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Engineering pltw engineering physics
Typology: Study Guides, Projects, Research
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Name_________________________
Engineers must look for better ways to build structures. Less material typically means that structures will be lighter and less expensive. Knowing the moment of inertia for different shapes is an important consideration for engineers as they strive to make designs lighter and less expensive.
Calculating Moment of Inertia: ๐ฐ =
(b = base [in], h = height [in])
Calculate the moment of inertia for Beam A
geometry
I
1.5in 5 5in
12
I 20.8in
Stiffness
Greater
Greater
One is horizontal and one is vertical
Calculate the moment of inertia for Beam B
Beam A is _____ times stiffer than Beam B!
Factors that affect deflection
โ๐ด๐จ๐ฟ =
๐ญ๐ณ๐
๐๐๐ฌ๐ฐ
I 5 5in^ 1.5in 12
I 1.54in
whats รtat^ inert
force applied^
length e
ฮ Max^
250
IBF 8.0ft
48 1,^
000
ฮ Max^
Material properties
Greater Greater
You will determine the weight of one of your classmates using nothing more than a standard 2x and a measuring device. This activity will provide you with a better understanding of Moment of Inertia and how it can be used to determine the strength of beams.
Preliminary lab calculations to determine beam Modulus of Elasticity
๏ฝ
3
xx
bh I 12
B โ width of the beam (in.)
h โ height of the beam (in.)
I โ Moment of Inertia (in.^4 )
Vertical Orientation Horizontal Orientation
IV = IH =
Position the beam as shown below.
Total Span (L) = __________in.
Pre-Loading Distance (D (^) PL ) = __________in.
(^1) 517in
1.517 in 3 482 3.482in 1.517in
4875
Applied Load Distance (D (^) AL ) = ___________in.
๏ (^) MAX = __________ in.
6. Determine the weight of volunteer (V 1 ) using the classroom floor scale.
Volunteer weight (F) ____________ lb
Rearrange the equation 3 MAX
FL ฮ = 48E I
to solve in terms of E
Substitute known values
Simplify and Solve
Note: An objectโs Modulus of Elasticity is a material-based property and stays the same regardless of orientation.
3 75
1 125
145
(^1 )
48 E^ 1.^ n
48
EE
Rearrange the equation 3 MAX
FL ฮ = 48E I
to solve in terms of F
Substitute known values
Simplify and Solve
Determining Beam Deflection
3 MAX
FL ฮ = 48E I
Substitute known values
Simplify and Solve
48
Max
85in 3
8
48EI Max
48
psi 5.34in^ 0.15in^ 125.51g
Practice Problem (to be completed INDIVIDUALLY)
Beam A B C D E F Common Name 2x6 2x6 2x8 2x8 2x10 2x Actual Dimensions (in.)
1.5 x 5.5 1.5 x 5.5 1.5 x 7.25 1.5 x 7.25 1.5 x 9.25 1.5 x 9.
Vertical or Horizontal Orientation
Cross- Sectional Area (in.^2 )
๐ด = 1. 5 ร 5. 5 = 8. 25 ๐๐^2
Moment of Inertia (in.^4 )
๐ผ =
โ= โฏ = 0. 50 ๐๐