|A|^3 + |B|^3 )

= I + A + B +

(A^2 + AB + BA + B^2 ) + O(|A|^3 + |B|^3 )

= eA+B^ + O(|A|^3 + |B|^3 ),

as desired.

  1. Let

A =

− 2 ǫ 1 0 −ǫ

, x 0 =

Let x(t) solve xt = Ax, x(0) = x 0. Find max 0 ≤t<∞ |x(t)|.

Solution The general solution is easily found to be

x(t) = c 1

e−^2 ǫt^ + c 2

ǫ

e−ǫt.

With the initial condition x(0) = x 0 , we find that

c 1 = −

ǫ , c 2 =

ǫ

giving x(t) =

ǫ

e−ǫt

1 − e−ǫt ǫ

From the above we can easily deduce that

max |x(t)| ≥ |x(1/ǫ)| ∈ O(1/ǫ).

  1. Let M be a real 2 × 2 matrix with eigenvalues ±i, and consider the ODE

Ut = M U.

Show the orbits in the phase plane are ellipses. Hint: Write M = C−^1 ΛC with Λ = diag(i, −i). Consider V = CU. Find an ODE for V and show that its orbits are circles. Solution As per the hint, we write M = C−^1 ΛC and set V = CU , so that

Vt = CUt = CM U = ΛCU = ΛV.

The solution to this (decoupled) ODE is

V (t) =

c 1 eit c 2 e−it

for some c 1 , c 2 ∈ C. It follows that the real and imaginary parts of each component of U = C−^1 V is a linear combination of cos t and sin t, hence the orbits of Ut = M U are ellipses.

  1. Consider the ODE (^) ( u v

t

u v

Find and classify its stationary points. Solution Let A =

A is nonsingular (det A = 3 6 = 0), so

)T

is the only stationary point for the ODE. The eigenvalues of A are the roots of

pA(λ) = det(λI − A) = λ^2 + 3,

giving eigenvalues λ± = ±i

  1. It follows that

)T

is a center.