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Topics covered in this course include fluid properties, fluid statics, fluid kinematics, control volume analysis, dimensional analysis, internal flows, differential analysis, external flows CFD, compressible flow and turbomachinery. Key words for this lecture are: Bernoulli Equation, Water Draining from a Tank, Energy Grade Line and Hydraulic Grade Line, Head Form of the Energy Equation, Atmospheric Pressure, Conservation of Energy Equation, Grade Lines in a Fluid Flow, Venturi Tube, Airplane Wi
Typology: Exercises
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Today, we will :
Example – Water draining from a tank
Given : Water drains by gravity from a tank exposed to atmospheric pressure. The vertical distance
from the pipe outlet to the surface of the water in the tank is Δ z = 0.500 m. The irreversible head
losses in the piping system (due to friction in the pipe, losses through the valve, elbow, etc.) are
estimated as h L
= 0.400 m of equivalent water column height. Note : You will learn how to calculate
the irreversible head losses associated with piping systems on your own in Chapter 8.
Open valve
V 2
Δ z
To do : Calculate the average velocity at the outlet, V 2
.
Solution :
From previous lecture…use the head form of the conservation of energy equation:
2 2
1 1 2 2
1 1 pump,u 2 2 turbine, e
1 2
L
z h z h h
g g g g
D. The Bernoulli Equation
Begin with the head form of the conservation of energy equation along a streamline:
2 2
1 1 2 2
1 pump,u 2 turbine, e
1 2
L
z h z h h
At any location in the
duct, the difference
between EGL and HGL
is V
2
/(2 g ).
At point 0, HGL = EGL inside the
tank, since the fluid is at rest ( V = 0).
Neither EGL or HGL can rise above
this value unless work is added to the
flow (e.g., with a pump).
Since the jet exits at atmospheric
pressure at the outlet of the pipe,
P 3
= P atm
, and HGL is equal to
the height of the free surface of
the liquid.
EGL continually falls due to
irreversible losses, but HGL can
rise or fall. Overall, however,
HGL also must fall. In fact, HGL
can never rise above EGL.
FIGURE 5-