Classical Test Theory - Basic Statistics for Behavioral Sciences - Lecture Notes, Study notes of Statistics for Psychologists

Classical Test Theory, Model, Assumptions, Correlation Between the Error Scores, Consequences, Parallel Tests, Standard Error of Measurement, Attenuation theory are some points from this helpful lecture notes.

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Ch. 3. Classical Test Theory
I. Model
XIP = TIP + EIP
where,
XIP: the observed score for test I and person P,
TIP: the true score for test I and person P, and
EIP: error of measurement for test I and person P.
E(EIP) = 0, thus
E(XIP) = TIP
II. Assumptions
A. ρET = 0
The correlation between the error scores and the true scores in the population is
zero.
B. ρE1E2 = 0
The error scores in two different tests are uncorrelated in the population.
C. ρE1T2 = 0
The error scores on Test 1 are uncorrelated with the true scores on Test 2.
D. The existence of parallel tests. Two tests are called parallel tests if T1 = T2 and
σ²E1 = σ²E2.
E. The existence of τ-equivalent tests. Two test are called τ-equivalent test if
T1 = T2 + c, where, c is a constant.
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Ch. 3. Classical Test Theory

I. Model

XIP = TIP + EIP

where,

XIP: the observed score for test I and person P,

TIP: the true score for test I and person P, and

EIP: error of measurement for test I and person P.

E (EIP) = 0, thus

E (XIP) = TIP

II. Assumptions

A. ρET = 0

The correlation between the error scores and the true scores in the population is

zero.

B. ρE1E2 = 0

The error scores in two different tests are uncorrelated in the population.

C. ρE1T2 = 0

The error scores on Test 1 are uncorrelated with the true scores on Test 2.

D. The existence of parallel tests. Two tests are called parallel tests if T 1 = T 2 and

σ²E1 = σ²E2.

E. The existence of τ-equivalent tests. Two test are called τ-equivalent test if

T 1 = T 2 + c, where, c is a constant.

III. Consequences

A. E (E) = 0 {From the model)

proof:

E (X) = E (T) + E (E)

= T + E (E)

E (X) = T

E (E) = 0

B. E (ET) = σET = 0

proof:

E (ET) = E (ET) - 0

= E (ET) - E (E) E (T)

= σET

σET

ρET = ──── = 0

σEσT

E (ET) = σET = 0

C. σ²X = σ²T + σ²E

proof:

σ²X = σ²(T + E)

= σ²T + σ²E + 2σET

= σ²T + σ²E

D. σ²T

ρ²XT = ────

σ²X

proof:

σXT

ρ²XT = [───── ]²

σXσT

[ E (XT) - E (X) E (T)]²

σ²Xσ²T

[ E ((T + E)T) - E (X) E (T)]²

σ²Xσ²T

( E (X) = T, E (T) = T, E (X) = E (T) )

[ E (T²) + E (ET) - E (T) E (T)]²

σ²Xσ²T

H. σ²T σ²T'

ρXX' = ──── = ────

σ²X σ²X'

(X and X' are scores on parallel tests.)

proof:

σXX'

ρXX' = ─────

σXσX'

σ(T + E)(T' + E')

= ─────────

σ²X

σTT' + σTE’ + σET' + σEE'

= ───────────────

σ²X

σTT'

= ─────

σ²X

σ²T

= ─────

σ²X

σ²T'

= ─────

σ²X'

I. σ²E

ρXX' = 1 - ────

σ²X

σ²T

ρXX' = ────

σ²X

σ²X - σ²E

= ───────

σ²X

σ²E

= 1 - ────

σ²X

J. ρXX' = 1 - ρ²XE

σXE

ρ²XE = [─────]²

σXσE

(σTE + σ²E)²

= ───────

σ²Xσ²E

(σ²E)²

= ──────

σ²Xσ²E

σ²E

= ────

σ²X

σ²E

ρXX' = 1 - ────

σ²X

= 1 - ρ²XE

K. ρ²XT = ρXX'

σ²T

ρ²XT = ────

σ²X

= ρXX'

L. σ²T = σXX'

σ²T

ρXX' = ─── (H)

σ²X

σXX' σXX'

ρXX' = ────= ──── ( σX = σX')

σXσX' σ²X

σ²T = σXX'

M. σ²E = σ²X(1 - ρXX')

σ²E = σ²X - σ²T ( σ²X = σ²T + σ²E)

= σ²X - σ²XρXX' ( ρXX' = σ²T/σ²X)

ρTxTz 1

ρXZ XX ' ZZ '

(Validity cannot be greater than the square-root of the product of two reliabilities

---> Attenuation Theory)

O. σ²Tx = N²σ²Ty

where

X = ΣYi [Ys are parallel test scores with E (Yi) = TY], and σ²Eyi = σ²Ey.

TX = E (X)

= E [ΣYi] = Σ E (Yi) = NTY

σ²Tx = E [TX - E (TX)]²

Now,

TX - E (TX) = NTY - E (NTY)

= NTY - N E (TY)

= N[TY - E (TY)]

σ²Tx = E [TX - E (TX)]²

= E [N(TY - E (TY))]²

= N² E [TY - E (TY)]²

= N²σ²Ty

P.

2 2 E (^) X E Y

N

where

X = ΣYi [Ys are parallel test scores with E (Yi) = TY], and σ²Eyi = σ²Ey.

EX X TX

= Y

N

i

Yi NT 1

= Y

N

i

NTY EYi NT 1

N

i

EYi 1

N

i

N

i j

j

EE

N

i

E (^) X EY YiYJ 1 1 1

2 2

2 E Y

N

Q.

NρYY'

ρXX' = ────────

1+(N-1)ρYY'

{Spearman-Brown formula, where N is number of parallel tests (Y is a subtest of X).}

σ²Tx

ρXX' = ────

σ²X

N²σ²Ty

= ─────────── ( σXX' = σ²Tx)

Σσ²Yi + ΣΣσYiYj

N²σ²Ty

= ─────────────

Nσ²Y + N(N-1)σ²Ty

N²ρYY'σ²Y

= ───────────────

Nσ²Y + N(N-1)ρYY'σ²Y

N²ρYY'σ²Y

= ──────────────

Nσ²Y(1 + (N-1)ρYY')

NρYY'

= ────────────

(1 + (N-1)ρYY')

R. If 1

lim YY ' 0 ,^ XX ' N

NρYY'

ρXX' = ───────

(1 + (N-1)ρYY')

'

'

1 1 YY

YY

N

N

N

As 0 ,( 1 )/ 1 , 1 , 0.

'

' ' YY YY

YY N N and XX if N

N