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Material Type: Exam; Professor: Carroll; Class: STATISTICAL METHODS; Subject: STATISTICS; University: Texas A&M University; Term: Unknown 2004;
Typology: Exams
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STAT303: 102 and 103 Exam #2, Form A Summer 2000
A. 0. B. 0. C. 1. D. 1. E. 1.
A. 0. B. 0. C. 0. D. 1. E. 1.
A. 0. B. 0. C. 0, there is no probability at exact points D. 0. E. 0.
A. the area under the curve B. the likelihood of an event occurring C. a proportion D. all of the above E. exactly two of the above
| Vehicle Hometown| car suv truck | Total --------+------------------------+---------- lcity | 9 1 2 | 12 metro | 20 9 3 | 32 outsid | 2 0 3 | 5 scity | 12 2 2 | 16 town | 13 3 7 | 23 --------+------------------------+---------- Total| 56 15 17 | 88 Pearson chi2(8) = 13.1191 Pr = 0.
A. The p-value, Pr = 0.108, is greater than 5%, so we can say that the relationship is statistically significant. B. The p-value, Pr = 0.108, is greater than 5%, so we can NOT say that the relation- ship is statistically significant. C. If you live in a metroplex, then you’re most likely to drive a car, so the categories are NOT related. D. The probability of driving a car is about the same whether you know you live in a metroplex or not, so the categories are not related. E. Since the table contains only one 0, the cat- egories must be related.
A. 7/ B. 7/ C. 7/ D. 17/ E. 17/
A. 2/ B. 2/ C. 2/ D. 16/ E. 2/17*2/
A. Yes, there’s only one in either category. B. Yes, it’s the least likely choice in either cat- egory. C. No, 1/ 12 6 = 1/15. D. No, 12/ 88 ∗ 15 / 88 6 = 1/88. E. No, 12/ 88 6 = 15/88.
A. 0. B. -0. C. 0. D. -0. E. 0.