Confidence Interval for B1 - Assignment | STAT 333, Assignments of Statistics

Material Type: Assignment; Class: Applied Regression Analysis; Subject: STATISTICS; University: University of Wisconsin - Madison; Term: Spring 2004;

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Stat 333 Spring 2004 1/30/2004
1 Confidence Interval for β1
The variance and standard deviation for b1are given by the following:
V(b1) = σ2
SXX
sd(b1) = σ
SXX
est.sd(b1) = s
SXX
Note that b1is the estimator of β1such that b1=SXY
SXX
. When constructing the confidence interval
for β1, we should know the following facts:
(1) β1is the parameter of interest and it is fixed, not random.
(2) b1is a random variable and it has the normal distribution with mean β1and variance σ2
SXX
.
(3) From (2), we know that b1β1
σ/SX X
has the standard normal distribution, N(0,1). Since σ2
is unknown, we use s2to estimate σ2, where s2= MSE = SSE/(n2). Therefore, b1β1
s/SXX
has the t-distribution with (n-2) degrees of freedom, i.e.,
b1β1
s/SXX tn2
With these facts, we have
P t(n2,1α
2)<b1β1
s/SXX
< t(n2,1α
2)!= 1 α
That is,
P b1t(n2,1α
2)·s
SXX
< β1< b1+t(n2,1α
2)·s
SXX != 1 α
So the 100(1 α)% confidence interval for β1is
b1±t(n2,1α
2)·s
SXX
4268 CSSC [email protected] Ting-Li Lin

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Stat 333 Spring 2004 1/30/

1 Confidence Interval for β 1

The variance and standard deviation for b 1 are given by the following:

V (b 1 ) =

σ^2

SXX

sd(b 1 ) =

σ √ SXX

est.sd(b 1 ) =

s √ SXX

Note that b 1 is the estimator of β 1 such that b 1 =

SXY

SXX

. When constructing the confidence interval

for β 1 , we should know the following facts:

(1) β 1 is the parameter of interest and it is fixed, not random.

(2) b 1 is a random variable and it has the normal distribution with mean β 1 and variance

σ

2

SXX

(3) From (2), we know that

b 1 − β 1

σ/

SXX

has the standard normal distribution, N (0, 1). Since σ^2

is unknown, we use s^2 to estimate σ^2 , where s^2 = MSE = SSE/(n − 2). Therefore,

b 1 − β 1

s/

SXX

has the t-distribution with (n-2) degrees of freedom, i.e.,

b 1 − β 1

s/

SXX

∼ tn− 2

With these facts, we have

P

(

−t(n − 2 , 1 −

α

2

b 1 − β 1

s/

SXX

< t(n − 2 , 1 −

α

2

)

= 1 − α

That is,

P

(

b 1 − t(n − 2 , 1 −

α

2

s √ SXX

< β 1 < b 1 + t(n − 2 , 1 −

α

2

s √ SXX

)

= 1 − α

So the 100(1 − α)% confidence interval for β 1 is

b 1 ± t(n − 2 , 1 −

α

2

s √ SXX

4268 CSSC [email protected] Ting-Li Lin