Completing the Square: A Method for Solving Quadratic Equations, Assignments of Calculus

The technique of 'completing the square' to solve quadratic equations. It provides examples and step-by-step instructions on how to find the constant term needed to factor a trinomial into identical quadratic factors. The document also covers the process of solving an equation by completing the square.

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Completing the Square
Provided by the Academic Center for Excellence 1 Reviewed August, 2014
Completing the Square
โ€œCompleting the squareโ€ is another method of solving quadratic equations. It allows trinomials to
be factored into two identical factors.
Example: ๐‘ฅ๐‘ฅ2+ 4๐‘ฅ๐‘ฅ+ 4
(๐‘ฅ๐‘ฅ+ 2)(๐‘ฅ๐‘ฅ+ 2) or (๐‘ฅ๐‘ฅ+ 2)2
To complete the square, it is necessary to find the constant term, or the last number that will enable
factoring of the trinomial into two identical factors. To find the constant term needed, simply take
the coefficient of โ€œ๐‘ฅ๐‘ฅ,โ€ divide by 2, and square the quotient. If you have an equation, rather than an
expression, the resulting number should be added to both sides of the equation.
Example: What is the constant term used to factor the expression ๐‘ฅ๐‘ฅ2โˆ’8๐‘ฅ๐‘ฅ into two
identical factors?
Step 1. Take the coefficient of โ€œ๐‘ฅ๐‘ฅโ€, which is โˆ’8, and divide it by two.
โˆ’8
2 =โˆ’4
Step 2. Take that number and square it.
(โˆ’4)2=16
Step 3. Adding the constant term of 16 would allow the expression to be factored
into identical factors.
๐‘ฅ๐‘ฅ2โˆ’8๐‘ฅ๐‘ฅ+16 = (๐‘ฅ๐‘ฅโˆ’4)2
To solve an equation by completing the square requires a couple of extra steps.
Example: Solve by completing the square ๐‘ฅ๐‘ฅ2+ 8๐‘ฅ๐‘ฅ+ 7 = 0
Step 1. Move the constant term to the other side of the equation by subtracting
from both sides.
๐‘ฅ๐‘ฅ2+ 8๐‘ฅ๐‘ฅ+ 7 โˆ’7 = 0 โˆ’7
๐‘ฅ๐‘ฅ2+ 8๐‘ฅ๐‘ฅ=โˆ’7
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Completing the Square Provided by the Academic Center for Excellence 1 Reviewed August, 2014

Completing the Square

โ€œCompleting the squareโ€ is another method of solving quadratic equations. It allows trinomials to be factored into two identical factors.

Example: ๐‘ฅ๐‘ฅ^2 + 4๐‘ฅ๐‘ฅ + 4 (๐‘ฅ๐‘ฅ + 2)(๐‘ฅ๐‘ฅ + 2) or (๐‘ฅ๐‘ฅ + 2)^2

To complete the square, it is necessary to find the constant term, or the last number that will enable factoring of the trinomial into two identical factors. To find the constant term needed, simply take the coefficient of โ€œ๐‘ฅ๐‘ฅ,โ€ divide by 2 , and square the quotient. If you have an equation, rather than an expression, the resulting number should be added to both sides of the equation.

Example: What is the constant term used to factor the expression ๐‘ฅ๐‘ฅ^2 โˆ’ 8 ๐‘ฅ๐‘ฅ into two identical factors? Step 1. Take the coefficient of โ€œ๐‘ฅ๐‘ฅโ€, which is โˆ’ 8 , and divide it by two. โˆ’ 2 =^ โˆ’^4 Step 2. Take that number and square it. (โˆ’4)^2 = 16 Step 3. Adding the constant term of 16 would allow the expression to be factored into identical factors. ๐‘ฅ๐‘ฅ^2 โˆ’ 8 ๐‘ฅ๐‘ฅ + 16 = (๐‘ฅ๐‘ฅ โˆ’ 4)^2

To solve an equation by completing the square requires a couple of extra steps.

Example: Solve by completing the square ๐‘ฅ๐‘ฅ^2 + 8๐‘ฅ๐‘ฅ + 7 = 0 Step 1. Move the constant term to the other side of the equation by subtracting from both sides. ๐‘ฅ๐‘ฅ^2 + 8๐‘ฅ๐‘ฅ + 7 โˆ’ 7 = 0 โˆ’ 7 ๐‘ฅ๐‘ฅ^2 + 8๐‘ฅ๐‘ฅ = โˆ’ 7

Step 2. Complete the square.

= 4^2 = 16

Step 3. Since 16 is being added to the left side of the equation it MUST also be added to the right side. ๐‘ฅ๐‘ฅ^2 + 8๐‘ฅ๐‘ฅ + 16 = โˆ’7 + 16 ๐‘ฅ๐‘ฅ^2 + 8๐‘ฅ๐‘ฅ + 16 = 9 Step 4. Factor the left side of the equation. ๐‘ฅ๐‘ฅ^2 + 8๐‘ฅ๐‘ฅ + 16 = 9 (๐‘ฅ๐‘ฅ + 4)^2 = 9 HINT: the number inside the factor should always be the same as the number obtained from dividing the coefficient of โ€œxโ€ by two! 8 2 = 4^ and the factor was^ (๐‘ฅ๐‘ฅ^ + 4)

2

Step 5. Take the square root of both sides and solve for ๐‘ฅ๐‘ฅ.

๏ฟฝ^2 (๐‘ฅ๐‘ฅ + 4)^2 = (^) โˆš^29 ๐‘ฅ๐‘ฅ + 4 = ยฑ ๐‘ฅ๐‘ฅ = โˆ’7 and โˆ’ 1

To complete the square, the coefficient of ๐‘ฅ๐‘ฅ^2 must be one. If it is any other number, first divide the entire equation by that number.

Example: Solve by completing the square 4 ๐‘ฅ๐‘ฅ^2 โˆ’ 12 ๐‘ฅ๐‘ฅ โˆ’ 4 = 12 Step 1. Divide the equation by 4 in order to get a leading coefficient of 1. (4x^2 โˆ’ 12x โˆ’ 4) 4 =

12 4 ๐‘ฅ๐‘ฅ^2 โˆ’ 3 ๐‘ฅ๐‘ฅ โˆ’ 1 = 3

Practice Problems

  • ๐‘ฅ๐‘ฅ = โˆ’1 and ๐‘ฅ๐‘ฅ =
    1. ๐‘ฅ๐‘ฅ^2 + 6๐‘ฅ๐‘ฅ + 5 =
    1. ๐‘ฅ๐‘ฅ^2 + 8๐‘ฅ๐‘ฅ โ€“ 9 =
    1. ๐‘ฅ๐‘ฅ^2 โ€“ 6๐‘ฅ๐‘ฅ + 9 =
    1. ๐‘ฅ๐‘ฅ 2 + 4๐‘ฅ๐‘ฅ โ€“ 7 =
    1. ๐‘ฅ๐‘ฅ 2 โ€“ 5๐‘ฅ๐‘ฅ โ€“ 24 =
    1. ๐‘ฅ๐‘ฅ^2 โ€“ 8๐‘ฅ๐‘ฅ + 15 =
    1. 4 ๐‘ฅ๐‘ฅ 2 โ€“ 4๐‘ฅ๐‘ฅ + 17 =
    1. 9 ๐‘ฅ๐‘ฅ^2 โ€“ 12๐‘ฅ๐‘ฅ + 13 =
    1. 4 ๐‘ฅ๐‘ฅ^2 โ€“ 4๐‘ฅ๐‘ฅ + 5 =
    1. 4 ๐‘ฅ๐‘ฅ^2 โ€“ 8๐‘ฅ๐‘ฅ + 1 =

Answers to Practice Problems

  1. โˆ’5 and โˆ’ 1

  2. 1 and โˆ’ 9

  3. 3 only

  4. โˆ’ 2 โˆ’ โˆš 11 and โˆ’ 2 + โˆš 11

  5. โˆ’3 and 8

  6. 3 and 5

2 + 2๐‘–๐‘–^ and^

2 โˆ’^2 ๐‘–๐‘–

3 +^ ๐‘–๐‘–^ and^

2 +^ ๐‘–๐‘–^ and^

2 and 1^ โˆ’^