Foundation 3/4 notes, Study notes of Physics

Notes for studyiing includes mechanics and magnetism

Typology: Study notes

2022/2023

Uploaded on 11/09/2023

sami-talab
sami-talab 🇦🇪

1 document

1 / 47

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
pf3
pf4
pf5
pf8
pf9
pfa
pfd
pfe
pff
pf12
pf13
pf14
pf15
pf16
pf17
pf18
pf19
pf1a
pf1b
pf1c
pf1d
pf1e
pf1f
pf20
pf21
pf22
pf23
pf24
pf25
pf26
pf27
pf28
pf29
pf2a
pf2b
pf2c
pf2d
pf2e
pf2f

Partial preview of the text

Download Foundation 3/4 notes and more Study notes Physics in PDF only on Docsity!

Andy Tillotson

Physics

Homeworks notcredited, instead HW Quizzes are 25%ofthe^ grade

2 types of

Lecture 1:9.1.9.

①out^ into board

a (^) ↑ can^ be^ +^ or^ - "standard as Angular displacement: 10

=0.0, W =

1in (^) o

e

Angular velocity:

Wayz=o 8 = |dof

magnitudee

save length^ S =^0 rotates around

SrB-radian^ (vi^ zaxis. radius ↑i (^) straightline Motion a^ constant

  • Righthand (^) rule II: &dug. (^) angular acceleration:^ 9av.^ z^ = n a 1 Oha instantaneous (^) angular acceleration:az^ = wn write formulas for (^) constantangular to

Example 1:^ car fire^ ro.5m^ rotating according to^ theformula:

&(t) =^ - 21.5rad/s2)E + (rad/s) t (^) W^ radis^ &^ Counterchocleiare

3 - clockwise

a) distance^ travelled^ in^ Is.^ 2) plotw^ and^ a^ sao^ aco &(1) = +1.5 rad^ ....^ counterlocisaen

a speeding up,

S = 50 =^ 0.5x1.Srad =05m

1

2 t

b) angular^ acceleration?^ .... d^ t Wz = 10 -^1 5+^2 +^ (t^ =^1 -^37 +^3 d) look atthe graphs describe^ qualitatively Oz = w2 =- 3rad/R

& ⑩^0 om ad- Parallel

axis theorem;

Ip =^ Icm^ +MdR

  • Perpendicular Axis theorem(only for ID object)

Iz =^ Fx^ + Iy

Rotational RE:

k = 12Iw2 ki + vi + other = (f + Uf

& kt = Id &

Ralling without^ slipping ->^ co^

= I ifitslips then w =

Total R = Etrans + Prot

Vam =

ww(dida

acm = 5&

Im = Y,ML

LC:

(i +^ 0i^

= kf +

07 · Iend = 5M M(gz = kzM(mV + Iw ①v 0y,gz^ = 2)'sMw Myngz = kM/mv3 + 12xtMXxy gz =^ (V^ + 1 v(t

  • Extx 1)v =^ g ( =^ v(t^
  • t)(t
  • Er= gz zv = gz Ans: 592 -x

97 =^0 v = ggtc &- (^) Torque: ↓S

Righthand^ rule^

method

a(F = 0xF T= rFsinO (^) * ....- Esince

SasF

it F,aa

Method b) T = wF

Method c) V = rsince

E =^2 F wet tongue ↑ (^) sangular acceleration ↑ a - ET = 1qz EF =man

Imomentof

Inertia^ EFy^ =^ may

2iz = Idz

I= (zmR2 TOP^ viewi^ +] ↑-x (^) + mly (^) xT

R

·

rm

a)

aN I =

EMR2y >f a ........... : ↑ masing^ ·a ugroc (^) my

7 a(

b) [F=^ man^ itlar 5Tx^ =^1 only colling withoutslipping. ①mgsino-F = man

8 - AR =

(GMR')2z 2z =^ - E R ② N^ - mg(

au = - z mp ⑥ an^ =^2 ③into^ O (^) mgsina -f = If

C

f = Emgsina

b) an = EgsinQ

  1. (^) Fs =^ uN^ fn^ =^ MuN Emgsinc?^ Mn^ lngcoc) M = (^) Etano a) 9W^ =^48 =^ + 10

+^ f-Rotation.^ - (^) wdom! (^4) translational ⑨ 8/2/25 &F=^ man and (^) of us & (^) Fy = may (^10) (^2) F= I2z (^) ==0xF

↑A. about^ a^ M

Angular momentum:works (^) symmetry v >L

I = 18 Ionlycenter^ of->^ B

L =^ TxF^ =^ umu ** (^) A =9T^ =^ T^ xF^ =^ gif=0,^

thenangular more^ seen

Li = (f

IiWi = IfWf wp = (E)uf (No external^ torques involved)

case

be insures in^ the^ case^ ofshier^ folding this^ arms^ work^ done^ in^ bringing an^ i

· th

N= we getc,^ d> show poque

1012/23 (^) ↓ Li = 1f (^) Fore ↓ mrR +Iw = CE r e (^) r

childs^ ↓

momentum

wf =m-k^ +^ Iwo

I + nR

15/2/23 (^) Gravitational force ↑ FAB

  • (^) force (^) thatAexerts on B

Fg

2mimu

=ma

o^ A-^ - -0^13 F FBA

  • FAB g

2m- (^) ↓Fa & F^ =^ ma a =^ 0z^ = Er e aemy = (E) v = &. g- eccentricity(theradius^ ofthe (^) ellips), for (^) a circle a^ =^0 d) p +w > 298

  • W
  • Gravitational (^) potential energy:does^
  • work.

* at^80 aPt^ =0.

& u =^ - ,mc 5 Total (^) mechanical (^) energy: *- jahms - empe^ energy tometest

Liz =^ LA a)Ei =^ ef^ GAM^

leaves - an =^0 CoE^ -> Va = uM 22/2/23 - SHM:

  • (^) kx = Map

an = x

m ** ==^ =^ e w^ =

some x(t) = Asin(wt+ 0) + (^) O, shifts graph left u(t) = Acus(ut + 0) - o,shifs (^) graph Right.

u(t) =^ A^ sin(Wt) + BCS (wt)

d

T = f 1 P w = 2

K

m

98 = E = I

E

Total E

M

Pf -> -> KE A A ⑧ kd = mg

p =

= 4 & (^) - physical pendulum:^ o^ = w simple (^) pendulum:w (^) = = :Im+ ma =E

I

Ex

in

i

No slipping,

n =^0 I

Es Ww^

a

& ⑧^ e

0 D

  • W=< -> opposite^ ofwe^ only in^ this^ care 2220 3 in (^) Epp. SFu=man &^ Fdz

fR

= (tMR2) x

  • Rx + f = man A==nRx(y)
  • f =^ - In an
  • lx - 42Man=man =an=^ - 2 we =

A q -

E

S

electractforce elect

* E^ =

E, F = 9.t fore 3 only for^ a^ source^ pointcharge. d you cantuse^ this^ for^ other^ means. charge

  • The^ direction (^) ofIdepends (^) only on the (^) source (^) charge

a vector field thatexist

everywhere in (^) space.

I

t ⑦->-

F

(^1) I -E electron travelling ... through space

V

I

---------------- > E, b ine =^ = 0 3

  • Electric (^) field line diagrams:

L

& #^ of^ lines^ entering or^ lecuim a (^) charge is (^) proportional to

  • 2 denver thelines, the stronger the (^) charges magnitude. 7 the

field

> &^

lines dontcross.

E e +^3 3 -^ -^ I^ XE^

  • (^) - - ti 1 - linear charge denim Q=f X = Mude -Y I

dg =Rde^ x=

dg] always^ the 11111111111 & se I (^5)

  • L^ ⑧
    • (^) de= (rad

-> integration variable

Jos are re

~first 30 mins:

MCA/ conceptual (^) things like^ (30^ prelecture. ~next^30 mins: easier (^) mastering phy type^ questions.

  • 45 mins^ COV2G like the writtenfew

1) make sheet

2) Review prefectures &^ 22.

3). Practice problem

Solving -go (^) through

the HW's.

  • Recitation (^) problems.

-Gauss's law:

Eext retardati

Better representation; -

  • ↑ -

= -^ +

metal - I

    • --

&-flectic fluxis (^) a scale (^) quantity. Ic = 8 E.^ da

  • Electric (^) field is a vector. d I^ >^ Electric (^) field (^) magnitude atpi

2 I^ >