Atomic Theory Review, Quizzes of Chemistry

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L. Farrell – Chemistry 11 – Atomic The ory Review – Answers - Page 1 of 7
Atomic Theory Review
Fill in the Blank
mass number
1. The number of protons and neutrons in the nucleus of an atom is the __.
isotopes
2. Atoms possessing the same number of protons but a different number of neutrons are __.
ground state
3. The lowest energy state of an electron in an atom is the __.
nucleon
4. A particle found in the nucleus is called a(n) __.
atomic number
5. The number of protons in an atom is represented by the __.
protons
6. The identity of an element is determined by the number of __ present.
orbital
7. The volume and shape of the region in space where you would be most likely to locate an electron is a(n) __.
diagonal rule
8. A system for predicting the order of filling energy sublevels with electrons is the __.
orbital
9. The letters s, p, d, or f, are used to designate a particular __ within an energy level.
Multiple Choice
D
1. Of the following assumptions or results of Dalton’s
atomic theory, the only one that remains essentially
correct in most cases is
A) All atoms of an element are identical in mass.
B) Atoms are indivisible and indestructible.
C) Oxygen has an atomic weight of 7.
D) Atoms of elements combine in the ratios of small
whole numbers to form compounds.
A
2. Rutherford’s experiments on the scattering of
particles by thin metal foils established that
A) The mass and charge of an atom are concentrated
in a nucleus.
B) Electrons are fundamental particles of all matter.
C) All electrons have the same charge.
D) Atoms are electrically neutral.
C
3. The species that has the same number of electrons as
32
16
S is
A)
35
17
Cl
-
B)
34
16
S
+
C)
40
18
Ar
2+
D)
35
16
S
2-
C
4. All of the following masses are possible for an individual
carbon atom except one. That impossible one is
A) 12.000 00 amu C) 12.011 15 amu
B) 13.003 35 amu D) 14.003 24 amu
D
5. There are two principal isotopes of indium (atomic
weight = 114.82). One of these,
113
49
In, has an atomic mass
of 112.9043 amu. The second isotope is most likely to be
A)
111
49
In B)
112
49
In C)
114
49
In D)
115
49
In
Short Answer
1. Compare the similarities and differences between Rutherford’s and Bohr’s theories of the atom.
Both Rutherford’s and Bohr’s models of the atom have a nucleus, which is an
extremely small, dense region in the center of the atom, that contains most of
the atom’s mass and all of its positive charge. Both models have negatively
charged electrons orbiting the nucleus. The difference is that Bohr’s model
specifies the exact path of the electrons. According to Bohr, electrons travel in
energy levels. The energy of the electron is quantized the electron can only
exist at specific allowable energy levels. Rutherford’s model did not specify the
path taken by the electron.
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Atomic Theory Review

Fill in the Blank

mass number 1. The number of protons and neutrons in the nucleus of an atom is the __.

isotopes 2. Atoms possessing the same number of protons but a different number of neutrons are __.

ground state 3. The lowest energy state of an electron in an atom is the __.

nucleon 4. A particle found in the nucleus is called a(n) __.

atomic number 5. The number of protons in an atom is represented by the __.

protons 6. The identity of an element is determined by the number of __ present.

orbital 7. The volume and shape of the region in space where you would be most likely to locate an electron is a(n) __.

diagonal rule 8. A system for predicting the order of filling energy sublevels with electrons is the __.

orbital 9. The letters s, p, d, or f, are used to designate a particular __ within an energy level.

Multiple Choice

D 1. Of the following assumptions or results of Dalton’s atomic theory, the only one that remains essentially correct in most cases is A) All atoms of an element are identical in mass. B) Atoms are indivisible and indestructible. C) Oxygen has an atomic weight of 7. D) Atoms of elements combine in the ratios of small whole numbers to form compounds. A 2. Rutherford’s experiments on the scattering of 4 particles by thin metal foils established that A) The mass and charge of an atom are concentrated in a nucleus. B) Electrons are fundamental particles of all matter. C) All electrons have the same charge. D) Atoms are electrically neutral.

C 3. The species that has the same number of electrons as (^3216) S is A) 3517 Cl-^ B) 3416 S+^ C) 4018 Ar2+^ D) 3516 S2- C 4. All of the following masses are possible for an individual carbon atom except one. That impossible one is A) 12.000 00 amu C) 12.011 15 amu B) 13.003 35 amu D) 14.003 24 amu D 5. There are two principal isotopes of indium (atomic weight = 114.82). One of these, 11349 In, has an atomic mass of 112.9043 amu. The second isotope is most likely to be A) 11149 In B) 11249 In C) 11449 In D) 11549 In

Short Answer

  1. Compare the similarities and differences between Rutherford’s and Bohr’s theories of the atom.

Both Rutherford’s and Bohr’s models of the atom have a nucleus, which is an extremely small, dense region in the center of the atom, that contains most of the atom’s mass and all of its positive charge. Both models have negatively charged electrons orbiting the nucleus. The difference is that Bohr’s model specifies the exact path of the electrons. According to Bohr, electrons travel in energy levels. The energy of the electron is quantized – the electron can only exist at specific allowable energy levels. Rutherford’s model did not specify the path taken by the electron.

  1. Compare the similarities and differences between Bohr’s model and the Quantum Mechanical model of the atom.

Both Bohr’s model and the Quantum Mechanical model of the atom have a nucleus, which is an extremely small, dense region in the center of the atom that contains most of the atom’s mass and all of its positive charge. Both models have electrons whose energy is quantized. Bohr thought that he could describe the exact path taken by an electron, but the Quantum Mechanical model states that we cannot specify the exact path of the electron, only the region where an electron is most likely to be found. This region is called an orbital. Additionally, there is more than one type of orbital.

  1. Draw energy level diagrams, and write electron configurations and energy level populations for lead and rutherfordium.

Lead

↑ ↑ 6p ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ 5d (^) ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ 4f 6s (^) ↑↓ ↑↓ ↑↓ 5p ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ 4d 5s ↑↓ ↑↓ ↑↓ 4p ↑↓ (^) ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ 3d 4s ↑↓ ↑↓ (^) ↑↓ ↑↓ 3p

3s Pb

↑↓ 2p 2s

1s

Electronic Configuration: 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^6 6s^2 4f^14 5d^10 6p^2 Energy Level Population: 2,8,18,32,18,

  1. Complete the following table. Symbol Atomic Number Mass Number Protons Neutrons Electrons (^3818) Ar (^18 38 18 20 )

(^188) O (^8 18 8 10 )

(^3616) S2– (^16 36 16 20 )

X– 17 37 17 20 18

Mg2+^12 26 12 14

  1. Calculate the average atomic mass of nickel that has five naturally occurring isotopes: 67.88% nickel-58 (mass = 57.9353 u), 26.23% nickel 60 (mass = 58.9332 u), 1.19% nickel-61 (mass = 60.9310 u), 3.66% nickel-62 (mass = 61.9283 u), and 1.08% nickel- (mass = 63.9280 u). Mass = (0.6788)(57.9353) + (0.2623)(58.9332) + (0.0119)(60.9310) + (0.0366)(61.9283) + (0.0108)(63.9280)

Mass = 39.33 + 15.46 + 0.725 + 2.27 + 0.

Mass = 58.47 u

  1. There are two principal isotopes of silver, 10747 Ag and 10947 Ag. The atomic weight of naturally occurring silver is 107.87, with 51.82% of the atoms being 10747 Ag. The mass of an atom of 10747 Ag is 106.9 amu. What is the mass, in amu, of an atom of 10947 Ag?

107 47 Ag^

109 47 Ag^ Average 106.9 amu x amu 107.87 amu 51.82% 100% – 51.82% = 48.18%

(0.5812)(106.9) + (0.4818)x = 107. 55.396 + 0.4818x = 107. 0.4818x = 52. x = 108.

109 47 Ag = 108.9 amu

  1. Naturally occurring indium consists of two isotopes: indium-113 with an atomic mass of 112.9043 u, and indium-115 with an atomic mass of 114.9041 u. If the average atomic mass of indium is 114.82 u, calculate the percentage of each isotope of naturally occurring indium. Indium-113 Indium-115 Avg

112.9043 u 114.9041 u 114.82 u

x y 100%

Equation 1: 112.9043x + 114.9041y = 114. Equation 2: x + y = 1 Elimination Equation 1: 112.9043x + 114.9041y = 114. Equation 2: -112.9043x – 112.9043y = -112. 1.9998y = 1. y = 0. x + y = 1 x = 1 – y x = 1 – 0.9579 x = 0.

Indium-113 = 4.21% Indium-115 = 95.79%

*9. Give all possible sets of quantum numbers for an electron in a 4f orbital.

n l m s