Elastic Potential energy notes plus questions, Exams of Physics

These notes clearly explain elastic potential energy in a simple, exam-focused way that makes spring and energy-storage problems much easier to understand and solve. Inside the full resource: • elastic potential energy explained step-by-step • Hooke’s Law made simple and easy to apply • extension vs force relationships clearly described • how to recognise when elastic energy is conserved Designed for quick revision before SACs or for students who want to properly understand spring systems instead of memorising formulas. Ideal for students aiming to improve confidence and accuracy in energy questions.

Typology: Exams

2025/2026

Available from 04/04/2026

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Elastic Potential Energy (Sec 3.4)
Elastic potential energy is the energy stored in a material when it is stretched or
compressed. If the material is elastic, this energy can be returned to the system, but
in inelastic materials, permanent change occurs once the force applied to the object is
removed.
Hooke’s Law
Hooke’s law states that the force applied to an object is directly proportional to the
spring’s extension.
Hooke's Law and Elastic Potential Energy
→Graph must pass through (0,0)
→Stiffer springs have a greater spring constant. (Larger gradient)
→Not obeyed after elastic limit (break in linearity)
F
=−
kx
EPE
=
Area
=1
2
Fx
=1
2
k x
2
i. Calculate spring constant of red and yellow springs.
ii. Calculate energy stored in red and yellow when extended
0.1 metres.
k = spring constant (Nm-1) = Gradient of
graph
x = change length (m) Extension or
Compression
F = force applied (N)
EPE = elastic potential energy (J), energy
stored in spring/object = Area under graph
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Elastic Potential Energy (Sec 3.4)

Elastic potential energy is the energy stored in a material when it is stretched or compressed. If the material is elastic, this energy can be returned to the system, but in inelastic materials, permanent change occurs once the force applied to the object is removed.

Hooke’s Law

Hooke’s law states that the force applied to an object is directly proportional to the spring’s extension.

Hooke's Law and Elastic Potential Energy

→Graph must pass through (0,0)

→Stiffer springs have a greater spring constant. (Larger gradient)

→Not obeyed after elastic limit (break in linearity)

F =− kx

EPE = Area =

Fx =

k x

2

i. Calculate spring constant of red and yellow springs.

ii. Calculate energy stored in red and yellow when extended

0.1 metres.

k = spring constant (Nm-1) = Gradient of graph x = change length (m) Extension or Compression F = force applied (N) EPE = elastic potential energy (J), energy stored in spring/object = Area under graph

Mass stationary attached to spring.

The tension(T) in the spring is given by:

T = mg =− kx

Total energy in a spring at any time for mass

oscillating when attached to spring.

The max velocity occurs at midpoint, when acceleration=0, this occurs when: T = mg = kx Total energy of system any time when mass is oscillating freely oscillating is given by:

E T = mgh +

k x

2

m v

2

Example 1

A spring-loaded toy fires a 20g pellet at 1.2m/s. If the spring constant of the spring is 50N/m, calculate how far the spring is compressed.

Example 2 (VCAA 2012 Quest 1)

Example 4 (VCAA 2018 Quest 6)

b. Calculate the acceleration of the ball when it reaches its maximum speed. Explain your answer. (2)

a. Calculate the total energy of the mass at its lowest point (Z). b. From the data in the graph, calculate the speed of the mass at its midpoint (Y).