Composite Functions in Math Analysis - Precalculus, Exercises of Pre-Calculus

Composite functions in Math Analysis - Precalculus. It defines the four operations of functions and their domains. It also explains how to form a composite function and find its domain. examples to illustrate the concepts. useful for students studying Math Analysis - Precalculus.

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Math Analysis Precalculus, Sullivan 10th Edition
Ch5Sec1 1 12/1/2019
Section 5.1 Composite Functions
From Section 2.1, you know functions, like numbers, can be added, subtracted, multiplied, and divided.
If f and g are functions:
Their sum,
,gf
is the function defined by
).x(g)x(f)x)(gf(
The domain of
)x)(gf(
consists of the numbers x that are in the domain of f and in the domain of g.
Their difference,
,gf
is the function defined by
).x(g)x(f)x)(gf(
The domain of
)x)(gf(
consists of the numbers x that are in the domain of f and in the domain of g.
Their product,
,gf
is the function defined by
).x(g)x(f)x)(gf(
The domain of
)x)(gf(
consists of the numbers x that are in the domain of f and in the domain of g.
Their quotient,
,
g
f
is the function defined by
The domain of
)x(
g
f
consists of the numbers x for which
0)x(g
that are in the domain of f and
in the domain of g.
Example 1: Let f and g be two functions defined as
2
x5)x(f
and
.1x3)x(g
Find all four operations
of f and g and the domain for each operation.
a)
)x(g)x(f)x)(gf(
b)
)x(g)x(f)x)(gf(
1x3x5 2
)1x3(x5 2
Domain: All real numbers
1x3x5 2
Domain: All real numbers
c)
)x(g)x(f)x)(gf(
d)
)x(g
)x(f
)x(
g
f
1x3
x5 2
Domain: All real numbers except
3
1
x
OR
3
1
xx
Form a Composite Function
Given two functions f and g, the composite function, denoted by
gf
(read as “f composed with g”), is defined by
)x(g)x(f)x()gf(
))x(g(f
.
The domain of
)x()gf(
is the set of all numbers x in the domain of g such that
)x(g
is in the domain of f.
Look at Figure 2. Only those values of x in the domain of g for which g(x) is in the domain of f can be in the domain of
gf
. The reason is that if g(x) is not in the domain of f, then f(g(x)) is not defined. Because of this, the domain of
gf
is a subset of the domain of g; the range of
gf
is a subset of the range of f.
)1x3(x5 2
23 x5x15
Domain: All real numbers
pf3
pf4

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Math Analysis – Precalculus, Sullivan 10 Edition

Section 5.1 – Composite Functions

From Section 2.1, you know functions, like numbers, can be added, subtracted, multiplied, and divided.

If f and g are functions:

Their sum, f g,is the function defined by( fg)(x)f(x)g(x).

The domain of ( fg)(x)consists of the numbers x that are in the domain of f and in the domain of g.

Their difference, f g,is the function defined by( fg)(x)f(x)g(x).

The domain of ( fg)(x)consists of the numbers x that are in the domain of f and in the domain of g.

Their product, f g,is the function defined by( fg)(x)f(x)g(x).

The domain of ( fg)(x) consists of the numbers x that are in the domain of f and in the domain of g.

Their quotient, , g

f is the function defined by , whereg(x) 0. g(x)

f(x) (x) g

f   

The domain of (x) g

f

consists of the numbers x for which g (x) 0 that are in the domain of f and

in the domain of g.

Example 1: Let f and g be two functions defined as

2 f (x) 5 x and g^ (x)^3 x^1. Find all four operations

of f and g and the domain for each operation.

a) ( fg)(x)f(x)g(x) b) ( fg)(x)f(x)g(x)

5 x 3 x 1

2    5 x ( 3 x 1 )

2   

Domain: All real numbers 5 x 3 x 1

2   

Domain: All real numbers

c) ( fg)(x)f(x)g(x) d) g(x)

f(x) (x) g

f  

3 x 1

5 x

2

Domain: All real numbers except 3

x 

OR

x x

Form a Composite Function

Given two functions f and g, the composite function, denoted by f g(read as “f composed with g”), is defined by

( f g)(x)f(x)g(x)

f(g(x)).

The domain of ( fg)(x)is the set of all numbers x in the domain of g such that g(x) is in the domain of f.

Look at Figure 2. Only those values of x in the domain of g for which g(x) is in the domain of f can be in the domain of

f g. The reason is that if g(x) is not in the domain of f, then f(g(x)) is not defined. Because of this, the domain off g

is a subset of the domain of g; the range of f gis a subset of the range of f.

5 x ( 3 x 1 )

2  

3 2  15 x  5 x

Domain: All real numbers

Math Analysis – Precalculus, Sullivan 10 Edition

Section 5.1 – Composite Functions (continued)

Figure 3 provides a second illustration of the definition. Here x is the input to the function g, yielding g(x). Then g(x) is

the input to the function f, yielding f (g( x )). Note that the “inside” function g in f (g( x ))is “processed” first.

Example 2: Let f and g be two functions defined asf (x) x 1

2   and g (x) 3 x. Find ( fg)( 1 )and( gf)( 2 ).

a) ( f g)(x)f(x)g(x) OR g (x) 3 x

f(g(x))  g ( 1 ) 3 ( 1 )

( 3 x) 1

2    3

3 x 1

2 2   So,f (g( 1 ))f( 3 )

9 x 1

2   3 1

2  

f (g( 1 )) 9 ( 1 ) 1

2    9  1

b) ( g f)(x)g(x)f(x) OR f (x) x 1

2  

g(f(x)) f ( 2 ) 2 1

2   

3 ( x 1 )

2   ^4 ^1

3 x 3

2    3

g( f( 2 )) 3 ( 2 ) 3

2  ^ So,g^ (f(^2 ))g(^3 )

Find the Domain of a Composite Function

To find the domain of ( fg)(x)f(g(x)),remember that

  1. g(x)must be defined, so exclude any value of x that is not in the domain of g(x).

  2. f(g(x))must be defined, so any x for which g(x) is not in the domain of f must be excluded.

Example 3: Find the domain of ( fg)(x)if x 3

f (x) 

 and. x 5

g (x) 

The domain of g(x)is x |x 5 .

 You must exclude  5 from the domain of ( fg)(x).

The domain of f(x)is  x |x 3 . ( fg)(x)f(g(x)), sog (x) 3.

Find where g (x) 3. Setg (x) 3.

x 5

2  3 (x 5 )

2  3 x 15

 13  3 x

x

Thus, the domain of ( fg)(x)is. 3

x x 5 and x

Alternate

Method

Alternate Method

Math Analysis – Precalculus, Sullivan 10 Edition

Section 5.1 – Composite Functions (continued)

Example 5: Given f ( x )  5x  6 and

g( x ) (x 6). 5

  Find ( f g )( x )and( g f )( x ).

( f g )( x ) f ( g(x) ) ( g f )( x ) g( f (x) )

f (x 6) 5

(5x 6) 6 5

5 (x 6) 6 5

(5x) 5

 (x  6)  6 x

x

So, in this example,( f g )( x ) ( g f )( x ).

In Section 5.2, you will see that there is an important relationship between functions f and g for which

( f g )( x )  ( g f )( x ) x.

Calculus Application

Some techniques in calculus require the ability to determine the components of a composite function.

Example 6: The functionH (x) 3 x 2

2   is the composition of functions f and g.

Find functions f and g such that( fg)(x)H(x).

Let f (x) x andg (x) 3 x 2.

2  

ThenH (x)(fg)(x)

f(g(x))

f ^3 x 2 

2  

3 x 2

2  

Functions f and g in Example 5 are not unique, but usually there is an obvious, or “natural”, selection for f and g that

comes to mind first.

You could also let f (x) x 2 andg (x) 3 x.

2 

ThenH^ (x)(fg)(x)

f(g(x))

2 f 3 x

3 x 2

2  

All material has been taken from Precalculus, by M. Sullivan, 10 th Edition