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Dimensional Analysis: Understanding Units, Types, and Dimensions, Slides of Physics

An introduction to dimensional analysis, explaining the concept of units, types of units, dimensions, and their relationship. It covers the conversion of units into fundamental dimensions, the use of dimensional analysis to determine correct units, and the limitations of this method.

Typology: Slides

2012/2013

Uploaded on 07/12/2013

madangopal
madangopal 🇮🇳

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Dimensional Analysis

Units and Types ^ Units are meters, seconds, feet, tons, etc. ^ Types of units are length, mass, force, volume, etc. ^ The type of unit of a value is called the dimension.•^ A value in square meters has dimensions of an area.•^ A value in kilometers per hour has dimensions of a velocity.

Powers of Units ^ It is useful to convert the dimensions of units intofundamental dimensions.•^ Length (

L )

-^ Time (

T )

-^ Mass (

M )

^ Units can be raised to a power, and so can thefundamental dimensions.•^ Area (

2 L )

-^ Volume (

3 L )

-^ Force (

M^ L^ /^ T
2 )

Missing Units ^ The energy in a compressedspring is given by

U^ = ½^ kx

U^ is the energy in kg m

22 /s, and

x^ is the length in m. What arethe correct units for

k?

^ Use dimensional analysis: ^ Substitute units fordimensions:•^ k

has units of kg/s

2 2 (^2222)

12 2 2 2 /

ML T

kxU MLkLT MLk T

  

Dimensional Expressions ^ The speed of waves in shallow water depends only on theacceleration of gravity

g , with dimensions

(^2) L / T , and on the

water depth

h. Which of the following formulas for the wave speed^ v

could be correct?^ ghv

a)^ b)

1 2 gh^2

v^ 

Base Quantities Acceleration

g ^ dimensions:

2 L / T

^ length/time

2 ^ example: m/s

Height 2

h ^ dimensions:

L

^ length ^ example cm

Speed^

v ^ dimensions:

L / T

^ length/time ^ example km/h

Checking a Result ^ Terms do not match

^ Terms match, this could be avalid formula.

1 2 gh^2

v^ 

L^2 L^2 T

L^  T

3 L^2 T

L^  T

ghvL^ L T L^ T ^2 L^ T L^  T

Limitations ^ Dimensional analysis only checks the units. ^ Numeric factors have no units and can’t be tested.

is also valid.is not valid.

ghv  3

next

4 

^ ghv