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Material Type: Exam; Class: Calculus I; Subject: Mathematics; University: University of Massachusetts - Amherst; Term: Spring 2003;
Typology: Exams
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We compute the derivative and do not simplify:
d dx
5 x^6 − 4 x−^2 + 3x^3 /^2 − 2
= 30x^5 + 8x−^3 + 3
(1) x^1 /^2
d dx
(2) (sec(x)) = sec(x) · tan(x)
d dx
cos(x) x^3 + ex^
(− sin x)(x^3 + ex) − (cos x)(3x^2 + ex) (x^3 + ex)^2
d dx (4) ((5x^2 + 2x + 3) · ex) = (10x + 2) · ex^ + (5x^2 + 2x + 3) · ex
d dx
(5) (esin(x)) = esin(x)^ cos(x)
d dx (6) (tan(ex)) = sec^2 (ex) · ex
d dx
(7) ((2x^2 − 3 x−^2 ) · sin(x^3 + 1)) =
= (4x + 6x−^3 ) · sin(x^3 + 1) + (2x^2 − 3 x−^2 ) · (cos(x^3 + 1) · (3x^2 )) d dx
(4x^2 − 2
3 x + 1)−^4
= −4(4x^2 − 2
3 x + 1)−^5 · (8x − 2
(8) (3x + 1)−^1 /^2 · 3)
d dx
cos^3 (x) + ex 2 − x^3
= 3 cos(x) · (− sin(x)) + ex 2 (9) · (2x) − 3 x^2
d dx
sin
x^2 − ex
= cos
x^2 − ex
(10) (x^2 − ex)−^1 /^2 · (2x − ex)