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1) Given: Required: + 32 ee w QA. $= bX years z z x= hgeame _2) Given: RKequiced_k ; out ling time + Let y= population density @ 3h 7 4= a hoe Solution: Solution’: XU) = 2 * fx0 x= Ce KY Weaete se xe cekt X (0) = cet isa lanes ae ce XW = ce” aye? fe a ecg Gale pe he 4 C2 PP 3x,t-2 eee ¥ po a. 1 giom + t= hyo “yeors 3x = we Ina = Inf?) 2 Kee ef aH = en Ing = i ing KC Ayto") Ye F = nes e™ aft) 42 ete) Ling =k E = java hours 4 1-3 hous a = peer (Max00') Inl3) = & arp”) 3) Given: Required, + @ 1oox y 3 go LS Lebt= population 14K @ 2X b= 2 howe Be ey a Soltinn: x= cet yoke 7 Wox , t2% ae “4 ina|t esa a Lo = ae I: | xe) = ¢ ae lo0% = Xo AS ww) Ls ae raya" aes Xl) = ee Woo Xf = en a in (3) » st in [et)= Wwe ae Tor art y, =o = ye 3 a oe | ee) | 2? aki te oo = gS* ee oe | - F 3X0 = Xe e thw) = Inia)” — Cray) (a TE) = Soe Ser Ee ge In wo) = = ints) te Y> k ; = 1,036, ong, 140 yeary Ing = Ine’ g{intod) +t os as 7 £8 1.056 x10" years iia. = 2h = Lina += %agqhoure y s.Ahourg =7 4:24pm is he Opproyimote time chould % becume ipo times what ab wot ot nuon. + 
