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Discussion exercises on series convergence for math 1b, including absolute and conditional convergence, alternating series test, and the riemann zeta function. It includes examples and problems to solve with classmates.
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GSI: Theo Johnson-Freyd http://math.berkeley.edu/~theojf/09Summer1B/
Find two or three classmates and a few feet of chalkboard. As a group, try your hand at the following exercises. Be sure to discuss how to solve the exercises — how you get the solution is much more important than whether you get the solution. If as a group you agree that you all understand a certain type of exercise, move on to later problems. You are not expected to solve all the exercises: some are very hard. Exercises marked with an § are from Single Variable Calculus: Early Transcendentals for UC Berkeley by James Stewart. Others are my own or are independently marked.
Let bn be a positive decreasing sequence: bn ≥ bn+1 ≥ 0 for every n. Then
(−1)nbn converges. Moreover, if we truncate the series after then N th term, and estimate
nbn by sN = ∑N 0 (−1)
nbn, then the error of the estimate is at most |bN +1|. A series
an converges absolutely if
|an| converges. It is a theorem that if
an is abso- lutely convergent, then it is convergent. But many series are convergent without being absolutely convergent. For example, the Alternating Harmonic series
n− (^1) /n converges by the alter-
nating series test, but
1
∣(−1)n−^1 /n
∣ (^) = ∑∞ 1 1 /n is the divergent Harmonic series. A series that
converges but does not absolutely converge is said to converge conditionally.
n=
(−1)n−^1 np
(a) converge absolutely? (b) converge conditionally? (c) diverge?
n=
rn
(a) converge absolutely? (b) converge conditionally? (c) diverge?
(a)
1
(−1)nn n + 2 (b)
2
(−1)n √ n
(c)
1
(−1)n−^1 ln(n + 4)
(d)
1
(−1)n^ n √ n^3 + 2
(e)
1
(−1)n 10 n^
(f)
1
cos πn n^2
(g)
1
(−1)n(−1)n^ cos π n
(h)
1
n 5
)n (i)
1
2 n
)n
(a)
n=
(−1)n 10 nn!
, |error| < 0. 000005 (b)
n=
(−1)n−^1 ne−n, |error| < 0. 0
(−1)n−^1 bn, where bn = 1/n if n is odd and bn = 1/n^2 if n is even, is divergent. Why does the alternating series test not apply?
n=1 an^ diverges, but^
n=1(an) (^2) converges. (b) Find a sequence {an} so that
n=1 an^ converges, but^
n=1(an) (^2) diverges.
n=
1 ns^. (a) For what s does the above definition of ζ(s) converge? I.e. what is the domain of the right-hand-side? (b) Prove that when both sides converge, we have:
∑^ ∞
n=
(−1)n−^1 ns^
2 s−^1
n=
ns
For what s does the left-hand-side converge? (c) Use the above equation to write a formula for ζ(s) that extends the domain to (0, 1) ∪ (1, ∞). (d) When s = 0, explain why the LHS of the above equation is the geometric series
0 r n with r = −1. Assuming that lim s→ 0
n− (^1) /ns (^) = lim s→ 0
0 r n, find ζ(0) = lim s→ 0 ζ(s).