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A proof using the rules of propositional logic to establish the conditional statement: for all x, (p(x) ∨ q(x)) → (p(x) → r(x) ∨ q(x)). The proof is based on the given premises: ∀x(p(x)∨q(x)) and ∀x((¬p(x) ∧ q(x))→r(x)). The proof proceeds through a series of logical steps, including universal instantiation, logical equivalence, de morgan's law, double negation law, commutative law, associative law, resolution, and idempotent law.
Typology: Exercises
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Discrete Mathematics 1.6. Step/Reason