Exam 1 with Answer Key for Electronics | ECE 2204, Exams of Basic Electronics

Material Type: Exam; Professor: Xu; Class: Electronics; Subject: Electrical & Computer Engineer; University: Virginia Polytechnic Institute And State University; Term: Fall 2008;

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Pre 2010

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Electronics I, ECE 2204, CRN 11883 Exam 1 Chapter 1&2 . Diodes
Use proper UNITS and ONLY 3 significant figures in all calculations.
NAME: _______________________________________
Signature: _____________________________________
By signing this exam, you agree that you have followed the Honor Code.
Part 1: Please circle the right answers to each question: (5% for each question)
1. For the semiconductor materials, which statements below are right?
(a) Extrinsic semiconductors can still conduct the current at T=0K, but intrinsic semiconductors
can not.
(b) For intrinsic semiconductors, the concentrations of electron and hole are always the same
(c) For N-type extrinsic semiconductors, there is only free electron as the carrier
(d) In most of the cases, majority carrier concentration can be assumed to be the same as the
impurity concentration being doped.
(e) The majority carrier of N-type semiconductor is hole, whereas the majority carrier of P-type
semiconductor materials is electron
2. For P-N junction, which statements below are right?
(a) The built-in potential barrier Vbi will be higher under higher temperature
(b) To turn-on the P-N junction, the external voltage should be higher than Vbi
(c) The width of the depletion region of the P-N junction will increase when it is reverse biased.
(d) When there is no biasing voltage across the P-N junction, there is no space-charge region
3. To converter electrical signal into optical signal (light), which diode should be used:
(a) Solar cell (b) Photodiode (c) Schottky diode (d) Light-Emitting Diode (LED)
4. Regarding the AC equivalent circuit of diode, its small-signal incremental resistance rd is:
(a) equal to forward diode resistance rf (b)
DQ
T
d
I
V
r
5. For a diode with 0.7V cut-in voltage and zero rf, and a Zener diode with 5.6V breakdown voltage
and zero rz, which circuits below can work properly?
10V
D
(a)
D
(b)
10V
D
(c)
10V
Z
(d)
10V
Z
(e)
10V
(f)
10V
pf3
pf4
pf5

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Electronics I, ECE 2204, CRN 11883 Exam 1 Chapter 1&2. Diodes Use proper UNITS and ONLY 3 significant figures in all calculations. NAME: _______________________________________ Signature: _____________________________________ By signing this exam, you agree that you have followed the Honor Code. Part 1: Please circle the right answers to each question: (5% for each question)

  1. For the semiconductor materials, which statements below are right? (a) Extrinsic semiconductors can still conduct the current at T=0K, but intrinsic semiconductors can not. (b) For intrinsic semiconductors, the concentrations of electron and hole are always the same (c) For N-type extrinsic semiconductors, there is only free electron as the carrier (d) In most of the cases, majority carrier concentration can be assumed to be the same as the impurity concentration being doped. (e) The majority carrier of N-type semiconductor is hole, whereas the majority carrier of P-type semiconductor materials is electron
  2. For P-N junction, which statements below are right? (a) The built-in potential barrier Vbi will be higher under higher temperature (b) To turn-on the P-N junction, the external voltage should be higher than Vbi (c) The width of the depletion region of the P-N junction will increase when it is reverse biased. (d) When there is no biasing voltage across the P-N junction, there is no space-charge region
  3. To converter electrical signal into optical signal (light), which diode should be used: (a) Solar cell (b) Photodiode (c) Schottky diode (d) Light-Emitting Diode (LED)

4. Regarding the AC equivalent circuit of diode, its small-signal incremental resistance rd is:

(a) equal to forward diode resistance rf (b)

DQ T

d I

V

r 

5. For a diode with 0.7V cut-in voltage and zero rf, and a Zener diode with 5.6V breakdown voltage

and zero rz, which circuits below can work properly?

10V D (a)

D

(b) 10V D (c) 10V Z (d) 10V Z (e) 10V Z (f) 10V

  1. Which circuits are full-wave rectifiers? D (a) ~ ~~^ ~~ (b) (c) (d)
  2. Between center-tap Full-wave rectifier and bridge Full-wave rectifier, which statements are rifht: (a) With the same AC source voltage Vs, center-tap rectifier will have high peak voltage at output. (b) The peak inverse voltage (PIV) of the diode in the center-tap rectifier will be about twice of the diode PIV in bridge rectifier (c) The peak inverse voltage (PIV) of the diode in the center-tap rectifier will be the same as the diode PIV in bridge rectifier
  3. For a half-wave rectifier below with fixed ac input voltage and output load resistor, when we increase the capacitance of C, (a) the peak voltage of Vo will be the same (b) output voltage ripple will be larger (c) output voltage ripple will be smaller (d) peak current of diode will be higher

9. For a Zener diode circuit below, assume Vz = 5V, rz = 1.0 ohm, Ri = 10k, which statements are

right: (a) VL= 5V when Vps= 10V (b) VL= 5V when Vps= 3V (c) VL= 0V when Vps= 3V (d) VL= 3V when Vps= 3V

100  20V 12V

  • rZ 100  20V 12V

rZ A R r

V V

I

i Z PS zO Z^0.^0792 100 1

Thus, PZ^  IZVZIZ (^ IZrZVZO )^0.^0792 (^0.^0792 ^1 ^12 )^0.^958 W Step 2: The critical condition for Iz = 0 is when Vz just reaches its breakdown voltage, 12V, and its current has yet to ramp up from zero, as shown in below: 100  20V (^) 0A 12V 100  20V (^) 0A 12V Therefore, the 12V is generated by the voltage divider between RI and RL. Thus, V R R

R

V

i L L L^12 ^20    RL  150 ohm As long as RL  150 ohm, there will be no enough voltage shared by RL to breakdown the zener diode. Under such condition, the power dissipation in zener diode is zero due to zero IZ.

2. In the diode circuit below, Vps = 10V. The low frequency ac voltage is Vac =

0.1sin(a) Calculate the Zener diode current and the power314t). The cut-in voltage of the diode is 0.7V and its forward diode resistance rf

= 1 . R1 = R2=200 . (a) Calculate the Zener diode current and the powera) Please use piecewise linear model to identify the Q-point of

the diode. (a) Calculate the Zener diode current and the powerb) draw the load line of the diode (a) Calculate the Zener diode current and the powerc) draw the DC and AC equivalent

circuits (a) Calculate the Zener diode current and the powere) what is the instantaneous voltage across the diode and current I 1?

Vac Answer: Step 1: Do the DC analysis to find the Q-point of the diode: ( 1 ) 2 R 1

V V

R

V

I D D PS D

Thus, ) (^2 )

1 R 1 R 2

V

R

V

I D ^ PS  D  (THIS IS THE LOAD LINE EQUATION)

Based on the piecewise linear model of diode in Figure 1.30 (a), forward-biased diode can be treated as the Vr in series with rf. Therefore, diode itself have the following I-V relationship: VDIDrfVrID  0. 7 ( 3 ) From (2) and (3), we can get: I^ D ^4.^3 /^101 ^0.^0425 ( A ) V (^) DID  0. 7  0. 7425 ( V ) (THIS IS THE Q-POINT OF DIODE UNDER 10V DC INPUT VOLTAGE) Step 2: Draw the load line : 0.7V 5V 0.05A Q-point VD ID Step 3: