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A summary of first and second-order differential equations and how to solve them. It also explains how to model a problem using differential equations. The first-order DEs are solved using variables separable DE and reduction through substitution. The second-order DEs are solved by integrating twice. The document also provides an example of how to model a problem using differential equations.
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Differential Equations Summary
1. First order differential equations
a. Variables Separable DE:
Arrange through manipulation such that the form below is achieved:
f ( x)dx=g(y) dy
Integrate subsequently to yield the required solution.
Example: Solve y dx
dy = 1 − for y<1.
dx
dy
y
y dx
dy
− dy dx 1 y
− ln| 1 −y |=x+ C
x B y e
−+ 1 − =
x y Ae
− = 1 − where
B A = e , B = −c (shown)
This solution is commonly termed the GEERAL SOLUTIO , where A is
unknown. When initial conditions are provided, eg y =0 when x =0, then A
assumes a specific value and the solution is termed the PARTICULAR SOLUTIO.
When we use the GC to plot out a series of graphs for various values of A , the result
is that we produce a family of solution curves.
b. Reduction through substitution:
The introduction of an intermediate variable aids in reducing the original
differential equation to a far simpler version which is readily solvable.
Example: Use the substitution y= vx , where v is a function of x, to solve the
differential equation x y dx
dy x = 3 +.
dx
dv v x dx
dy y =vx⇒ = +
Substituting into the differential equation gives
x vx dx
dv x v x = +
dx x
dv x dx
dv x
2 = ⇒ =
= dx x
dv
∴ v = 3 ln|x|+C
y = 3 x ln|x|+ Cx (shown)
2. Second order differential equations:
Second order DEs are typically of the form ( ) 2
2
f x dx
d y = , whereby running the
DE through two iterations of integration will yield the required solution.
Example: g dt
d s =− 2
2
Integrating twice wrt t gives: gt A dt
ds =− +
and At B
gt s = − + + 2
2
(shown)
3. Modelling a problem through the usage of a differential equation:
Typically the question demands the student to first formulate a DE relating
to the context of the situation, and subsequently solve it. Realise that the
formulation of a DE involves the following considerations:
(i) Constants of proportionality
(ii) Net rate, which is usually composed of an “in” rate and “out” rate,
eg birth rate - death rate
Example: The growth of a particular species of insect is studied in an experimental
environment. The rate of death is proportional to the number in
thousands, x , of insects, at any time t days after the start of the
experiment. The rate of birth is proportional to.
2 x When x= 2 ,
the number of larvae hatched is equal to the number of insects that
died. Show that = ax( x− 2 ) dt
dx where a is a constant.
dt
dx Birth rate minus death rate
= ax −bx
2
When x = 2 , = dt
dx 0