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Examples and calculations related to elastic potential energy of springs. It covers the concept of spring constant, the relationship between force and deformation, and the work done to stretch or compress a spring. Students will learn how to calculate the potential energy, spring constant, and deflection of a spring using the elastic potential energy equation.
Typology: Lecture notes
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The elastic potential energy of a spring is one half the product of its spring constant multiplied by the square of its extension or compression. or
Energy may be stored in a system when work is done on the system.
free length
When you apply a force to a spring, it deforms.
The applied force does work on the spring. The change in the springās length is called the deformation, x.
The work done to stretch or compress the spring is stored in the spring as elastic potential energy.
The elastic potential energy of a spring is one half the product of its spring constant multiplied by the square of its deformation.
If the spring constant is 200 N/m and the spring is deflected by 1.0 cm, how much energy is stored?
200 Elastic potential energy
If the spring constant is 200 N/m and the spring is deflected by 1.0 cm, how much energy is stored?
200 Elastic potential energy only 0.01 J! 0.01 0. How strong a spring is needed to get 1.0 joule of energy from a 1.0 cm deflection?
Spring constant 1.0 0. How strong a spring is needed to get 1.0 joule of energy from a 1.0 cm deflection?
Spring constant 1.0 0. k = 20,000 N/m 20000 How strong a spring is needed to get 1.0 joule of energy from a 1.0 cm deflection?
Spring constant 1.0 20000 0. This is a pretty stiff spring! What might it be used for? k = 20,000 N/m
Inside the fork tube is a spring with a spring constant of roughly 20,000 N/m.
x 1 cm How much force is needed to compress this spring one centimeter? k = 20,000 N/m
x 1 cm How much force is needed to compress this spring one centimeter? k = 20,000 N/m
x 1 cm
The spring pushes back in the opposite direction with a force of -200 N. How much work must be done to stretch a spring with k = 1.0 N/m by 25 cm?
Elastic potential energy
How much work must be done to stretch a spring with k = 1.0 N/m by 25 cm?
Elastic potential energy
Only 0.03 J! This is a very weak springā looser than a SlinkyĀ®.
How about a k = 100 N/m spring? How much work must be done to stretch a spring with k = 100 N/m by 25 cm?
100 Elastic potential energy
How does the stored energy change if the displacement is doubled? The energy increases by a factor of four (2^2 ). What happens if the displacement is tripled?
100 Elastic potential energy 2
Where does this formula come from?
Hypothesis: The elastic potential energy is derived from the work done to deform the spring from its free length...
Work is force times distance. W = Fd W = Fd F = -kx
W = Fd
F = -kx where k is the spring constant in N/m...
F = -kx W = Fd
where k is the spring constant in N/m... and x is the change in length of the spring in meters.
BUT the force F from a spring is not constant. On a graph of force vs. distance it is a line of constant slope.
BUT the force F from a spring is not constant. It starts at zero and increases as the deformation x increases.
The area on this graph...
The area on this graph is force times distance... The area on this graph is force times distance which is the work done!
This expression is true for more than just springs!
Elastic potential energy is stored in all objects that can deform and spring back to their original shape.
such as a rubber band...