Circuit Theorems-Electrical Circuit Analysis-Lecture Slides, Slides of Electrical Circuit Analysis

This lecture was delivered for Electrical Circuit Analysis course by Prof. Dhananjay Malhotra at Shree Ram Swarup College of Engineering

Typology: Slides

2011/2012

Uploaded on 07/20/2012

anuhya
anuhya 🇮🇳

4.2

(23)

115 documents

1 / 16

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
9/15/2009
1
Circuit Theorems Circuit Theorems --Chapter 4Chapter 4
41
Motivation
4
.
1
Motivation
4.2 Linearity Property
4.3 Superposition
4.4 Source Transformation
4.5
Thevenin
s Theorem
1
4.5
Thevenin s Theorem
4.6 Norton’s Theorem
4.7 Maximum Power Transfer
4.1: Motivation4.1: Motivation
Kirchoff’s laws analyze the
circuits without tampering
with its original
configuration. A major
disadvantage is that for
large complex circuit,
tedious computation is
involved.
Thevenin and Norton
theorems are applicable to
analyze the linear circuits.
The concepts of
If you are given the above
circuit, are there any other
alternative(s) to
2
What are they? And how?
•Can you work it out by
inspection?
The concepts of
superposition, source
transformation, and
maximum power transfer
are also used to make the
circuit analysis simpler.
determine.
docsity.com
pf3
pf4
pf5
pf8
pf9
pfa
pfd
pfe
pff

Partial preview of the text

Download Circuit Theorems-Electrical Circuit Analysis-Lecture Slides and more Slides Electrical Circuit Analysis in PDF only on Docsity!

Circuit TheoremsCircuit Theorems -- Chapter 4Chapter 4

4 14.1 MotivationMotivation

4.2 Linearity Property

4.3 Superposition

4.4 Source Transformation

4.5 Thevenin’s Theorem

1

4.5 Thevenin s Theorem

4.6 Norton’s Theorem

4.7 Maximum Power Transfer

4.1: Motivation4.1: Motivation

  • Kirchoff’s laws analyze the circuits without tampering with its original configuration. A major disadvantage is that for large complex circuit, tedious computation is involved.
  • Thevenin and Norton theorems are applicable to analyze the linear circuits.
  • The concepts of
    • If you are given the above circuit, are there any other alternative(s) to

2

  • What are they? And how?
  • Can you work it out by inspection?
  • The concepts of superposition, source transformation, and maximum power transfer are also used to make the circuit analysis simpler.

determine.

docsity.com

4.2: Linearity Property4.2: Linearity Property

  • It is the property of an element describing a linear relationship between cause and effect.
  • A linear circuit is one whose output is linearly related (or directly proportional) to its input.
  • Linearity is combination of both homogeneity (scaling) property and additivity property.

1. Homogeneity (scaling) property: If the input, also called

as excitation, is multiplied by a constant, then the output, also called as response, is multiplied by a constant.

v = i R → k v = k i R

2 Additivity property: The additivity property requires that the

3

2. Additivity property: The additivity property requires that the

response to a sum of inputs is the sum of response to each input applied separately.

v 1 = i 1 R and v 2 = i 2 R

→ v = (i 1 + i 2 ) R = v 1 + v 2

  • In general a circuit is linear if it is both additive and homogeneous.

4.2: Linearity Property4.2: Linearity Property

  • Note that since p=i 2 R=v 2 /R (making it quadric function rather than a linear one)rather than a linear one), the relationship between power and voltage (or current) is nonlinear.
  • Therefore, the theorems covered in this chapter are not applicable to power.

2 2 2

2 1 1 p Ri

p Ri

=

=

4

1 2

12

2 2

2 1

2 3 1 2

2 2

2

( )

p p

Ri Ri Rii

P Ri i

p Ri

≠ +

= + +

= +

docsity.com

Class Activity (5)Class Activity (5)

Practice Problem 4.2: Assume that Vo = 1V and use linearity to calculate the actual value of Vo in the circuit.

7

4.3: Superposition Theorem4.3: Superposition Theorem

  • It states that the voltage across (or current through) an element in a linear circuit is theg ) algebraic sum of the voltage across (or currents through) that element due to EACH independent source acting alone while all the others independent sources are turned off.
  • The principle of superposition helps us to analyze a linear circuit with more than one d d b l l h

8

independent source by calculating the contribution of each independent source separately.

docsity.com

4.3: Superposition Theorem4.3: Superposition Theorem

Practice Problem 4.

Using the superposition theorem, find v o in the circuit of Fig.

9

4.3: Superposition Theorem4.3: Superposition Theorem

Steps to apply superposition principle

  1. Turn off all independent sources except one source. Find the output (voltage or current) due to that active source using nodal or mesh analysis.
  2. Repeat step 1 for each of the other independent sources

10

independent sources.

  1. Find the total contribution by adding algebraically all the contributions due to the independent sources.

docsity.com

4.3: Superposition Theorem4.3: Superposition Theorem

Practice Problem 4.

Use superposition to find v x in

the circuit below.

13

Dependant source keep unchanged

4.3: Superposition Theorem4.3: Superposition Theorem

Practice Problem 4.

Use superposition to find v x in

the circuit below.

2A is discarded by open-circuit

20 Ω (^) v1 20 Ω^ v

10V is discarded by open-circuit Dependant sourcekeep unchanged

14

10 V + −^4 Ω

(a)

0.1v 1 2 A 4 Ω

(b)

0.1v 2

docsity.com

4.4: Source Transformation4.4: Source Transformation

  • An equivalent circuit is one whose v-i

characteristics are identical with the

original circuit.

  • It is the process of replacing a voltage

source v (^) S in series with a resistor R by a current source i (^) S in parallel with a resistor

R or vice versa

15

R , or vice versa.

4.4: Source Transformation4.4: Source Transformation

  • Arrow of the current source is directed toward the positive terminal of the voltage source.
  • The source transformation is not possible when R = 0 for voltage source and R = ∞ for current source.
  • • The two circuits are equivalent provided they have same voltageThe two circuits are equivalent provided they have same voltage- current relation at terminal a-b.
  • If the sources are turned off the equivalent resistance at terminal a-b in both circuits is R.

+ +

-

  • Also when the terminal a-b are short circuited, the short circuit current flowing from a to b is i (^) sc=v (^) s/R in the circuit on the left h d id d i i i h i i

16

(a) Independent source transform

(b) Dependent source transform

+ +

**- -

  • -** R

v v (^) s = isR or is = s

hand side and i (^) sc=i (^) s in the circuit on the right hand side. Thus v (^) s/R=i (^) s in order for the two circuits to be equivalent. Hence source transformation requires

docsity.com

4.5:4.5: Thevenin’sThevenin’s TheoremTheorem

MOTOVATION:

  • Often it happens that an element in a circuit is variable, usually called load, while all the other elements are fixed e.g. household outlet connected withh h ld tl t t d ith different appliance.
  • In such case each time the variable element is changed, the whole circuit has to analyzed all over again.
  • To avoid such problem, Thevenin theorem provides a technique by which the fixed part of the circuit can be replaced by an equivalent circuit

19

replaced by an equivalent circuit.

  • Thevenin theorem is very important in circuit analysis. It helps to simplify the circuit. A large circuit may be replaced by a single independent voltage source and a single resistor.

4.5:4.5: Thevenin’sThevenin’s TheoremTheorem

  • It states that a linear two-terminal circuit (Fig. a) can be replaced by an equivalent circuit (Fig. b) consisting of a voltage source VTHTH in series with a resistor RTH , where;
  • VTH is the open-circuit voltage at the terminals.
  • To get the value of RTH if there are two cases:
  • CASE 1: If the network has only independent sources, we can turn off all the independent sources. RTH is the i t i t f th t k l ki

20

input resistance of the network looking between terminals a-b.

docsity.com

Class ActivityClass Activity

Practice Problem 4.8: Using Thevenin’s theorem, find the

equivalent circuit to the left of the terminals in the circuit

shown belowshown below. Hence find i. Hence find i

21

4.54.5 Thevenin’sThevenin’s TheoremTheorem

  • CASE 2: If the network has dependent sources, we turn off all independent sources. As with the superposition, dependent sources are not to be turned off because they are controlled by circuit variables.
  • We apply a voltage vo at the terminals a and b and determine the resulting current i (^) o. Then Rth=vo /i (^) o.
  • Alternatively we may insert a current source i (^) o at terminals a-b as shown in the fig(b) and find terminal voltage v

22

the fig(b) and find terminal voltage vo. Again Rth=vo /i (^) o.

  • Either of the two approaches will give the same results. For example we may use vo =1 v or i (^) o =1 A.

docsity.com

Class ActivityClass Activity

Example 4.10: Evaluate the solution by connecting a 9 Ω

resistor and a 10 V source across the output terminals of the

original circuit and then across the Thevenin equivalent

circuitcircuit

25

Class ActivityClass Activity

Practice Problem 4.10: Obtain the Thevenin equivalent

circuit.

26

docsity.com

4.6 Norton’s Theorem (1)4.6 Norton’s Theorem (1)

It states that a linear two-terminal circuit can be replaced by an equivalent circuit of a current source IN in parallel with a resistor RN ,

Where

  • IN is the short circuit current through the terminals.
  • RN is the input or equivalent resistance at the terminals when the independent sources are turned off.

27

th

th N

N th

R

V I

R R

=

=

  • The Thevenin’s and Norton equivalent circuits are related by a source transformation. For this reason the source transformation is often called Thevenin-Norton transformation.

4.6 Norton’s Theorem (1)4.6 Norton’s Theorem (1)

th

N th V I

R R

=

=

  • Since V (^) TH, IN and RTH are related according to eq (i), to determine the thevenin or Norton equivalent circuit requires that we find: th

N R

circuit requires that we find: I =

  1. The open circuit voltage voc across the terminals a and b.
  2. The short circuit current i (^) sc at terminals a and b.
  3. The equivalent or input resistance Rin at terminals a and b when all the independent sources are (^) V = v

28

independent sources are turned off.

  • We can calculate any two of the three using the method that takes least effort and use them to get the third using ohm’s law…

N sc

oc th

N sc

th oc

R i

v R

I i

V v

= =

=

=

docsity.com

4.6 Norton’s Theorem (2)4.6 Norton’s Theorem (2)

Practice Problem 4.12:

Find the Norton

equivalent circuit of the

circuit shown below.

Calculate the Isc

31

docsity.com