Diffraction - General Physics - Lecture Slides, Slides of Physics

In these Lecture Slides, the Lecturer has put emphasis on the following key points : Diffraction, Double-Slit Interference, Optical Path, Two Waves, Interference, Integer Number, Interference Occurs, Wavelengths, Bright Fringes, Three-Slit Interference

Typology: Slides

2012/2013

Uploaded on 07/24/2013

singy
singy 🇮🇳

4.4

(7)

71 documents

1 / 9

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
Chapter 32: Interference and Diffraction
th
Few words on mini-exam 6 (solutions Thursday)
Review of two-slit interference
Multiple-slit interference and diffraction gratings
Interference from a thin film
Review of single-slit diffraction (if time)
Reading: up to page 575 in the text book (Ch. 32)
Docsity.com
pf3
pf4
pf5
pf8
pf9

Partial preview of the text

Download Diffraction - General Physics - Lecture Slides and more Slides Physics in PDF only on Docsity!

Chapter 32: Interference and Diffraction

th

  • Few words on mini-exam 6 (solutions Thursday)
  • Review of two-slit interference
  • Multiple-slit interference and diffraction gratings
  • Interference from a thin film
  • Review of single-slit diffraction (if time) Reading: up to page 575 in the text book (Ch. 32)

Double-Slit Interference

Optical path difference between the two waves:

d sin!

When equal to a half integer number of wavelengths, destructive interference occurs, i.e., dark fringes. d sin! = ( m + 1 2 ) " ( m = 0 , 1 , 2 ,...)

Double-Slit Interference

  • Minima occur, i.e., dark fringes, for this condition.
  • Condition for primary maxima same as for two slits.

d sin! = ( m +

1 3

)! or ( m +

2 3

)! ( m = 0 , 1 , 2 ,...)

Three-Slit Interference Sum = 0 when waves are out of phase by 1/3 of cycle.

Thin Films

Thin Films Thin film No phase change 180 o phase change

  • Extra path length in the film = 2 nd
    • 180 o phase change if n 1 < n 2 .
    • No phase change if n 1 > n 2 .
  • Therefore, because of the π/ phase shift at the first interface, the condition for constructive interference at normal incidence is: 2 nd = ( m + 1 2