Binomial Coefficients - Homework Assignment | MATH 201, Assignments of Mathematics

Material Type: Assignment; Class: INTRO TO PROOFS; Subject: MATHEMATICS; University: Iowa State University; Term: Spring 2009;

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MATH 201 §A: BINOMIAL COEFFICIENTS
DUE FRIDAY 27 MAR 2009
Definition 1. For every integer n0and every integer k, the bi-
nomial coefficient n
kis the coefficient of xkin the expansion of the
binomial power (1 + x)n.
The binomial expansion is, according to this definition,
(1) (1 + x)n=
n
X
k=0 n
kxk.
Note that since (1 + x)0= 1 we have 0
0= 1. We also have
(2) n
k= 0 whenever k < 0 or k > n.
Our first theorem says that a table of binomial coefficients can be
computed one row at a time by the “Pascal triangle” rule.
Theorem 1. For every n1and every k, the binomial coefficients
satisfy
(3) n
k=n1
k1+n1
k
Proof. Let n1 and write
(4) (1 + x)n= (1 + x)·(1 + x)n1= (1 + x)(1 + · · · +xn1).
The coefficient of x0is 1 on both sides of this equation, so
n
0=n1
0=n1
1+n1
0
by Equation (2); this proves Equation (3) in the case k= 0. The
coefficient of xnis 1 also, proving the formula in the case k=n.
For the coefficient of xkwith 0 < k < n, rewrite Equation (4):
(5)
(1+x)n= (1+x)1 + · · · +n1
k1xk1+n1
kxk+· · · +xn1.
The coefficient of xkon the left side of Equation (5) is n
k. On the
right side we find two ways to produce an xkterm: either the 1 from
1
pf2

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MATH 201 §A: BINOMIAL COEFFICIENTS

DUE FRIDAY 27 MAR 2009

Definition 1. For every integer n ≥ 0 and every integer k, the bi-

nomial coefficient

n k

is the coefficient of xk^ in the expansion of the

binomial power (1 + x)n.

The binomial expansion is, according to this definition,

(1) (1 + x)n^ =

∑^ n

k=

n k

xk.

Note that since (1 + x)^0 = 1 we have

0

= 1. We also have

(2)

n k

= 0 whenever k < 0 or k > n.

Our first theorem says that a table of binomial coefficients can be computed one row at a time by the “Pascal triangle” rule.

Theorem 1. For every n ≥ 1 and every k, the binomial coefficients satisfy

(3)

n k

n − 1 k − 1

n − 1 k

Proof. Let n ≥ 1 and write

(4) (1 + x)n^ = (1 + x) · (1 + x)n−^1 = (1 + x)(1 + · · · + xn−^1 ).

The coefficient of x^0 is 1 on both sides of this equation, so ( n 0

n − 1 0

n − 1 − 1

n − 1 0

by Equation (2); this proves Equation (3) in the case k = 0. The coefficient of xn^ is 1 also, proving the formula in the case k = n. For the coefficient of xk^ with 0 < k < n, rewrite Equation (4): (5)

(1+x)n^ = (1+x)

n − 1 k − 1

xk−^1 +

n − 1 k

xk^ + · · · + xn−^1

The coefficient of xk^ on the left side of Equation (5) is

(n k

. On the right side we find two ways to produce an xk^ term: either the 1 from 1

(1 + x) multiplies the term

(n− 1 k

xk, or the x from (1 + x) multiplies the term

(n− 1 k− 1

xk−^1. Thus the coefficient of xk^ on the right hand side

is

(n− 1 k− 1

(n− 1 k

Binomial coefficients can be used to enumerate subsets of finite sets.

Theorem 2. The binomial coefficient

(n k

is the number of k-element subsets of an n-element set.

Proof. In-class Exercise. Use induction on n. 

Consult the proof of Theorem 6.15 in the textbook. You may also want to use the following Lemma.

Lemma 1. Let A be an n-element set and B = A ∪ {x} an n + 1- element set. If S is a k-element subset of B, then either S ⊆ A, or x ∈ S (so S − {x} has k − 1 elements) and S − {x} ⊆ A.

Proof. Since B consists of A together with one additional element x, every subset of B that does not contain x is a subset of A. Moreover, if a subset of B does contain x, then all the other elements of that subset belong to A. 

Theorem 2 provides an alternate proof of the textbook’s Theorem 6.15.

Corollary. The number of subsets of an n-element set is 2 n.

Proof. By Theorem 2 and the binomial expansion Equation (1), the number of subsets of an n-element set is ∑^ n

k=

n k

= (1 + 1)n^ = 2n.

The expression

(n k

is pronounced “binomial n, k.” Because of The- orem 2 the symbol is often read as “n choose k.” Homework assignment: Theorem 3 gives the formula that expresses binomial coefficients in terms of factorials. Use induction to prove Theorem 3. You will need the convention that 0! = 1.

Theorem 3. The binomial coefficients are given by

(6)

n k

n! k!(n − k)! For the proof, use Theorem 1 to show that the set S = {n ∈ N ∪ { 0 } : Equation (6) holds for 0 ≤ k ≤ n}

is inductive.