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Solutions to mathematics exercises from millersville university. The first exercise involves finding the area between the curves y = x^3 - 2x^2 and y = x^2 by integrating the difference of their functions. The second exercise calculates the volume of a triangular prism representing the attic, given its base area and length.
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Millersville University Name Answer Key
Department of Mathematics
MATH 211, Homework 02
January 30, 2006
Sketch and find the are of the region determined by the intersection of the curves:
y = x
3 โ 2 x
2 , y = x
2 .
x
y
x
y
The curves intersect when the following equation is satisfied:
x
3 โ 2 x
2 = x
2
x
3 โ 3 x
2 = 0
x
2 (x โ 3) =
x = 0 or x = 3
Thus the area between the curves is
0
x
2 โ
x
3 โ 2 x
2
dx
0
โx
3
2 dx
x
4
3
3
0
The diagram below illustrates a triangular cross section of the attic.
height = 10 ft
base = 30 ft
The cross sectional area of the attic is the constant
bh =
The length of the attic is 60 feet and thus the volume of the attic is
60
0
A dx =
60
0
150 dx = (60)(150) = 9000 ft
3 .