Atomic Structure and Periodic Trends, Exercises of Chemistry

The concepts of atomic structure and periodic trends, focusing on the relationship between sodium and chlorine. It discusses the differences in atomic radius, ionic charge, ionization energy, and electron affinity between these two elements. The document also includes practice problems that reinforce the understanding of these principles. The content covers key topics in chemistry, such as the periodic table, atomic properties, and ionic bonding. This information could be useful for students studying general chemistry, inorganic chemistry, or related fields at the university level. A solid foundation for understanding the fundamental behavior of atoms and how they interact, which is essential for further studies in chemistry and related sciences.

Typology: Exercises

2022/2023

Uploaded on 02/27/2023

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Answers to 5-3 Apply: Two Trendy Elements
1. Sodium and Chlorine are in the same period but sodium has a much bigger
radius than Chlorine because it has a smaller nuclear charge (number of
protons) pulling on the electrons.
2. Na would have a +1 charge because it will lose the only electron it has in the
3rd energy level. By doing this it will obtain the noble gas configuration of Ne.
Chlorine is only one electron shy of having a completely filled sublevel and
therefore will take an electron to form a -1 charge thus obtaining the noble
gas configuration equal to Ar.
3. The I.E. for sodium is much lower than the I.E. for chlorine because it is easier
to remove an electron from a sublevel when there are fewer electrons in the
outer level.
4. Chlorine has a much higher electron affinity than sodium because chlorine is
only one electron away from forming noble gas electron configuration.
5. (can’t draw on the computer) For Na, remove the electron from the outer
level representing just the core electrons. For Cl, add an electron to the outer
layer and make the third level a little bit bigger.
6. The Na ion is now smaller than the Cl ion because when metals lose electrons
their size gets smaller and when non-metals gain electrons their size gets
bigger.
5-3 Practice Problems
1. a. Cl 6. Rubidium atom
b. Cl
7. Bromine atom
2. a. Se
b. S 8. Lithium ion
3. a. La 9. Tellurium ion
b. La
10. a. Al
4. a. Cr b. P
b. Cr
5. a. N
b. As

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Answers to 5-3 Apply: Two Trendy Elements

  1. Sodium and Chlorine are in the same period but sodium has a much bigger radius than Chlorine because it has a smaller nuclear charge (number of protons) pulling on the electrons.
  2. Na would have a +1 charge because it will lose the only electron it has in the 3 rd^ energy level. By doing this it will obtain the noble gas configuration of Ne. Chlorine is only one electron shy of having a completely filled sublevel and therefore will take an electron to form a -1 charge thus obtaining the noble gas configuration equal to Ar.
  3. The I.E. for sodium is much lower than the I.E. for chlorine because it is easier to remove an electron from a sublevel when there are fewer electrons in the outer level.
  4. Chlorine has a much higher electron affinity than sodium because chlorine is only one electron away from forming noble gas electron configuration.
  5. (can’t draw on the computer) For Na, remove the electron from the outer level representing just the core electrons. For Cl, add an electron to the outer layer and make the third level a little bit bigger.
  6. The Na ion is now smaller than the Cl ion because when metals lose electrons their size gets smaller and when non-metals gain electrons their size gets bigger. 5-3 Practice Problems
  7. a. Cl 6. Rubidium atom b. Cl
  8. Bromine atom
  9. a. Se b. S 8. Lithium ion
  10. a. La 9. Tellurium ion b. La
  11. a. Al
  12. a. Cr b. P b. Cr
  13. a. N b. As