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Find the mole fraction of the sodium chloride and of the water in the solution. 2). How many grams of magnesium cyanide are needed to make 275 mL of a 0.075. M ...
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1. 6.80 g NaCl x 1 mole NaCl = 0.116 mole NaCl 58.45 g NaCl 2750 mL H 2 O x 1 g H 2 O x 1 mole H 2 O = 152.8 mol H 2 O 1 mL H 2 O 18 g H 2 O mole fraction NaCl = 0.116 mole NaCl = 7.59 x 10- 152.9 mole soln mole fraction H 2 O = 152.8 mole H 2 O = 0. 152.9 mole soln 2. 275 mL H 2 O x 1 g H 2 O = 0.275 L H 2 O 1000 mL H 2 O 275 L Mg(CN) 2 x 0.075 mole Mg(CN) 2 x 76.3 g Mg(CN) 2 = 1.6 g Mg(CN) 2 1 L Mg(CN) 2 1 mole Mg(CN) 2 3. 275 mL H 2 O x 1 g H 2 O x 1 kg H 2 O = 0.275 kg H 2 O 1 mL H 2 O 1 g H 2 O 0.275 kg H 2 O x 0.075 mol Mg(CN) 2 x 76.3 g Mg(CN) 2 = 1.6 g Mg(CN) 2 1 kg H 2 O 1 mole Mg(CN) 2 4. 1.25 molal NaOH = 1.25 mole NaOH 1 kg H 2 O 1.25 mole NaOH x 40 g NaOH = 50.0 g NaOH 1 mole NaOH Measure 50.0 g NaOH and add water to 1 L volume. 5. 52 g K 2 SO 4 x 1 mole K 2 SO 4 = 0.299 mole K 2 SO 4 174 g K 2 SO 4 0.299 mole K 2 SO 4 = 0.073 M 4.100 L K 2 SO 4 6. 375 mL x 0.0750 = 28.125 mL ethylene glycol 28.125 mL ethylene glycol x 1.09 g ethylene glycol/1ml = 30.7 g ethylene glycol 7. 39 g KOH x 1 mole KOH x 1 L KOH = 0.93 L = 930 mL 56 g KOH 0.75 mol KOH 8. 3.0 L soln x 0.750 moles HCl x 36.45 g HCl = 82 g HCl 1 L soln 1 mole HCl 9. 1.3 atm = C C = (1.3 atm)(0.48 g/L) = 0.25 g/L 2.5 atm 0.48 g/L (2.5 atm) 10. 0.850 g NH 4 NO 3 x 1 mole NH 4 NO 3 = 0.0106 mole NH 4 NO 3 80 g NH 4 NO 3 0.0106 mole NH 4 NO 3 = 0.0307 M 0.345 L NH 4 NO 3 11. 0.675 L BaI 2 x 0.400 moles BaI 2 = 0.270 moles BaI 2
0.270 moles BaI 2 x 391.1 g BaI 2 = 106 g BaI 2 1 mole BaI 2 Measure 106 g BaI 2 into a beaker and add water to 675 mL volume.