Linear Algebra: Systems of Equations, Row Reduction, and Solutions, Exams of Linear Algebra

These are the notes of Solved Exam of Linear Algebra which includes General Solution, Linear Systems, Homogeneous System, Solution Sets, Particular Solution, Nonhomogeneous, Coefficient Matrix etc. Key important points are: Augmented Matrix, Linear System, Values, Consistent, Corresponding, Reduction Algorithm, System is Consistent, General, Solution Set, Linear Combination

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2012/2013

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MT210 MIDTERM 1 SAMPLE 2
ILKER S. YUCE
FEBRUARY 19, 2011
QUESTION 1. SYSTEMS OF LINEAR EQUATIONS
The augmented matrix of a linear system has the form
[a1 1
2a1 1 ]
Determine the values of afor which the linear system is consistent.
ANSWER
We apply row-reduction algorithm to the augmented matrix corresponding to the system given above:
Assume that a= 0, then we get
[a1 1
2a1 1 ](2/a)R1+R2ÏR2
//[a1 1
0a12
a12
a].
By Theorem 2, we know that the system above is consistent if and only if there is no row of the form
[0 0 1]. Therefore, we must have either a12
a= 0 or we must have a12
a= 0 and 12
a= 0. Let
us solve the equation a12
a= 0 or (a+ 1)(a2) = 0 or a=1or a= 2.
We need to examine the case a= 0. If a= 0, then we have x2= 1 and x1= 1. So, the system is
consistent. Note that the case a= 2 also gives a consistent system. Finally, we conclude that the system
above is consistent if and only if a=1.
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MT210 MIDTERM 1 SAMPLE 2

ILKER S. YUCE

FEBRUARY 19, 2011

QUESTION 1. SYSTEMS OF LINEAR EQUATIONS

The augmented matrix of a linear system has the form

[ a 1 1 2 a − 1 1

]

Determine the values of a for which the linear system is consistent.

ANSWER

We apply row-reduction algorithm to the augmented matrix corresponding to the system given above: Assume that a ̸ = 0, then we get

[ a 1 1 2 a − 1 1

]

( 2 /a ) R 1 + R (^2) // ÏR 2

[

a 1 1 0 a − 1 ^2 a 1 ^2 a

]

By Theorem 2, we know that the system above is consistent if and only if there is no row of the form [0 0 1]. Therefore, we must have either a − 1 ^2 a ̸ = 0 or we must have a − 1 (^) a^2 = 0 and 1 ^2 a = 0. Let us solve the equation a − 1 ^2 a = 0 or ( a + 1)( a − 2) = 0 or a = 1 or a = 2. We need to examine the case a = 0. If a = 0, then we have x 2 = 1 and x 1 = 1. So, the system is consistent. Note that the case a = 2 also gives a consistent system. Finally, we conclude that the system above is consistent if and only if a ̸ = 1.

QUESTION 2. ROW REDUCTION AND ECHELON FORMS

Write the augmented matrix corresponding the system below:

x 1 6 x 2 4 x 3 = 5 2 x 1 10 x 2 9 x 3 = 4 −x 1 + 6 x 2 + 5 x 3 = 3_._

Solve the system by applying the row reduction algorithm. If the system is consistent, find the general solution set.

ANSWER

The augmented matrix corresponding to the given system is

 

We need to reduce the augmented matrix

 

 −^2 R^1 + R^2 ÏR^2

R 1 + R 3 ÏR 3

 3 R^2 + R^1 ÏR^1

R 3 + R 2 ↔R 2

 7 R^3 + R^1 ↔R^1

(1 / 2) R 2 ↔R 2

G.S. =

x 1 = 1 x 2 = 2 x 3 = 2

QUESTION 4. THE MATRIX EQUATION Ax=b

A.) Write the given matrix equation below as system of linear equations:  

x 1 x 2 x 3

ANSWER

x 1 + x 2 + x 3 = 1 x 1 − x 2 2 x 3 = 5 2 x 1 + 4 x 3 = 5

B.) Solve the system and write the general solution.

ANSWER

We need to reduce the augmented matrix that represents the given system (I’ll leave the details to you)  

G.S. =

x 1 = 7 / 2 x 2 = 15 / 2 x 3 = 3

QUESTION 5. SOLUTION SETS OF LINEAR SYSTEMS

A. Solve the nonhomogeneous system Ax=b and write the solution in parametric vector form where

A =

 (^) and b =

ANSWER

 R^2 + R^3 ÏR^3

2 R 2 + R 1 ÏR 1

 R^1 + R^3 ÏR^3

3 R 3 + R 1 ↔R 1

 −^2 R^3 + R^2 ÏR^2

2 R 1 + R 3 ↔R 3 ,−R 1 + R 2 ÏR 2

G.S. =

x 1 = 2 x 2 = 7 x 3 = 4

B. Using the parametric vector form of the solution set in part A., determine a particular solution p.

ANSWER

We see that p =

 (^) is a particular solution.

C. Write the general solution for the system A x = 0 in parametric vector form.

ANSWER

The parametric vector form of homogeneous part of the general solution set is

vh =