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Material Type: Exam; Professor: Carroll; Class: STATISTICAL METHODS; Subject: STATISTICS; University: Texas A&M University; Term: Unknown 1989;
Typology: Exams
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A. A teacher compares the pre-test and post- test scores of students. B. A teacher compares the scores of students using a computer-based method of instruc- tion with the scores of other students using a traditional method. C. A teacher compares the scores of students in her class on a standardized test with the national average score. D. A teacher compares her class’ average score on a standardized test with the national av- erage score. E. A teacher calculates the average of scores of students on a pair of tests and compares the two averages.
A. the width of all of the confidence intervals covered in class B. the chance of making a Type II error C. the α-level D. the p-value E. All of the above are affected.
A. claiming that μ 1 < μ 2 B. failing to prove μ 1 > μ 2 when it’s really true C. claiming that μ 1 < μ 2 when it’s really greater D. claiming that μ 1 > μ 2 when it’s not true E. failing to prove μ 1 < μ 2 when it’s really true
A. We cannot decide without running a test of hypotheses. B. Since both sample proportions (0.4 for males and 0.25 for females) are not less than 0.05, we fail to reject H 0 and conclude we could not prove that the true proportions are different. C. Since the sample proportions (0.4 for males and 0.25 for females) are not equal, we re- ject H 0 and conclude that the true propor- tions are not equal. D. Since the confidence includes 0, we fail to reject H 0 and conclude that we could not prove the true proportions are different. E. Since the confidence does not include 0, we reject H 0 and conclude that the true pro- portions are different.
A. We must have at least 30 in each sample. B. Since the sample sizes are less than 30, the data must be normal. C. The standard deviations (variances) must be equal. D. All of the above are necessary. E. None of the above are necessary.
A. get the data from the 4 different companies and run an ANOVA test to compare the means B. poll golfers at a randomly selected golf course and record their brand and average drive (distance the ball is driven) C. take a random sample of each brand and have a golfer hit all of them, in random or- der D. take a random sample of gold course and record which brands are used E. take a random sample of each brand and have four golfers hit all of them, in random order
A. H 0 : μ = X vs. HA : μ 6 = X, where X is the true average distance an air filled football travels when kicked B. H 0 : μair = μhelium vs. HA : μair > μhelium C. H 0 : μair = μhelium vs. HA : μair 6 = μhelium D. H 0 : μair = μhelium vs. HA : μair < μhelium E. H 0 : πair = πhelium vs. HA : πair > πhelium, where π is the proportion of field goals kicked
A. if the kickers don’t know which type of foot- ball they kicked, air or helium B. if the kickers don’t know who the sportswriter is (or what paper he’s with) C. if the kickers don’t know where the uprights (goal) are D. if the kickers don’t know how far others kick E. if the kickers don’t know if they made the team or not
A. the means for the two populations are ac- tually equal. B. the standard deviations for the two popula- tions are actually equal. C. the sample means for the two populations are equal. D. the sample sizes are the same. E. Two of the above are correct.
Group Mean Test Score Std Dev. control 75.7 12. 1.5mg 84.1 18. 2.5mg 102.4 20.
The p-value for this test is 0.007. Which of the following is correct?
A. The standard deviation for the 2.5mg dose is not equal to the other two. B. The true variances for the three groups are not all equal. C. The true means for the three groups are not all equal. D. The 2.5mg dose works the best since it has the largest mean test score. E. The 2.5mg dose works 7% better than the other two.
A. We need a control to determine the size of the effect. B. Having a control enables us to control the effect of confounding variables. C. Having a control makes the differences more statistically significant. D. Having a control makes the assumption of independence and normality more reliable. E. Having a control enables us to control the effect of the drug.
A. 17.1% of the time we would see a sample mean age of Republicans at least this much smaller than that of Democrats even though the true mean ages are the same. B. 17.1% of the Republicans are younger than the average Democrat. C. 17.1% of the time we would see a sample mean age of Republicans at least this dif- ferent from that of Democrats even though the true mean ages are the same. D. The Republicans are 17.1% younger than the Democrats. E. 17.1% of the time we would find Republi- cans younger than Democrats even though they’re the same age on average.
A. More than 17.1% of the Republicans would be younger than the average Democrat. B. The test would no longer be valid since the sample means are so different. C. The p-value would be smaller. D. The results would be more significant. E. Two of the above are correct.
A. ANOVA F -test, assuming the data is nor- mal. B. Case 2: the 1-sample test of the mean, as- suming that the data is normal. C. Case 10: the paired test, pairing the brands by runner. D. Non-parametric case for paired data since we don’t know if the data is normal. E. Case 9: the 2-sample test, assuming that the data is normal.
A. We don’t know the true value, so we have to guess. B. We can’t assume that they’re equal (either the sd’s or the p’s), so we need a better estimate. C. We get better estimates. D. It makes the data more random (it comes from a ‘pool’ of choices). E. None of the above are correct.
A. 0. B. 0. C. 0. D. 0. E. 0.
1A,2C,3B,4D,5E,6C,7E,8B,9C,10D,11D 12A,13B,14C,15B,16A,17E,18D,19C,20A