assignment work sheet, Exercises of Probability and Statistics

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MUSTUFA KAMIL R/0905/08 G-5
Adama Science and Technology University
School of Electrical Engineering and Computing
Computer Science and Engineering Program
Probability Assignment 1
1. A six-sided die is loaded in a way that each even face is twice a likely a
each odd face. All even faces are equally likely, a are all odd faces.
Construct a probabilistic model for a single roll of this die and find the
probability that the outcome is less than 4.
Solution :-
We first determine the probabilities of the six possible outcomes.
Let a = P(1) = P(3) = P(5) and b = P(2) = P(4) = P(6).
We are given that b = 2a.
By the additivity and normalization axioms,
3a + 3b = 1
3a + 3(2a) = 1
9a = 1
a = 1/9
b = 2a
b = 2(1/9)
b = 2/9, and
P(1,2, 3) = P(1) + P(2) + P(3) = 1/9 + 1/9 + 2/9 = 4/9.
2. We roll two fair 6-sided dice. Each one of the 36 possible outcomes is
assumed to be equally likely.
(a) Find the probability that doubles are rolled.
(b) Given that the roll results in a sum of 4 or less, find the conditional
probability that doubles are rolled.
(c) Find the probability that at least one die roll is a 6.
(d) Given that the two dice land on different numbers, find the
conditional probability that at least one die roll is a 6.
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MUSTUFA KAMIL R/09 0 5/ 08 G- 5

Adama Science and Technology University

School of Electrical Engineering and Computing

Computer Science and Engineering Program

Probability Assignment 1

1. A six-sided die is loaded in a way that each even face is twice a likely a

each odd face. All even faces are equally likely, a are all odd faces.

Construct a probabilistic model for a single roll of this die and find the

probability that the outcome is less than 4.

Solution :-

We first determine the probabilities of the six possible outcomes.

Let a = P( 1 ) = P( 3 ) = P( 5 ) and b = P( 2 ) = P( 4 ) = P( 6 ).

We are given that b = 2a.

By the additivity and normalization axioms,

3 a + 3b = 1

3 a + 3(2a) = 1

9 a = 1

a = 1/ 9

b = 2a

b = 2 (1/ 9 )

b = 2/9, and

P( 1 , 2 , 3 ) = P( 1 ) + P( 2 ) + P( 3 ) = 1/9 + 1/ 9 + 2/9 = 4 / 9.

2. We roll two fair 6-sided dice. Each one of the 36 possible outcomes is

assumed to be equally likely.

(a) Find the probability that doubles are rolled.

(b) Given that the roll results in a sum of 4 or less, find the conditional

probability that doubles are rolled.

(c) Find the probability that at least one die roll is a 6.

(d) Given that the two dice land on different numbers, find the

conditional probability that at least one die roll is a 6.

MUSTUFA KAMIL R/09 0 5/ 08 G- 5

Solution :-

a. Each possible outcome has probability 1/36. There are 6 possible outcomes that are

doubles, so the probability of doubles is 6/36 = 1/6.

b. The conditioning event (sum is 4 or less) consists of the 6 outcomes

{(1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (3, 1) }, 2 of which are doubles, so the conditional

probability of doubles is 2/6 = 1/3.

c.

There are 11 possible outcomes with at least one 6, namely,{ (6, 6), (6, i), and (i, 6)},

for i = 1 to 5. Thus, the probability that at least one die is a 6 is 11/36.

d. There are 30 possible outcomes where the dice land on different numbers. Out of these, there are 10 outcomes in which at least one of the rolls is a 6. Thus, the desired

conditional probability is 10/30 = 1/3.