Evaluating Trigonometric Functions: A Step-by-Step Guide with Example Problem, Study notes of Trigonometry

Material Type: Notes; Class: Trigonometry; Subject: Mathematics; University: Utah State University; Term: Unknown 1989;

Typology: Study notes

Pre 2010

Uploaded on 08/19/2009

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Evaluating Trigonometric Functions
If we have any angle, θ, in standard position with a point (x, y) on the terminal side of θ
and r=px2+y2>0, then use the following definitions to evaluate the six trigonometric
functions:
sin θ=y
rcos θ=x
r
tan θ=y
x, x 6= 0 cot θ=x
y, y 6= 0
sec θ=r
x, x 6= 0 csc θ=r
y, y 6= 0
The following figure shows us the quadrants and will also help us to evaluate the
functions:
Quadrant II Quadrant I
sin θ: + sin θ: +
cos θ:cos θ: +
tan θ:tan θ: +
Quadrant III Quadrant IV
sin θ:sin θ:
cos θ:cos θ: +
tan θ: + tan θ:
Problem 6.
Determine the value of the six trigonometric functions of the angle, θ.
sin θ=1
2; cot >0
Solution Step 1:
With values for yand r, we can find the value for x. Remember that ris
a distance and can never be negative. Thus:
pf2

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Evaluating Trigonometric Functions

If we have any angle, θ, in standard position with a point (x, y) on the terminal side of θ

and r =

√ x^2 + y^2 > 0, then use the following definitions to evaluate the six trigonometric functions:

sin θ=

y r

cos θ=

x r

tan θ=

y x

, x 6 = 0 cot θ=

x y

, y 6 = 0

sec θ=

r x

, x 6 = 0 csc θ=

r y

, y 6 = 0

The following figure shows us the quadrants and will also help us to evaluate the functions:

Quadrant II Quadrant I sin θ : + sin θ : + cos θ : − cos θ : + tan θ : − tan θ : +

Quadrant III Quadrant IV sin θ : − sin θ : − cos θ : − cos θ : + tan θ : + tan θ : −

Problem 6.

Determine the value of the six trigonometric functions of the angle, θ.

sin θ = −

; cot > 0

Solution Step 1:

With values for y and r, we can find the value for x. Remember that r is

a distance and can never be negative. Thus:

r =

x^2 + y^2

r^2 = x^2 + y^2

r^2 − y^2 = x^2

22 − (−1)^2 = x^2

4 − 1 = x^2

x = ±

Since sin θ < 0 and cot θ > 0 in quadrant III, we know that cos θ < 0.

Thus:

x = −