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AG Calc Chapter 14 Review Names VS) ee ae 1. Find 2 other pairs of polar coordinates for (5, 110°), one with a positive r and the other with a negative r. Ie )) LES: 250) WG ), G, ua FO) y) | 2. Draw a sketch of the following: a) r=2+4sin0 b) yr =3+3c0s0 3. Convert the following equations to Cartesian. a) r=4sin8@ (7-= uysine 4—6sin@ : X= + Cos(O) : VL 4-WSMO)= 4 (= ge? I uy - or sine= 1 Vx ge ; yt ty Ly? by- “© OO A O=8 aAye-17 Vy Ce, (Pa 14 QO aC =) 4 +Y4(Y 2)2 = L- UX 24y% = Gy~ + cenrer= (6,2) "- Ly 2( x24) = (s+ (oY) ~ : 4. Convert the following equations to Polar. lox a+ Joy* = =a |e + 12yt3oy" 5. = ' ——— < a) Bx=y" b) x +y°-3y=0 [I> x2 20)*-I2y- |= 0 s 3rcosp = V7SIDO (v cos &)* (rsin©)* - 3(rsine) r2coh$*O+ V*SI0 “6 - SrSI"DO (2 (cos *8 + Sin2@) -—2°T Sno => V(r-3SI00 1 yr ~ 3rSine . Y= 3506 5. Convert the following parametric equations to Cartesian. Y=O x=5-31 x=5cos! === +=—=«—CS b) = a. y=1+2 — 3s1n/ oa | Sas dae A | x cost Q=siot| 2X | 6. Alex hits a ball 3 feet above the ground with an initial velocity of 115 ft/sec. The ball leaves the bat at a 35° angle with the horizontal and heads towards a 25 foot wall 380 feet from home plate. a) Does the ball clear the fence b) Ifso, by how much does it cle —_ s rey) )° f>>¢ Z > Or, Fm ar the wall. = ye ((SCOoSs / a5 )e VeEVCO! Motioc i + IS cim(3S74 sel Y : 4\ yer 254+ af S60= [1760S C35°)4 tx 4,04 A= ~lyt+4a4 Sow (as)+ +3 oa eee §, 24 d) DoeSnot Cea ball in problem 6, there is a split-second 6 ft/sec gust of horizontal 280 (I5coSC3S)+ +Gt abo= t (MS COS(3S)t 6) W eae : = 93.0S¢ pots por Wea 7. Suppose that the moment Alex hit the wind in the direction of the ball. a) Does the ball clear the fence and if so by how much. ~~ @ 2. 8 How fast should a horizontal wind gust be in order for the ball to land on top of the wall? 2s 34+ 15 SOGSI4 — Mba > - O= =29 (+ (YS. SI CISIFI [OT > our IS W0d7Onta ( X* 3.756 Q)= +.32 f+) 0¢ m= [ISLS C8H)T *0O¥ X BFO = iS cos( 35+) + ut 26.145= “Wl 3.870) 
