Given Matrix - Linear Algebra - Solved Exam, Exams of Linear Algebra

These are the notes of Solved Exam of Linear Algebra which includes General Solution, Linear Systems, Homogeneous System, Solution Sets, Particular Solution, Nonhomogeneous, Coefficient Matrix etc. Key important points are: Given Matrix, Properties, Determinants, Determinant, Inverse, Upper Triangular Matrix, Operations, Matrix Is Invertible, Linear System, Linear Transformations

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MT210 TEST 3 SAMPLE 1
ILKER S. YUCE
APRIL 19, 2011
QUESTION 1. THE PROPERTIES OF DETERMINANTS
Find the determinant of the matrix below. Specify whether the matrix has an inverse without trying to
compute the inverse.
2222
2 2 3 0
22 2 0
1131
ANSWER
Row reduce the given matrix to an upper triangular matrix and keep track of the operations you perform:
1·R1+R2R2,1·R1+R3R3,1
2·R1+R4R4. Then perform 2·R2+R4R4and R2R3.
2222
2 2 3 0
22 2 0
1131
2222
04 0 2
0 0 1 2
0 0 0 4
Note that there is only one switch. As a result, the determinant is -32 which is not 0. Therefore, the given
matrix is invertible.
1
pf3
pf4
pf5

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MT210 TEST 3 SAMPLE 1

ILKER S. YUCE

APRIL 19, 2011

QUESTION 1. THE PROPERTIES OF DETERMINANTS

Find the determinant of the matrix below. Specify whether the matrix has an inverse without trying to

compute the inverse. 

ANSWER

Row reduce the given matrix to an upper triangular matrix and keep track of the operations you perform:

1 · R 1 + R 2 ↔ R 2 , 1 · R 1 + R 3 ↔ R 3 ,

1 2

· R 1 + R 4 ↔ R 4. Then perform 2 · R 2 + R 4 ↔ R 4 and R 2 ↔ R 3.

Note that there is only one switch. As a result, the determinant is -32 which is not 0. Therefore, the given

matrix is invertible.

QUESTION 2. CRAMER’S RULE, VOLUME, AND LINEAR TRANSFORMATIONS

Solve the linear system using Cramer’s Rule:

2 x 1 + 3 x 2 − x 3 = 2

3 x 1 2 x 2 + x 3 = 1

5 x 1 4 x 2 + 2 x 3 = 3

ANSWER

x 1 =

x 2 =

x 3 =

The solution is ( 5 / 11 , 36 / 11 , 76 / 11).

QUESTION 4. LINEARLY INDEPENDENT SETS; BASES

Let v ⃗ 1 = (1 , 1 , 1), v ⃗ 2 = (1 , 2 , 3) and v⃗ (^) 3 = (1 , 1 , 2).

a. Show that the vectors above are linearly independent.

ANSWER

There are three pivot positions and three vectors. Therefore, v⃗ (^) 1 ,⃗v (^) 2 v,⃗ (^) 3 are linearly independent.

b. Find the unique scalars(weights) c 2 , c 2 , c 3 such that v⃗ = (2 , 1 , 3) can be written as v ⃗ = cv 1 2 + cv 2 2 + cv 3 3.

ANSWER

Thus, we get c 1 = 0, c 2 = 1 , and c 3 = 3 or v⃗ = 0 ·v⃗ (^) 1 + ( 1) v ⃗ 2 + 3 v⃗ (^) 3.

QUESTION 5. RANK

Define a linear transformation T : P 2 Ï P 2 by T (p( x )) = p ( x ).

a. Describe the range of T

ANSWER

Consider the vector space P 2 with the standard basis { 1 , x, x 2 }. Then, the transformation T is given as

T ( ax 2

  • bx + c ) = 2 ax + b = 2 a ( x ) + b (1). In other words, a basis for the range of T is C = { 1 , x}.

Consequently,

Range of T = {s + tx : s, t ∈ R }.

b. Find dim ( R ( T )).

ANSWER

Since the basis C has 2 elements, dim ( R ( T )) = 2.

c. Find dim ( N ( T )).

ANSWER

By the RANK THEOREM, we have dim ( N ( T )) + dim ( R ( T )) = dim P 2 , i.e., dim ( N ( T )) = 3 2 = 1.