Complex Algebra 5 - Exercises - Mathematics, Exercises of Mathematics

Let f be a nonconstant analytic function on a neighborhood of z0, and let n be the multiplicity of the zero at z0 of the function f(z)−f(z0). We have seen that, for any a sufficiently close to f(z0), the equation f(z) = a has n solutions (counted with multiplicity) near z0, call them z1, . . . , zn in some order.

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Math 213a: Complex analysis
Problem Set #4 (15 October 2003):
Contour integrals II
1. [Qualifying Exam, Spring 1997] For b > 0, compute R
0log x dx/(x2+b2).
2. Evaluate Rπ
0log |a+ cos(θ)| as a function of a0. [As you might expect, the
formula will depend on whether a1 or a1. Can you obtain this formula
without using complex analysis?]
3. Prove that Z
0
cos(mx)
cosh(πx)emx2dx =1
2em/4
for all m > 0. [From the Fall 1998 Qualifying Exam.] Can you evaluate any other
such integrals this way (other than those obtained trivially from this formula by
linear change of variable etc.)?
4. Let fbe a nonconstant analytic function on a neighborhood of z0, and let nbe the
multiplicity of the zero at z0of the function f(z)f(z0). We have seen that, for any
asufficiently close to f(z0), the equation f(z) = ahas nsolutions (counted with
multiplicity) near z0, call them z1, . . . , znin some order. Prove that the coefficients
of the polynomial Qn
j=1(Xzj) are analytic functions of ain that neighborhood
of z0. [These coefficients are (up to sign) the elementary symmetric functions in
the zj. For n= 1 the claim is equivalent to the existence of an analytic inverse
function. To prove it in general, show that Pn
j=1 zk
jis an analytic function of afor
each k= 1,2,3, . . ..]
5. For any two disjoint circles C1,C2in the Riemann sphere P1(C), define I(C1, C2) as
the value of the double path integral with respect to arc length:
I(C1, C2) := IC1IC2
|dz1| |dz2|
|z1z2|2.
This may be an improper integral if either C1or C2passes thru (i.e., is a straight
line in C), but even in that case the integral clearly converges.
i) Show that I(C1, C2) is PGL2(C)-invariant; that is, that I(φC1, φC2) = I(C1, C2)
for any fractional linear transformation φ:P1(C)P1(C).
ii) Determine I(C1, C2) as a function of the radii R1, R2of the circles and the distance d
between their centers. [Check: when d= 0, so C1, C2are concentric, you should
obtain
I(C1, C2) = 4π2R1R2
|R2
1R2
2|;
more generally, the formula should diverge when d=|R1R2|.] What is I(C1, C2)
if C1=R?
To b e continued.. .
This problem set is due Wednesday, October 22, at the beginning of class.

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Math 213a: Complex analysis Problem Set #4 (15 October 2003): Contour integrals II

  1. [Qualifying Exam, Spring 1997] For b > 0, compute

0 log^ x dx/(x

(^2) + b (^2) ).

  1. Evaluate

∫ (^) π 0 log^ |a^ + cos(θ)|^ dθ^ as a function of^ a^ ≥^ 0.^ [As you might expect, the formula will depend on whether a ≤ 1 or a ≥ 1. Can you obtain this formula without using complex analysis?]

  1. Prove that (^) ∫ (^) ∞

0

cos(mx) cosh(πx) e−mx

2 dx =

e−m/^4

for all m > 0. [From the Fall 1998 Qualifying Exam.] Can you evaluate any other such integrals this way (other than those obtained trivially from this formula by linear change of variable etc.)?

  1. Let f be a nonconstant analytic function on a neighborhood of z 0 , and let n be the multiplicity of the zero at z 0 of the function f (z)−f (z 0 ). We have seen that, for any a sufficiently close to f (z 0 ), the equation f (z) = a has n solutions (counted with multiplicity) near z 0 , call them z 1 ,... , zn in some order. Prove that the coefficients of the polynomial

∏n j=1(X^ −^ zj^ ) are analytic functions of^ a^ in that neighborhood of z 0. [These coefficients are (up to sign) the elementary symmetric functions in the zj. For n = 1 the claim is equivalent to the existence of an analytic inverse function. To prove it in general, show that

∑n j=1 z k j is an analytic function of^ a^ for each k = 1, 2 , 3 ,.. ..]

  1. For any two disjoint circles C 1 , C 2 in the Riemann sphere P^1 (C), define I(C 1 , C 2 ) as the value of the double path integral with respect to arc length:

I(C 1 , C 2 ) :=

C 1

C 2

|dz 1 | |dz 2 | |z 1 − z 2 |^2

This may be an improper integral if either C 1 or C 2 passes thru ∞ (i.e., is a straight line in C), but even in that case the integral clearly converges. i) Show that I(C 1 , C 2 ) is PGL 2 (C)-invariant; that is, that I(φC 1 , φC 2 ) = I(C 1 , C 2 ) for any fractional linear transformation φ : P^1 (C) → P^1 (C). ii) Determine I(C 1 , C 2 ) as a function of the radii R 1 , R 2 of the circles and the distance d between their centers. [Check: when d = 0, so C 1 , C 2 are concentric, you should obtain I(C 1 , C 2 ) = 4π^2

R 1 R 2

|R^21 − R^22 |

more generally, the formula should diverge when d = |R 1 − R 2 |.] What is I(C 1 , C 2 ) if C 1 = R? To be continued...

This problem set is due Wednesday, October 22, at the beginning of class.