MATH 111 Exam I Hints and Answers Autumn 2008 - Prof. Jennifer Taggart, Exams of Mathematics

Hints and answers for the math 111 exam i held in autumn 2008. It covers various questions related to total revenue (tr), total cost (tc), marginal cost (mc), average cost (ac), and profit maximization.

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Pre 2010

Uploaded on 03/10/2009

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MATH 111 EXAM I Hints and Answers
Version Beta
Autumn 2008
1. (a) (4 points) HINT: Price per item is the same as average revenue. Average revenue at
q= 6 hundred Items is the slope of the diagonal line through the TR graph at 6.
ANSWER: approximately $66.67 per Item
(b) (4 points) HINT: You’re looking for the marginal revenue at q= 2 hundred Items. Draw
the secant line through the T R graph at q= 2.00 and q= 2.01 and compute its slope.
ANSWER: approximately $80
(c) (2 points) NOTE: There was a typo on this exam. The fixed costs should have been
100 hundred dollars.
ANSWER: The T C graph is a line parallel to the V C graph with y”-intercept 100.
(d) (4 points) ANSWER: Since T C is linear, every time you produce one more Item, your
total cost will increase by the same amount (that amount being the slope of the T C
graph: approximately 23.70). So, the graph of marginal cost will be a horizontal line
with height 23.70.
(e) (4 points) HINT: Profit (the vertical distance between TR and T C ) is largest at about
q= 6 hundred Items.
ANSWER: Maximum profit is approximately 160 hundred dollars or $16000.
2. (4 points each)
(a) HINT: The smallest value of MC is the y”-coordinate of the lowest point on the M C
graph.
ANSWER: $4 per Thing
(b) HINT: The breakeven price is the y”-coordinate of the point of intersection of MC and
AC.
ANSWER: approximately $8.55 per Thing
(c) HINT: Average cost at 14 Things is approximately $9.55 per Thing and AC(14) =
T C(14)
14 .
ANSWER: approximately $133.70
(d) HINT: Draw the graph of MR: a horizontal line with height 5.50. Profit is maximized
at the smallest whole number quantity at which MR becomes less than or equal
to MC.
ANSWER: 10 Things
3. (a) (6 points 3 points each)
i. ANSWER: B(7) B(0)
ii. ANSWER: A(t+h)A(t)
h
(b) (4 points) HINT: Draw a reference line with slope 2. Slide your reference line up until it
intersects the graph of Bat its y”-intercept and find another point at which it intersects
the Bgraph.
ANSWER: approximately t= 0.7 or t= 5.2
(c) (4 points) HINT: Find a time at which the vertical gap between the two graphs is 3 and
the Bgraph is above the Agraph.
ANSWER: approximately t= 8.25
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MATH 111 – EXAM I Hints and Answers Version Beta Autumn 2008

  1. (a) (4 points) HINT: Price per item is the same as average revenue. Average revenue at q = 6 hundred Items is the slope of the diagonal line through the T R graph at 6. ANSWER: approximately $66.67 per Item (b) (4 points) HINT: You’re looking for the marginal revenue at q = 2 hundred Items. Draw the secant line through the T R graph at q = 2.00 and q = 2.01 and compute its slope. ANSWER: approximately $ (c) (2 points) NOTE: There was a typo on this exam. The fixed costs should have been 100 hundred dollars. ANSWER: The T C graph is a line parallel to the V C graph with “y”-intercept 100. (d) (4 points) ANSWER: Since T C is linear, every time you produce one more Item, your total cost will increase by the same amount (that amount being the slope of the T C graph: approximately 23.70). So, the graph of marginal cost will be a horizontal line with height 23.70. (e) (4 points) HINT: Profit (the vertical distance between T R and T C) is largest at about q = 6 hundred Items. ANSWER: Maximum profit is approximately 160 hundred dollars or $16000.
  2. (4 points each)

(a) HINT: The smallest value of M C is the “y”-coordinate of the lowest point on the M C graph. ANSWER: $4 per Thing (b) HINT: The breakeven price is the “y”-coordinate of the point of intersection of M C and AC. ANSWER: approximately $8.55 per Thing (c) HINT: Average cost at 14 Things is approximately $9.55 per Thing and AC(14) = T C(14)

ANSWER: approximately $133. (d) HINT: Draw the graph of M R: a horizontal line with height 5.50. Profit is maximized at the smallest whole number quantity at which M R becomes less than or equal to M C. ANSWER: 10 Things

  1. (a) (6 points – 3 points each)

i. ANSWER: B(7) − B(0) ii. ANSWER:

A(t + h) − A(t) h (b) (4 points) HINT: Draw a reference line with slope 2. Slide your reference line up until it intersects the graph of B at its “y”-intercept and find another point at which it intersects the B graph. ANSWER: approximately t = 0.7 or t = 5. 2 (c) (4 points) HINT: Find a time at which the vertical gap between the two graphs is 3 and the B graph is above the A graph. ANSWER: approximately t = 8. 25

(d) (2 points) ANSWER: ii