Conditions - Linear Algebra - Quiz Solution, Exercises of Linear Algebra

This is the Quiz Solution of Linear Algebra. Mainly includes points are Explicit Conditionsm, Expansion Across, Equilibrium Prices, Equation, Elementary, Elementary Row etc. Key important points of tags are: Conditions, Column Vectors, Necessary, Cient, Column Vectors, Span, Indeed Satisfy, Conditions, Values, Column Vectors

Typology: Exercises

2012/2013

Uploaded on 02/27/2013

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Math 205B Quiz 04 page 1 02/05/2010 Name. Siete olvhens -6 -12 -17 -7 5 by m 10 8 9 T=2 be n 1. Let A= 2 0 1 -1 -1 |, b= |63|, and d= | 3]. Label the column vectors of A as ¢1, -.., ¢5- 3 3 1 5 2 by 2 —t =1 =33.-1 2 bs, 1 -6 -12 -17 -7 5{/10000 100 0 OJf0 0 1/2 1/16 3/16 10 8 9 7 -1)0 1000 010 2 41/0 0 -1/2 5/16 —1/16 FACT: 2 0 1 -1 —1]/0 0 1 0 O| hasRREF| 0 0 1 -1 -1/0 0 0 -1/8 -3/8 3 3 1 5 2;00010 000 0 Oj1 0 -3 2 —6 -l1 -1 -3 1 2;00001 000 0 Oj0 1 -1 —2 2 1A. Use the FACT to find any/all conditions on 61, ..., bs which are necessary and sufficient for b to be in the span of the column vectors A. the last two rmls J the RREF iy fhe a Lay the sft Ppreredted hy PS=be amital <> OF b, - 3b, +2b,- 6b, Is = b = b, -2b,, + 2b, 1B. Verify that cs does indeed satisfy the conditions in 1A. ai Ficch condition QD = 5 ~3(-1) + 2(2) ~6(2) 2] Send anditon © W -1-(1) -2(2) +2(2) ? = 54344712 7 = -14t -444 = (2-2 7 = O+0 = OF = 60 1C. Find all values of m and n for which d is in the span of the column vectors A. Using the conditiens trom 1A S O= m -3{3) +2(2) “tt! og {Orm- Fae O= n-3-2(2) +2) “I? . ; o=m- m= ore. n-s Finis 1D. Is cs a linear combination of the first four column vectors of A? If so, find an explicit LC; if not explain why not. one wt & dlarsile | erasith. fhe agaoted merix [8 & E &)/ 5], We competstions hectsiand beciwre ts h he het. [rate H. lcalomr fe | foes NOT chang ts keer! J So ta soldtaans 4 XG eRe enya als Me RZ |e) | ap | iI [4 if we pik xy =O (say) Hhem a/ i md Peed Le ae o Big [OE 1-1 | tas mn ene mp yy, fg acs eu ALTERWATE: Soh: — Al sols 4 Ax = ° dine gitn by the REF ake hed, Go X20 X= -Ung Xe Gwe Xe ww 1 So Hook 08, lee, +2, +08, +e =6 Aye: baths (amd ky= 0) =a 2 ~.=5 x & free * i @ soln d XG te tS te Xs 9 free in the, © ape uth @ penne weg ST sabain boas Yeates ¥,--%q , thn Ee %-% |MORE AN sWeKs (iE 8iF) neste. % in Lt ae allernat, som ha 5! (x, 9-71) New GE! Why