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A proof using propositional logic that if m^2 = n^2, then m and n are either equal or opposites. The proof is based on the given premises and uses various logical laws such as de morgan's law, double negation law, and commutative law.
Typology: Exercises
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Discrete Mathematics 1.7. (i)If m^2=n^2, then m^2-n^2=(m+n)(m-n)=0. When the product of two number is 0,at least one of them is 0,so m+n=0 or m-n=0,which means m=n or m=-n (ii)if m=n, then m^2=n^2. On the other hand, if m=-n, then m^2=(-1.6. Step/Reason