Commutator Formulas, Lecture notes of Quantum Mechanics

Commutator formulas in quantum mechanics. It defines commutators and their use in calculating expectation values. The document also provides different formulas to manipulate commutators. It is a useful resource for students studying quantum mechanics and related topics.

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Commutator Formulas
Shervin Fatehi
September 20, 2006
1 Introduction
A commutator is defined as1
[ˆ
A, ˆ
B] = ˆ
Aˆ
Bˆ
Bˆ
A(1)
where ˆ
Aand ˆ
Bare operators and the entire thing is implicitly acting on
some arbitrary function. We’ve seen these here and there since the course
began, most recently in the Heisenberg equation of motion for an expectation
value’s time dependence:2
d
dthAit=1
i¯hh[ˆ
A, ˆ
H]it
It’s worth recalling that any operator ˆ
Afor which [ ˆ
A, ˆ
H] = 0 is a constant
of the motion that is, its expectation value hAit=hAiwill be independent
of time altogether.
Commutators can be a little tricky (Problem Set 2 should’ve proved that
to you!), so let’s have a look at the different formulas we can use to make
manipulating them a little easier.
1Most quantum mechanics books will discuss commutators in some detail. You can
also check out the Wikipedia page, http://en.wikipedia.org/wiki/Commutator, for more
information.
2The notation I’m using here is shorthand. Wherever the h...itappears, you should
remember that it means we’re calculating
hΨ(t)|ˆ...|Ψ(t)i=Z
−∞
Ψ(x, t)( ˆ...)Ψ(x, t) dx
1
pf2

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Commutator Formulas

Shervin Fatehi

September 20, 2006

1 Introduction

A commutator is defined as

1

[

A,

B] =

A

B −

B

A (1)

where

A and

B are operators and the entire thing is implicitly acting on

some arbitrary function. We’ve seen these here and there since the course

began, most recently in the Heisenberg equation of motion for an expectation

value’s time dependence:

2

d

dt

〈A〉t =

i¯h

〈[

A,

H]〉t

It’s worth recalling that any operator

A for which [

A,

H] = 0 is a constant

of the motion – that is, its expectation value 〈A〉 t

= 〈A〉 will be independent

of time altogether.

Commutators can be a little tricky (Problem Set 2 should’ve proved that

to you!), so let’s have a look at the different formulas we can use to make

manipulating them a little easier.

1 Most quantum mechanics books will discuss commutators in some detail. You can

also check out the Wikipedia page, http://en.wikipedia.org/wiki/Commutator, for more

information.

2 The notation I’m using here is shorthand. Wherever the 〈.. .〉t appears, you should

remember that it means we’re calculating

〈Ψ(t)|.. .ˆ|Ψ(t)〉 =

∫ ∞

−∞

Ψ

∗ (x, t)( ˆ.. .)Ψ(x, t) dx

2 Formulas

There aren’t actually that many formulas to point out to you – “just” seven,

not counting one that I’ll have you prove as an exercise – but the amazing

thing is that only the definition given in (1) is fundamental! As a result, you

should be able to prove any claim that you find dubious on your own, and

you’ll only have to do a little pencil pushing. Even if you don’t have trouble

believing any of these formulas, it’s worth working them out at least once.

With that said, here they are (c is a constant):

[

A, c] = 0

[

A,

A] = 0

[

A,

B] = −[

B,

A]

[c

A,

B] = [

A, c

B] = c[

A,

B]

[

A,

B ±

C] = [

A,

B] ± [

A,

C]

[

A

B,

C] =

A[

B,

C] + [

A,

C]

B

[

A,

B

C] =

B[

A,

C] + [

A,

B]

C

3 Exercise

Show that [

A, f (

A)] = 0, given that the function f has a power series ex-

pansion in

A. This is a handy thing to know when you want to evaluate the

commutator of ˆx or ˆp with the Hamiltonian operator

H.