Discrete Structures Exam 2 - Spring 1994: Problems and Solutions, Exams of Discrete Structures and Graph Theory

The problems and solutions for exam 2 of a discrete structures course held in spring 1994. The exam covers topics such as equivalence relations, mathematical induction, hamming distance function, density function, length function, and sequences.

Typology: Exams

2012/2013

Uploaded on 04/27/2013

ashay
ashay 🇮🇳

4.1

(15)

196 documents

1 / 1

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
Page 1
Discrete Structures - Exam 2 - Spring 1994
1. Let f:A A be a function and define the relation R on A to be:
R = {(a,b) | a,b A and f(a) = f(b)}. Prove that R is an Equivalence Relation.
2. Using Mathematical Induction, prove .
3. Rewrite 13 - 13(25) + 13(252) - 13(253) +...- 13(2521) in summation form.
4. Calculate .
5. Let Σ = {0,1} be an alphabet and consider the functions
H:Σn×ΣnZn, d:ΣnZn and LnZn defined, for any strings s,t in Σn as:
H(s,t) = the number of positions where s and t disagree
(Hamming Distance Function),
d(s) = the number of 1’s in string s (Density Function),
L(s) = the number of characters in string s (Length Function).
Calculate: (a) H(101100111,111001101) (b) d(101100111) (c) L(θ)
6. Rewrite the following as a summation over j using the change of variables
j = k - 2:
7. Evaluate
8. Consider the sequence: si = si-1 + si-2 + si-3 with s0 = 1, s1 = 3, and s2 = 1. Use the Strong Form
of Mathematical Induction to prove that si is odd for all i N.
9. Prove that each of the following functions is a one-to-one correspondence or show a
counterexample to why it is not:
(a) F:R R defined by F(x) = 5x + 1
(b) G:R R defined by G(x) = 3x2 - 5
10. Let A = {0,1,2,3,4} and R be the relation of congruence modulo 2 on A; that is,
R = {(x,y) | x,y A and 2|(x - y)}.
(a) Draw the directed graph of R.
(b) Describe the partition induced on A by the equivalence relation R.
7m
m0=
p
7p1+ 1
6
---------------------=
1
k
---1
k1+
------------
⎝⎠
⎛⎞
k1=
10
nk–2+()
k1=
n2+
k!
kk 1()!
---------------------
k1=
50
Docsity.com

Partial preview of the text

Download Discrete Structures Exam 2 - Spring 1994: Problems and Solutions and more Exams Discrete Structures and Graph Theory in PDF only on Docsity!

Page 1

Discrete Structures - Exam 2 - Spring 1994

1. Let f:A → A be a function and define the relation R on A to be: R = {(a,b) | a,b ∈ A and f(a) = f(b)}. Prove that R is an Equivalence Relation. 2. Using Mathematical Induction, prove. 3. Rewrite 13 - 13(25) + 13(25^2 ) - 13(25^3 ) +...- 13(25 21 ) in summation form. 4. Calculate. 5. Let Σ = {0,1} be an alphabet and consider the functions H:Σn×Σn→Zn, d:Σn→Zn and L:Σn→Zn defined, for any strings s,t in Σn^ as: H(s,t) = the number of positions where s and t disagree (Hamming Distance Function), d(s) = the number of 1’s in string s (Density Function), L(s) = the number of characters in string s (Length Function). Calculate: (a) H(101100111,111001101) (b) d(101100111) (c) L(θ) 6. Rewrite the following as a summation over j using the change of variables j = k - 2: 7. Evaluate 8. Consider the sequence: si = s (^) i-1 + si-2 + s (^) i-3 with s 0 = 1, s 1 = 3, and s 2 = 1. Use the Strong Form of Mathematical Induction to prove that s (^) i is odd for all i ∈ N. 9. Prove that each of the following functions is a one-to-one correspondence or show a counterexample to why it is not: (a) F:R → R defined by F( x ) = 5 x + 1 (b) G:R → R defined by G( x ) = 3 x^2 - 5 10. Let A = {0,1,2,3,4} and R be the relation of congruence modulo 2 on A; that is, R = {( x,y ) | x,y ∈ A and 2|( x - y )}. (a) Draw the directed graph of R. (b) Describe the partition induced on A by the equivalence relation R.

7 m m = 0

p

7 p^ +^1 – 1 6

= ---------------------

1 k

--- 1 k + 1 ⎝⎛ – ------------⎠⎞ k = 1

10

( nk + 2 ) k = 1

n + 2

k! k k ( – 1 )!


k = 1

50

Docsity.com