Equation - Linear Algebra - Quiz Solution, Exercises of Linear Algebra

This is the Quiz Solution of Linear Algebra. Mainly includes points are Explicit Conditionsm, Expansion Across, Equilibrium Prices, Equation, Elementary, Elementary Row etc. Key important points of tags are: Equation, Row Equivalent, Components, Matrix, Augmented Matrix, Corresponding, Satisfy, Conditions, Vectors, Homogeneous Equation

Typology: Exercises

2012/2013

Uploaded on 02/27/2013

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Math 2054 Quiz 6, pagel ~ November 2, 2007 NAME, Sggerted Solshions 1. Suppose b has components 6), b:,63, A is a 3x4 matrix and the augmented matrix corresponding to 1468 by — 2bs the equation Ax = b is row equivalent to | 0 0 1 1) by +43 0 0 0 &| 3b) + 2b, + bg 1A. Suppose k = 1. What conditions (if any) must },,b2 and bg satisfy in order for b to be in Col(A)? Explain! Of A= 1y the system & Conistont. for any & by yee S Hore G00 NO restachens y eee (Wo candihinc) on b, he hs 2 1B. So, if k = 1, is Col(A) all of R3? Explain! G61 GIA=RR? see tr aay 6 ERY Aaa hus a sol, fe 6 es 43 Le f the Gglornns f 1C. Suppose & = 1. Find vectors that span the nullspace of A. Hint: Think about the way we write the solutions of the homogeneous equation Ax = 0 in “parametric form”. i ; . . EA Ged Soe %, 4 = ; [2 ol ® = Ai=0 haw sauturs =| A] [ a af : - he : Senet 8 3 hare x0 free, 6°, ail vectors iy null {) ane wna Piles 4 fs) vector [2] 5 his vector gaans the rullipace. 1D. Suppose k = 0. What conditions (if any) Zr di, by and i satisfy in order for b to be in Col(.A)? Explain! ng, ARR hua sebhm <> 3b,+2b, th =20 (otha se the Syctm)s incomsitent,) Lt in parcola 1E. So, if k =0, is Col(A) all of R37 ceee f rr. = shai th he cobimn Space now, [J el* Le 00h uetdors b= b | lig an en 2A. Is the set H ={f € F | the graph of f passes through the point (0,3)} closed under vector addi- tion? Prove i ive a counterexample. GB. wr clk Br (cmt » Fij=Xt3 at alk) = x3, since lo) =3, LEM, al sace. 9l)= 3, 64% But ous oe 6, i“ te Sroph 4 Fe4 p passer thea. (36) iattead d (2, 3), so Uf Lee Goind fw? specihe abmbea 4 H whose Sam ts NOT in 2B. Is the set G = {f € F | the graph of f passes through the point (3,0)} closed under vector addi- tion? Prove itor give a counterexample. lk fant 9 ie doy aehitong Member gf (Fj ne need ross Fi eG, & #(3)=0 fet 9(3)= 0. Mu, (f+ +9)(2) = 3) +903) =0400, So te alo passes tow (3, ) And ths fog OG, 2. Let F be the vector space of all continuous functions f : R — R, as discussed in class. 2C. Which (if either) of H or G is a subspace of F? G 6 Nor Shee eee i , tl detnte. Quon contnh the © vector! (na DEG Since the creme’ 2 paeraa Pgh (49) 3 ee cae od lis : ‘and tS aaa bh chow HE chased om cmelt, foo